# Practice MCQs For Speed, Velocity & Acceleration

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This quiz contains practice questions for Speed, Velocity & Acceleration (O Level). There are explanations for some of the questions after you submit the quiz. If you could not figure out why a particular option is the answer, feel free to drop a comment below or ask a question in ‘O’ & ‘A’ Level Discussion section of the forum. If you wish to contribute questions to this quiz, please contact us.

The quiz comprises of 10 questions, which are randomly selected from a large pool of questions. After completion, you can refresh the page and try the quiz again for a new set of 10 questions.

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1. An object is falling under gravity with terminal velocity.

What is happening to its speed?

2. A car travels 9 km southwards, followed by another 5 km southwards. What is the magnitude of its distance and displacement?

3. A boy jogs around his neighbourhood for 1.5 hours as shown in the following diagram:

(a) What is his displacement?

(b) What is the total distance he jogged?

(c) What is his average speed?

4. A car travels 9 km southwards, followed by 5 km northwards. What is the magnitude of its distance and displacement?

5. A ball is thrown vertically upwards at an initial speed of $23 \, \text{m s}^{-1}$. What is the displacement of the ball 3 seconds after it was thrown?

6. A car travels at a constant speed of $5 \, \text{m s}^{-1}$ for 2 seconds, then accelerates at a rate of $4 \, \text{m s}^{-2}$ for 3 seconds. What is the total distance traveled by the car?

7. A ticker tape timer produces 50 dots on a tape in 1 second. Below is a portion of the tape:

How long was the time taken to produce the above strip?

8. The graph below shows the movement of a car over a period of 50 seconds.

What was the distance travelled by the car during the time when it was moving at a steady speed?

9. A ball is thrown downwards at a velocity of 8 m/s and bounces upwards. Which of the following is its velocity-time graph?

[Assume no air resistance or energy lost and take downwards motion as positive direction]

4) None of the above

10. A car driver plans to take a total of two hours to make a journey of 75 km. The driver allocated a rest time of 45 mins in the middle of the journey.

At what average speed must the driver travel during the rest of the time if she wants to complete the journey in the two hours?

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### 47 thoughts on “Practice MCQs For Speed, Velocity & Acceleration”

1. 7. A ball is thrown vertically upwards at an initial speed of 23 \, \text{m s}^{-1} . What is the distance traveled by the ball 3 seconds after it was thrown?
29 mcorrect
55 m
24 mwrong
50 m
Can someone please explain why the answer is 29 and not 24?

• Note that the acceleration due to gravity is $10 \, \text{m s}^{2}$. The ball would have reached zero velocity in less than 3 seconds.

You will need to break the problem into parts and not solve it with the application of one single kinematics equation.

2. answer this please with calculation:A car travels at a constant speed of 5 \, \text{m s}^{-1} for 2 seconds, then accelerates at a rate of 4 \, \text{m s}^{-2} for 3 seconds. What is the total distance traveled by the car?

3. “A ball is thrown vertically upwards off a cliff at a speed of 23ms^-1. It falls to the bottom of the cliff after 10 seconds. What is the height of the cliff? ( g = 10ms^-2 )”

If I were to use s = ut + 1/2(at^2) , I would get the answer: -270m , which is not correct according to the answer. (this can be negative as it is a displacement value)

s: height (?), u: initial velocity (23), t: time (10), a: acceleration (-10 due to gravity)

If I were to use s = 1/2(u + v)t , I would get the answer 115m, which is not correct according to the answer.

s: height (?), u: initial velocity (23), v: final velocity (0)(because the ball has fallen to the bottom and is presumably on the floor), t: time (10)

If I were to use v^2 = u^2 + 2as, and rearrange to get s = (v^2 – u^2)/2a , I would get the answer: -26.45m , which is not correct according to the answer. (this can be negative as it is a displacement value)

s: height (?), u: initial velocity (23), v: final velocity (0)(because the ball has fallen to the bottom and is presumably on the floor), a: acceleration (-10 due to gravity)

(I am using the velocity as 23 throughout this even though it says that 23 is the ‘speed’, i’m not sure if that is where I am going wrong because then I would have to find the velocity by using v = s/t , but I don’t know s, and I am sure that here; ‘speed’ is interchangeable with ‘velocity’)

I don’t know where I am going wrong here, whether or not I am messing up somewhere with the wrong equation, or the final velocity. I am just so stuck on this for some reason, I would appreciate any help ASAP.

8. A ball is thrown vertically upwards. It lands on the top of a cliff after attaining a maximum height of 100 m in 7 s. What is the height of the cliff if the ball reaches the top of the cliff after 9 s? What is the height of the cliff? $\left( g = 10 \, \text{m s}^{ – 2} \right)$

ball thrown onto cliff
70 m
90 m
60 m
80 m

Thank you.

• Use the three kinematics equations (located here).

Step 1: Break the problem into three parts:
– Ball at t = 0
– Ball at t = 7s
– Ball at t = 9s

Step 2: Focus on the t = 7 s and t = 9s.

Step 3: Use the kinematics equation to find the distance travelled by the ball from t = 7s to t = 9s.
(Hint: The initial velocity will be zero, time will be 2 seconds, acceleration will be the gravitational acceleration and s will be the distance travelled)

• The hight of cliff after 9s will be 80m.

5. Pls help me. An object accelerates from 3m/s to 10 m/s in 3s. Find distance travelled.

• Please refer to this post: Acceleration (O Level). In particular, pay close attention to the kinematics equations.

If you require more help, you can post on the forum

• the answer to this question is 2.33 m if I am not wrong?

• Nope, that is not correct.

There are two methods to solving this question:
1) Use one of the kinematics equations; or
2) Plot out the velocity-time graph of the object. (Refer to Reading Kinematics Graphs

• Yeah. I’ve shown all the correct calculations on “Khamir Kheir’s” reply section. Please check and correct if any mistakes. Thank you!

• Given
Intial velocity = 3m/s
Final velocity = 10m/s
Time = 3s

a = v – u/t
= 10 -3/3
= 7/3 = 2.33

• correct

• This is wrong. The question asked to find the distance but you found acceleration instead.
We can use the basic one of the four equations of motion.

Given,
initial velocity = 3m/s
final velocity = 10m/s
time = 3s
distance = ?

s = (u+v/2) t
(where, s = distance, u = initial velocity, v = final velocity, t = time)

So,

s = (3+10/2) x 3
s = 6.5 x 3
s = 19.5m

$$s = \frac{1}{2}(u+v)t$$