Wavefunction and Schrödinger Equation
Key idea: H3 Quantum Mechanics: what the wavefunction ψ means, why |ψ|² is a probability density, and how the Schrödinger equation constrains allowed energies.
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The core idea
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Learning objectives
- Use state functions, boundary conditions, stationary states, and measurement to analyse introductory quantum systems.
Quantum mechanics describes a particle using a wavefunction (rather than a single trajectory). The Schrödinger equation is the wave equation that tells you what wavefunctions are allowed in a given potential energy V(x).
1. Meaning of the wavefunction
- The wavefunction Ψ(x,t) is a (generally complex) function that encodes the state of the particle.
- The wavefunction itself is not measured directly. Predictions come from its modulus squared.
- In one dimension, dP = |Ψ(x,t)|² dx; in three dimensions, dP = |Ψ(r,t)|² dV.
- Normalisation: total probability is 1: ∫_(-∞)^∞ |Ψ(x,t)|² dx = 1
The diagram below separates the sign-changing wavefunction from the measurable density and shows interval probability as an area under |ψ|².
2. Matter-wave link
Particles show wave behaviour. For a non-relativistic particle with momentum p:
λ = h/p
It is often useful to write momentum in “wave” form:
p = ħ k ⇒ k = 2π/λ
This connection is why quantised wavelengths in a bound system lead to quantised momenta/energies.
3. Schrödinger equations
Time-dependent equation in one dimension
iħ (∂ Ψ)/(∂ t) = -(ħ²/2m)(∂² Ψ)/(∂ x²) + V(x)Ψ
It tells you how the state evolves in time for a given potential energy V(x).
Time-independent equation for stationary states
If V(x) does not depend on time, many exam problems focus on stationary states with:
Ψ(x,t) = ψ(x)e^(-iEt/ħ)
Substituting this into the time-dependent equation gives the time-independent form:
-(ħ²/2m)d²ψ/dx² + V(x)ψ = Eψ
This is an eigenvalue equation: for bound systems, only certain values of E produce acceptable (normalisable) solutions.
4. Physical constraints and boundary conditions
In typical 1D H3 problems, acceptable wavefunctions must satisfy:
- ψ is finite and single-valued.
- ψ is continuous.
- dψ/dx is continuous wherever V(x) is finite.
- ψ is normalisable: ∫ |ψ|² dx is finite.
- At an infinite wall, the wavefunction must vanish at the boundary (e.g., ψ = 0 at the wall).
5. Problem workflow
- Sketch V(x) and split space into regions where V is simple/constant.
- Solve the differential equation in each region:
- If E > V: solutions are oscillatory (sin/cos).
- If E < V: solutions are exponential (decaying/growing).
- Apply boundary conditions (continuity + wall conditions) to determine constants and quantise allowed E.
- Normalise (if asked).
- Interpret results using |ψ|² and sanity-check units.
6. Quick check
A. If you scale the wavefunction by a constant A, what happens to the probability density?
Answer
If ψ → Aψ, then |ψ|² → |A|²|ψ|². You must renormalise to keep total probability equal to 1.
B. In a region of constant potential, what kind of wavefunction do you expect for E > V vs E < V?
Answer
- E > V: oscillatory (sinusoidal) solutions.
- E < V: exponential solutions (decaying/growing), which is the mathematical basis for tunnelling in finite barriers.
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Course and syllabus information
- Course
- Advanced Physics
- Edition
- Advanced Physics