5G FR1 and FR2: exposure differences

Select RF exposure metrics from frequency and geometry, distinguish 5G range labels from exposure criteria, and interpret changing beams and measurement averages.

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  • RF Radiation Safety
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A 5G label does not tell you the quantity to compare or the measurement to make. Start from the actual frequency, antenna aperture, accessible location and operating state. Then decide which exposure metric and averaging procedure the adopted framework requires.

Before you start

Use field regions, power-density quantities and time averaging. This lesson applies those ideas to beamformed systems; it does not supply a new set of exposure limits.

Separate the radio designation from the exposure criterion

For terrestrial NR, ETSI TS 138 101-2 V17.20.0, Release 17, Table 5.1-1 defines FR1 as 410 MHz–7.125 GHz. FR2-1 spans 24.25–52.6 GHz and FR2-2 spans 52.6–71 GHz. Keep the specification version with those labels; a range is not a statement that every frequency within it is deployed.

The 6 GHz transition used by some exposure criteria lies inside FR1. Consequently, “FR1 means SAR; FR2 means power density” is an unreliable decision rule. Use frequency, exposure geometry and the exact criterion. Distinguish local dosimetry from whole-body assessment and basic restrictions from external reference levels.

Connect wavelength, aperture and absorption

With wave speed c, wavelength is λ = c/f. FR2 wavelengths are approximately 4–12 mm, allowing many elements in a compact array. Aperture size and phase control determine the beam pattern; a higher frequency alone does not determine the field at a person.

For an isolated aperture of largest active dimension D, r_FF ≈ 2D²/λ is a far-field screening estimate. Within it, distance alone cannot justify S = Eᵣₘₛ²/377. Beyond it, reflections and additional sources can still invalidate a single travelling-wave model. Use the actual active aperture rather than a device’s case dimensions.

At higher frequencies absorption tends to concentrate near the tissue surface. ICNIRP’s 2020 framework distinguishes local SAR and absorbed power density by frequency, with specified spatial and temporal averaging. Incident power density is an external quantity; it is not automatically absorbed power density. The above-6 GHz lesson develops that distinction.

Estimate an array’s field region

Worked example 1

Estimate the far-field boundary of a mmWave array

Problem

You want to know whether a point measurement can reasonably be treated as plane-wave-like.

Use f = 28 GHz and largest active aperture dimension D = 0.20 m for an isolated array in air.

Estimate the far-field boundary and assess whether measurements at 1–3 m can reasonably be treated as plane-wave-like.

Show full solution
  1. Find the wavelength and aperture

    Method

    Convert the operating frequency to wavelength and identify the array aperture.

    Reason

    The Fraunhofer estimate depends on aperture size relative to wavelength.

    Working

    Answer

    Assume:

    • f = 28 GHz → λ ≈ (3 × 10⁸)/(28 × 10⁹) ≈ 0.0107 m
    • array aperture D = 0.20 m
  2. Estimate the far-field boundary

    Method

    Insert the aperture and wavelength into the Fraunhofer expression.

    Reason

    The boundary estimate screens whether the observation distance is sufficiently far from the array.

    Working

    Answer

    Fraunhofer estimate:

    r_FF ≈ 2D²/λ = 2(0.20)²/0.0107 ≈ 7.5 m
  3. Interpret the measurement region

    Working

    Answer

    The estimated boundary is 7.5 m. Points at 1–3 m are inside it, so distance alone does not justify a plane-wave conversion. Use a method valid for the radiating near field. Beyond 7.5 m, this aperture estimate still does not rule out reflections or other sources that change the local E/H relationship.

Average one position without claiming every position

Beam steering and traffic scheduling can move a maximum. A time average at one point and an area average across several points answer different questions. Average the required power-like quantity over the specified time window; keep the location fixed while making that time record. A max-hold display stores a maximum rather than reconstructing its duration.

Guided practice 2

Interpret a changing beam at one location

About 8 min

Problem

At one fixed accessible location, a validated measurement reports incident power density of 2.00 W/m² for 120 s, 12.0 W/m² for 30.0 s and 1.00 W/m² for the remaining 210 s. These are complete, non-overlapping parts of an illustrative 360 s study window, with the same measurement geometry.

Find the time-integrated incident energy density in J/m² and the time-averaged incident power density in W/m². Explain what the 12.0 W/m² maximum establishes, and what information is still missing for an area-averaged criterion or a maximum over operating states.

Make the decisions, then compare your working

Unit: J/m²
Unit: W/m²

Hints

Hint 1

Keep the location and time window fixed

Calculate ∑ SᵢΔ tᵢ. The quiet interval contributes energy too.

Hint 2

Separate a maximum from an average

Divide the total by 360 s. Neither the largest value nor an unweighted mean accounts for the unequal durations.

Show solution step by step
  1. Accumulate incident energy

    Method

    Weight each power density by its duration.

    Reason

    Energy density has units (W/m²) s = J/m².

    Working

    Answer

    Contributions are 2.00(120) = 240, 12.0(30.0) = 360 and 1.00(210) = 210 J/m². Their sum is 810 J/m².

  2. Recover the time average

    Method

    Divide by the total observation duration.

    Reason

    All three states belong to the same point and complete window.

    Working

    Answer

    S bar = 810/360 = 2.25 W/m². This lies between 1.00 and 12.0 W/m². The unweighted mean would treat three unequal durations as equal.

  3. State the scope of the result

    Method

    Keep the measured statistic distinct from the required comparison.

    Reason

    A time record at one point neither maps an area nor bounds unobserved traffic and beam states.

    Working

    Answer

    The observed maximum is 12.0 W/m², not the time average. The record alone does not establish an area average, a worst-case sliding window, brief-exposure criteria or a configured maximum. Compare those distinctions yourself; the checker verifies energy density and the study-window average only.

Reconsider the method when the band and geometry change

Check your understanding 1 A new band and a close measurement

A terrestrial FR1 device operates at 6.50 GHz with active aperture D = 0.100 m. A proposed close-to-body test is at 0.150 m. The assessor plans to infer SAR from a single electric-field reading because “it is FR1.”

Using c = 3.00 × 10⁸ m/s, assess the field-region argument and the metric choice. Identify the information required before choosing the comparison method.

Show answer

Here λ = 0.0462 m and 2D²/λ = 0.433 m. The proposed point is inside that screening boundary, so this estimate does not justify a plane-wave conversion. Nor does a field-in-air reading directly measure SAR.

The operating frequency exceeds 6 GHz despite its FR1 designation. Select the actual local or whole-body criterion from the adopted framework, including its incident/absorbed quantity, averaging and close-to-body method. The aperture estimate is a method screen, not a complete near-field dosimetry model. Compare your response for both failed assumptions and the missing comparison conditions.

Review the measurement decisions

Check your understanding 2

Why does a close-to-body assessment at a lower FR1 frequency commonly use SAR, while an FR2 assessment uses a surface metric?

Show answer

Lower-frequency energy can be deposited through a larger tissue volume, so SAR describes absorbed power per unit mass. FR2 absorption is more superficial, so a surface metric describes the local deposition. Select the exact metric from the adopted framework and frequency: FR1 itself extends above 6 GHz.

Check your understanding 3

Why can a “spot peak” be misleading for beamformed systems?

Show answer

Because beams move and scheduling changes the maximum over time and space. Many criteria are defined with time and/or spatial averaging, so a spot peak is not automatically the comparison quantity.

Check your understanding 4

An above-6 GHz criterion specifies an area average. Why can a single point reading not establish that average?

Show answer

The field can vary across the required area. A point reading samples one position; the criterion requires the metric averaged over the specified area, with any separate small-area focusing check applied too.

Keep frequency, geometry and averaging together

Record the active band, aperture, operating states, accessible region, measured quantity, detector response, averaging and uncertainty. A broadband total cannot identify 5G’s contribution without a justified attribution method; a quiet beam state cannot bound all beam states. Change the method when one of those conditions changes.

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Syllabus and review details

No official syllabus alignment is listed for this lesson.

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