Estimation, errors and uncertainty
Key idea: Good measurement is about the quality of the evidence, not the number of decimal places. Separate scatter from bias, then carry the uncertainty through the calculation.
Continue where you stopped
The core idea
H1 Physics 8867 · Lesson 2 of 3
Check your understandingBy the end of this lesson, you should be able to
- Make defensible order-of-magnitude estimates.
- Distinguish precision, accuracy, random error and systematic error.
- Find uncertainty in a derived quantity using absolute, fractional or percentage uncertainties.
Learn the idea
Big question: How do you turn imperfect readings into a result whose reliability is honestly stated?
Estimate before measuring or calculating
An estimate is a physical argument in miniature. Choose a familiar comparison, state one or two assumptions and keep only a sensible order of magnitude. Estimating the mass of classroom air, for example, needs a room volume and an approximate air density—not centimetre-level room dimensions.
A prior estimate also catches calculator slips. If a human walking speed appears as 300 m s⁻¹, the arithmetic or unit conversion deserves another look.
Check your understanding: Would 10⁻³ kg, 1 kg or 10³ kg be the most sensible order of magnitude for a textbook?
1 kg. A milligram-scale book is far too light and a tonne-scale book far too heavy.
Match the uncertainty rule to the operation
Random error produces unpredictable scatter and mainly limits precision; repeated readings help reveal and reduce its effect on a mean. Systematic error shifts readings consistently and mainly limits accuracy. A zero error is one systematic example and must be corrected rather than averaged away.
Absolute uncertainty belongs naturally with addition and subtraction because the quantities share a unit. Fractional or percentage uncertainty belongs with multiplication, division and powers because the result scales with each factor. These rules give a sensible worst-case estimate; they are not a full statistical analysis.
Check your understanding: Why do repeated readings not remove a zero error?
Every reading is shifted in the same direction, so averaging preserves the bias instead of cancelling it.
Key ideas
- An estimate should include a sensible power of ten and unit.
- Precision concerns spread; accuracy concerns closeness to the accepted value.
- An uncertainty should describe the measurement method, not invented extra precision.
Relationships to know
Δ(A ± B) = ΔA + ΔBΔ(AB)/(AB) ≈ ΔA/A + ΔB/Bfor y = xⁿ, Δy/y ≈ |n|Δx/x
Follow the reasoning
Worked example
Correct a zero error and report uncertainty
Question: A micrometer gives 2.31, 2.35, 2.33 and 2.37 mm for a wire diameter and has a +0.02 mm zero error. Report the corrected diameter with a justified uncertainty.
Step 1: Find the central reading
Why: The mean reduces the effect of random scatter in repeated readings.
Working: Mean indication = (2.31 + 2.35 + 2.33 + 2.37)/4 = 2.34 mm.
Step 2: Correct the systematic offset
Why: A positive zero error makes every indication too large.
Working: Corrected mean = 2.34 − 0.02 = 2.32 mm.
Step 3: Use the spread to estimate uncertainty
Why: Half the range represents the observed random spread for this small repeated set.
Working: Uncertainty = (2.37 − 2.31)/2 = 0.03 mm.
Answer: Diameter = (2.32 ± 0.03) mm.
Check: The value and absolute uncertainty use the same decimal place, and the correction moves the result downward as a positive zero error should.
Now try it with support
Practise with support
A rectangle has length (8.0 ± 0.1) cm and width (5.0 ± 0.1) cm. Find its area and absolute uncertainty.
Hints
- Area is a product, so add percentage uncertainties.
- Convert the final percentage uncertainty back to cm².
View the guided answer
A = 40.0 cm². Fractional uncertainty = 0.1/8.0 + 0.1/5.0 = 0.0325, so ΔA = 1.3 cm². Report A = (40.0 ± 1.3) cm².
Your turn
Practise independently
Four diameter readings are 2.31, 2.35, 2.33 and 2.37 mm, while the micrometer has a +0.02 mm zero error. Calculate and report the corrected result with a justified uncertainty.
Check your answer
The mean indication is 2.34 mm. A +0.02 mm zero error is subtracted, giving 2.32 mm. The half-range is (2.37 − 2.31)/2 = 0.03 mm, so report (2.32 ± 0.03) mm.
Common mistakes and exam guidance
Watch out for
- Calling a tightly grouped but biased set accurate.
- Adding percentage uncertainties when the measured quantities are being added rather than multiplied.
In an exam
- Name whether an error affects precision or accuracy and explain why.
- Keep full calculator values while working, then match the result’s decimal place to the absolute uncertainty.
Put the ideas together
Exam-style practice [6 marks]
A block has mass (125.0 ± 0.1) g and dimensions (5.00 ± 0.02) cm by (2.00 ± 0.02) cm by (1.00 ± 0.02) cm. Calculate its density and estimate the absolute uncertainty.
Plan before you answer
- Calculate volume and density using the central values.
- Add percentage uncertainties for the product and quotient.
- Convert the percentage uncertainty into an absolute uncertainty.
View the marking points and model answer
Marking points
- Obtains volume 10.0 cm³.
- Obtains density 12.5 g cm⁻³.
- Finds percentage contributions 0.08%, 0.40%, 1.0% and 2.0%.
- Adds them to about 3.5%.
- Finds absolute uncertainty about 0.44 g cm⁻³.
- Reports (12.5 ± 0.4) g cm⁻³ with sensible precision.
Model answer
Volume = 5.00(2.00)(1.00) = 10.0 cm³, so ρ = 125.0/10.0 = 12.5 g cm⁻³. The percentage uncertainty is 0.1/125.0 × 100% + 0.02/5.00 × 100% + 0.02/2.00 × 100% + 0.02/1.00 × 100% = 3.48%. Thus Δρ = 0.0348(12.5) = 0.44 g cm⁻³, giving ρ = (12.5 ± 0.4) g cm⁻³.
Finish from memory
Three-question recap
Which type of error mainly limits precision?
Check
Random error, because it produces scatter between repeated readings.
What happens to percentage uncertainties when quantities are multiplied?
Check
Their percentage or fractional uncertainties are added.
Why should an estimate avoid many significant figures?
Check
Its assumptions and approximate inputs do not justify false numerical precision.
Continue with the next resource in this course.
Course and syllabus information
- Course
- GCE A-Level H1 Physics
- Edition
- GCE A-Level H1 Physics 2027