R.m.s. values and equal heating

Key idea: R.m.s. current gives the same mean heating power as steady D.C. in the same resistor. For a sinusoid, the r.m.s. value is the peak divided by √2.

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  • GCE A-Level H2 Physics 2027
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Averaged over a complete cycle, a sinusoidal current is zero: it flows one way for half the time and the other way for the other half. Yet it heats a kettle element perfectly well, because the heating does not depend on the direction of the current. To say how large an alternating current is, we need a value that measures its heating effect.

Root-mean-square value

In a resistor of constant resistance R, the power at any instant is I²R. This is positive whichever way the current flows. The root-mean-square (r.m.s.) current Iᵣₘₛ is the steady direct current that would produce the same mean power in the same resistor:

Iᵣₘₛ²R = ⟨I²⟩ R ⇒ Iᵣₘₛ = square root of (⟨I²⟩)

where ⟨I²⟩ is the mean of I² over a complete cycle. The name gives the order of operations: square the current, take the mean, then the square root. The r.m.s. voltage is defined in the same way.

Square before averaging

For a complete sinusoid, the squared normalised current has cycle mean 0.5. Its positive square root gives Iᵣₘₛ/I₀ = 1/√2. Both current directions contribute to heating.

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For a complete sinusoid, the squared normalised current has cycle mean 0.5. Its positive square root gives Iᵣₘₛ/I₀ = 1/√2. Both current directions contribute to heating.For a complete sinusoid, the squared normalised current has cycle mean 0.5. Its positive square root gives Iᵣₘₛ/I₀ = 1/√2. Both current directions contribute to heating.
For a complete sinusoid, the squared normalised current has cycle mean 0.5. Its positive square root gives Iᵣₘₛ/I₀ = 1/√2. Both current directions contribute to heating.
Open full-size graph
What to noticeCalculated ideal-model values; not experimental measurements.
View figure data
Figure data: Square before averaging
Time, t (ms)Squared currentCycle mean
0.00.00000000.5
0.10.00098660.5
0.20.00394260.5
0.30.00885640.5
0.40.01570840.5
0.50.02447170.5
0.60.03511180.5
0.70.04758650.5
0.80.06184670.5
0.90.07783600.5
1.00.09549150.5
1.10.11474340.5
1.20.13551570.5
1.30.15772640.5
1.40.18128800.5
1.50.20610740.5
1.60.23208660.5
1.70.25912320.5
1.80.28711040.5
1.90.31593770.5
2.00.34549150.5
2.10.37565510.5
2.20.40630930.5
2.30.43733340.5
2.40.46860470.5
2.50.50000000.5
2.60.53139530.5
2.70.56266660.5
2.80.59369070.5
2.90.62434490.5
3.00.65450850.5
3.10.68406230.5
3.20.71288960.5
3.30.74087680.5
3.40.76791340.5
3.50.79389260.5
3.60.81871200.5
3.70.84227360.5
3.80.86448430.5
3.90.88525660.5
4.00.90450850.5
4.10.92216400.5
4.20.93815330.5
4.30.95241350.5
4.40.96488820.5
4.50.97552830.5
4.60.98429160.5
4.70.99114360.5
4.80.99605740.5
4.90.99901340.5
5.01.00000000.5
5.10.99901340.5
5.20.99605740.5
5.30.99114360.5
5.40.98429160.5
5.50.97552830.5
5.60.96488820.5
5.70.95241350.5
5.80.93815330.5
5.90.92216400.5
6.00.90450850.5
6.10.88525660.5
6.20.86448430.5
6.30.84227360.5
6.40.81871200.5
6.50.79389260.5
6.60.76791340.5
6.70.74087680.5
6.80.71288960.5
6.90.68406230.5
7.00.65450850.5
7.10.62434490.5
7.20.59369070.5
7.30.56266660.5
7.40.53139530.5
7.50.50000000.5
7.60.46860470.5
7.70.43733340.5
7.80.40630930.5
7.90.37565510.5
8.00.34549150.5
8.10.31593770.5
8.20.28711040.5
8.30.25912320.5
8.40.23208660.5
8.50.20610740.5
8.60.18128800.5
8.70.15772640.5
8.80.13551570.5
8.90.11474340.5
9.00.09549150.5
9.10.07783600.5
9.20.06184670.5
9.30.04758650.5
9.40.03511180.5
9.50.02447170.5
9.60.01570840.5
9.70.00885640.5
9.80.00394260.5
9.90.00098660.5
10.00.00000000.5
10.10.00098660.5
10.20.00394260.5
10.30.00885640.5
10.40.01570840.5
10.50.02447170.5
10.60.03511180.5
10.70.04758650.5
10.80.06184670.5
10.90.07783600.5
11.00.09549150.5
11.10.11474340.5
11.20.13551570.5
11.30.15772640.5
11.40.18128800.5
11.50.20610740.5
11.60.23208660.5
11.70.25912320.5
11.80.28711040.5
11.90.31593770.5
12.00.34549150.5
12.10.37565510.5
12.20.40630930.5
12.30.43733340.5
12.40.46860470.5
12.50.50000000.5
12.60.53139530.5
12.70.56266660.5
12.80.59369070.5
12.90.62434490.5
13.00.65450850.5
13.10.68406230.5
13.20.71288960.5
13.30.74087680.5
13.40.76791340.5
13.50.79389260.5
13.60.81871200.5
13.70.84227360.5
13.80.86448430.5
13.90.88525660.5
14.00.90450850.5
14.10.92216400.5
14.20.93815330.5
14.30.95241350.5
14.40.96488820.5
14.50.97552830.5
14.60.98429160.5
14.70.99114360.5
14.80.99605740.5
14.90.99901340.5
15.01.00000000.5
15.10.99901340.5
15.20.99605740.5
15.30.99114360.5
15.40.98429160.5
15.50.97552830.5
15.60.96488820.5
15.70.95241350.5
15.80.93815330.5
15.90.92216400.5
16.00.90450850.5
16.10.88525660.5
16.20.86448430.5
16.30.84227360.5
16.40.81871200.5
16.50.79389260.5
16.60.76791340.5
16.70.74087680.5
16.80.71288960.5
16.90.68406230.5
17.00.65450850.5
17.10.62434490.5
17.20.59369070.5
17.30.56266660.5
17.40.53139530.5
17.50.50000000.5
17.60.46860470.5
17.70.43733340.5
17.80.40630930.5
17.90.37565510.5
18.00.34549150.5
18.10.31593770.5
18.20.28711040.5
18.30.25912320.5
18.40.23208660.5
18.50.20610740.5
18.60.18128800.5
18.70.15772640.5
18.80.13551570.5
18.90.11474340.5
19.00.09549150.5
19.10.07783600.5
19.20.06184670.5
19.30.04758650.5
19.40.03511180.5
19.50.02447170.5
19.60.01570840.5
19.70.00885640.5
19.80.00394260.5
19.90.00098660.5
20.00.00000000.5

Check your understanding 1 Zero average, non-zero heating

A current is + 2.0 A for half a cycle and -2.0 A for the other half. Calculate its mean current and its r.m.s. current. Explain why a resistor still heats.

Unit: A
Show the steps Optional working
Unit: A²
Unit: A

Show answer

The mean current is (2.0-2.0)/2 = 0. The mean square is (4.0 + 4.0)/2 = 4.0 A², giving Iᵣₘₛ = 2.0 A. Heating depends on I²R, which is positive in both directions.

Check your understanding 2 Explain the heating

Explain why zero mean current does not imply zero mean power. Compare averaging before and after squaring.

Show answer

Compare ⟨I⟩²R with ⟨I²⟩ R. Opposite currents cancel in the mean of I; their squares do not cancel. A resistor heats in both directions.

R.m.s. value of a sinusoid

For I = I₀ sin ω t, I² = I₀² sin² ω t. Since sin² θ = (1/2)(1- cos 2θ) and cos 2θ averages to zero over a cycle, the mean of sin² ω t is 1/2. So ⟨I²⟩ = (1/2)I₀² and

Iᵣₘₛ = I₀/(square root of 2), Vᵣₘₛ = V₀/(square root of 2)

These hold only for a sinusoid. For any other waveform, go back to square, mean, root.

Mains voltage ratings are quoted as r.m.s. values. The 230 V mains has a peak of 230 square root of 2 = 325 V.

Worked example 1

From r.m.s. value to equation

Problem

A sinusoidal current has an r.m.s. value of 3.00 A and a frequency of 60.0 Hz. It is zero and increasing at t = 0. Write an equation for the current.

Show full solution
  1. Peak value

    Method

    Multiply the r.m.s. current by square root of 2.

    Reason

    The number in front of the sine must be the peak, not the r.m.s. value.

    Working

    Answer

    I₀ = square root of 2 × 3.00 = 4.24 A

  2. Angular frequency

    Reason

    ω = 2π f.

    Working

    Answer

    ω = 2π × 60.0 = 120π rad s⁻¹

  3. Equation

    Working

    Answer

    I = 4.24 sin(120π t), with I in amperes and t in seconds

Guided practice 2

What an r.m.s. voltage means

About 3 min

Problem

A sinusoidal voltage has a peak value of 20.0 V. Find its r.m.s. value, and state what that value means for a resistor connected to it.

Find the r.m.s. voltage

Unit: V
A steady voltage equal to this r.m.s. value gives the same resistor

Hints

Hint 1

meaning

The meaning is a comparison with a steady voltage across the same resistor.

Show full solution
  1. Value and meaning

    Working

    Answer

    Vᵣₘₛ = 20.0/(square root of 2) = 14.1 V. A steady 14.1 V across the same resistor would give the same mean power.

Spot the mistake 3

Which number is the r.m.s. current?

About 3 min

Learner claim

For I = 5.00 sin(100π t), in amperes, a student says the r.m.s. current is 5.00 A. What does 5.00 A represent, and what is the r.m.s. current?

Try this before viewing the solution

5.00 A is the
Unit: A

Show solution step by step
  1. Read the peak

    Method

    Identify 5.00 A as the peak I₀.

    Reason

    sin(100π t) varies between -1 and + 1, so the current varies between -5.00 A and + 5.00 A.

    Working

    Answer

    I₀ = 5.00 A

  2. Convert

    Working

    Answer

    Iᵣₘₛ = 5.00/(square root of 2) = 3.54 A

Try it yourself 4

A pulsed current

Minimal support

Problem

A repeating current is 4.0 A for one quarter of each cycle and zero for the other three quarters. Find its r.m.s. value.

Find the r.m.s. current

Show the steps Optional working
Unit: A²
Unit: A

Hints

Hint 1

not a sinusoid

I₀/square root of 2 does not apply. Weight each value of I² by the fraction of the cycle it lasts.

Show solution step by step
  1. Mean square

    Reason

    The current is 4.0 A for a quarter of the time and zero otherwise.

    Working

    Answer

    ⟨I²⟩ = (1/4)(4.0)² + (3/4)(0)² = 4.0 A²

  2. Root

    Working

    Answer

    Iᵣₘₛ = square root of 4.0 = 2.0 A

Exam-style question 1

The mains supply

5 marks

Examination question

A sinusoidal mains supply is labelled 230 V, 50.0 Hz.

(a) Explain what is meant by the r.m.s. value of an alternating voltage. [2 marks]

(b) Calculate the peak voltage of the supply. [1 mark]

(c) The voltage is zero and increasing at t = 0. Write an equation for the voltage V at time t. [2 marks]

Write your answer before viewing the mark scheme

Show solution step by step
  1. (a) Meaning

    2 marks

    Method

    Compare with a steady voltage across the same resistor.

    Reason

    The r.m.s. value is defined by equal heating.

    Working

    Answer

    It is the steady (direct) voltage that would produce the same mean power in the same resistor.

  2. (b) Peak

    1 mark

    Reason

    Mains labels give r.m.s. values.

    Working

    Answer

    V₀ = square root of 2 × 230 = 325 V

  3. (c) Equation

    2 marks

    Working

    Answer

    ω = 2π × 50.0 = 100π rad s⁻¹, so V = 325 sin(100π t), in volts

Common mistakes

  • Putting the r.m.s. value in front of the sine instead of the peak.
  • Treating the r.m.s. value as the average current; the average of a sinusoid over a cycle is zero.
  • Using I₀/square root of 2 for a waveform that is not a full sinusoid, such as a half-wave rectified or square wave.
  • Taking the square root before averaging.

Spotted an error? Report a correction

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