RLC Circuits Analysis

Key idea: Set up the source-free series RLC differential equation, classify damping regimes using R and Rc, and use standard solution forms with examples.

  • GCE A-Level H3 Physics 2027
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Learning objectives

  • Apply U = ½LI² to the energy stored in an inductor.
  • Derive the expression U = ½LI² for the potential energy stored in an inductor by considering the work done on charges.
  • solve problems using the formulae for the combined inductance of two or more inductors in series and in parallel
  • solve problems involving circuits with resistors, inductors, and sources of constant e.m.f. (includes solving first-order differential equations) [RL series circuits with constant e.m.f. source]
  • solve problems involving circuits with inductors and capacitors only (includes solving second-order differential equations) [LC series circuits without e.m.f. source]
  • solve problems involving circuits with resistors, inductors and capacitors only (candidates are not expected to solve the general second-order differential equations, though they can be asked to verify and use particular solutions). [RLC series circuits without e.m.f. source]

An RLC series circuit with no e.m.f. source is a second-order transient system. Depending on R, it can:

  • oscillate with decaying amplitude (underdamped), or
  • return to equilibrium without oscillating (critical/overdamped).

In H3, you are not expected to solve the most general second-order differential equation from scratch, but you should be able to set up the equation, identify the regime, and use/verify standard solution forms.

1. Definitions (Must Know)

  • State variable (common choice): capacitor charge q(t) (C).
  • Current: I(t) = dq/dt
  • KVL for source-free series RLC: V_L + V_R + V_C = 0
  • Using V_L = LdI/dt = Ld²q/dt², V_R = IR = Rdq/dt, V_C = q/C gives: Ld²q/dt² + Rdq/dt + q/C = 0
  • Natural angular frequency (LC): ω₀ = 1/(square root of LC)
  • Damping factor: γ = R/2L
  • Damped angular frequency (underdamped): ω_d = square root of (ω₀²-γ²)
  • Critical resistance: R_c = 2 square root of (L/C)
  • Symbols used in this lesson: L (H), R (Ω), R_c critical resistance (Ω), C (F), q (C), I (A), t (s), ω₀,ω_d (rad s⁻¹), γ (s⁻¹).

2. Key Ideas (What Earns Marks)

  • The governing equation is: q double dot + R/Lq dot + (1/LC)q = 0 where dots denote time derivatives.
  • Determine the behaviour from R relative to R_c:
    • Underdamped: R < R_c (oscillatory, decaying)
    • Critical: R = R_c (fastest return without oscillation)
    • Overdamped: R > R_c (no oscillation, slower return)
  • In underdamped case, amplitude decays as e^(-γ t): q(t) = Qe^(-γ t) cos(ω_dt + φ) and I(t) = dq/dt is also sinusoidal with the same envelope.
  • The resistor dissipates energy. For weak damping, the energy envelope and cycle-averaged stored energy decay approximately as e^(-2γ t); the instantaneous total stored energy is not a perfect exponential throughout each cycle.

Quick classification table:

RegimeConditionWhat you see
UnderdampedR < R_cOscillations with decaying envelope
CriticalR = R_cFastest return without oscillation
OverdampedR > R_cNo oscillation, slower return
Capacitor charge against time for underdamped, critically damped, and overdamped source-free series RLC responses
Critical damping is the boundary between oscillatory and non-oscillatory responses and gives the fastest return without crossing equilibrium.

3. Detailed Explanations

A. Setting up the ODE (the main H3 skill)

Use KVL and write each element voltage in terms of q:

  • V_L = Ld²q/dt²
  • V_R = Rdq/dt
  • V_C = q/C

So: Lq double dot + Rq dot + q/C = 0

B. How to classify the response quickly

Define: ω₀ = 1/(square root of LC), γ = R/2L

  • If γ < ω₀, ω_d is real and you get oscillations (underdamped).
  • If γ = ω₀, you are critically damped.
  • If γ > ω₀, you are overdamped.

Equivalent resistance test: R_c = 2 square root of (L/C)

C. “Use/verify” a given solution form (what the syllabus allows)

If you are given a proposed form for q(t), you can verify it by:

  1. differentiating to get q dot and q double dot, and
  2. substituting into Lq double dot + Rq dot + q/C = 0 to check it holds.

This is often faster than solving from scratch and is explicitly within H3 expectations.

4. Common Mistakes

  • Using the wrong variable: mixing q(t) and I(t) without using I = dq/dt consistently.
  • Forgetting the capacitor relation V_C = q/C.
  • Using ω = 1/square root of LC even when R is not negligible (use ω_d for underdamped).
  • Confusing γ = R/2L with τ = L/R (RL time constant).

5. Exam Tips

  • Start from the canonical ODE: Lq double dot + Rq dot + q/C = 0

  • Immediately compute R_c = 2 square root of (L/C) to classify the regime.

  • If the question gives/assumes “underdamped oscillations”, use: γ = R/2L

    ω_d = square root of (1/LC-(R/2L)²)

  • Useful decay facts (underdamped):

    • amplitude time constant: τₐₘₚ = 1/γ = 2L/R
    • energy decays with half the time constant: τ_U = 1/2γ = L/R

6. Worked Examples

Modelled example 1

Classify the response and find ω_d

Core

Problem

An RLC circuit has L = 0.50 H, C = 8.0 μF and R = 10 Ω. Classify its response and find ω_d.
Study the worked solution
  1. Find the undamped scale

    Method

    ω₀ = 500 rad s⁻¹.

    Reason

    ω₀ = 1/square root of LC.

    Working

    ω₀ = 1/square root of ((0.50)(8.0 × 10⁻⁶)) = 500
  2. Find damping rate

    Method

    γ = 10 s⁻¹.

    Reason

    γ = R/(2L).

    Working

    γ = 10/[2(0.50)] = 10
  3. Classify and calculate

    Method

    The response is underdamped and ω_d = 499.9 rad s⁻¹.

    Reason

    γ < ω₀ and ω_d = square root of (ω₀²-γ²).

    Working

    ω_d = square root of (500²-10²) = 499.9

Guided practice 2

Verify a proposed solution form (underdamped)

About 8 min

Problem

Verify that q = Qe^(-γ t) cos(ω_dt) satisfies q double dot + (R/L)q dot + q/(LC) = 0 when γ = R/(2L) and ω_d² = 1/(LC)-γ².

Try this before viewing the solution

Hints

Hint 1: group sine and cosine terms
After differentiating twice, substitute and require the sine and cosine coefficients to vanish separately.
View solution step by step
  1. Differentiate

    Method

    q dot = Qe^(-γ t)(-γ c-ω_ds).

    Reason

    Use product and chain rules, with c = cos ω_dt and s = sin ω_dt.

    Working

    q double dot = Qe^(-γ t)[(γ²-ω_d²)c + 2γω_ds]
  2. Cancel sine terms

    Method

    2γ = R/L.

    Reason

    The differential equation must hold for all t.

    Working

    γ = R/(2L)
  3. Cancel cosine terms

    Method

    ω_d² = 1/(LC)-γ².

    Reason

    Substituting the damping condition leaves this coefficient relation.

    Working

    γ²-ω_d²-(R/L)γ + 1/(LC) = 0

Common misconception 3

Find the amplitude decay time constant

Find and correct the mistake

Learner claim

For L = 0.20 H and R = 5.0 Ω, a learner uses L/R as the amplitude decay time. Explain the missing factor and find τₐₘₚ.

Try this before viewing the solution

Amplitude time constant

View solution step by step
  1. Read the envelope

    Method

    The amplitude factor is e^(-Rt/(2L)).

    Reason

    γ = R/(2L).

    Working

    e^(-t/τₐₘₚ) = e^(-Rt/(2L))
  2. Find the time constant

    Method

    τₐₘₚ = 0.080 s.

    Reason

    τₐₘₚ = 2L/R.

    Working

    τₐₘₚ = 2(0.20)/5.0 = 0.080 s

Examiner practice 4

Find the critical resistance

3 marks

Examination question

A series RLC circuit has L = 0.20 H and C = 5.0 μF. Find R_c. [3 marks]

Try this before viewing the solution

View solution step by step
  1. State the boundary

    1 mark

    Method

    R_c = 2 square root of (L/C).

    Reason

    Critical damping occurs when R/(2L) = 1/square root of LC.

    Working

    R_c = 2 square root of (L/C)
  2. Substitute

    1 mark

    Method

    R_c = 2 square root of (0.20/(5.0 × 10⁻⁶)).

    Reason

    Convert microfarads to farads.

    Working

    square root of 40000 = 200
  3. Report

    1 mark

    Method

    R_c = 400 Ω.

    Reason

    Resistance has ohm units.

    Working

    R_c = 2(200) = 400 Ω

Challenge 5

Decide whether it is overdamped

Minimal support

Independent transfer

For the circuit in Example D, R_c = 400 Ω but the actual resistance is 600 Ω. Classify the response and state whether it oscillates.

Try this before viewing the solution

Hints

Hint 1: compare with the boundary
Overdamping occurs on the high-resistance side of critical damping.
View solution step by step
  1. Compare resistances

    Method

    R > R_c.

    Reason

    600 Ω > 400 Ω.

    Working

    R/R_c = 1.5
  2. Classify

    Method

    The response is overdamped and non-oscillatory.

    Reason

    Resistance exceeds the critical boundary.

    Working

    R > R_c ⇒ overdamped

7. Mind Stretchers

Mind stretcher 1: Why R changes the frequencyExtension

In an LC circuit, ω₀ = 1/square root of LC. In an underdamped RLC circuit, the oscillation frequency is ω_d < ω₀.

Why does adding a resistor reduce the oscillation frequency?

Answer

The resistance introduces a term proportional to dq/dt in the differential equation. For an underdamped solution, this changes the oscillatory part of the characteristic response from ω₀ to ω_d = square root of (ω₀²-γ²). Since γ² > 0, ω_d < ω₀. Energy dissipation explains the shrinking amplitude; the differential equation gives the frequency shift.

Mind stretcher 2: How fast does the energy decay?Extension

In a weakly underdamped RLC circuit, the amplitude envelope decays like e^(-γ t), so the energy envelope scales approximately as U ∝ e^(-2γ t).

After time t = 1/γ, by what factor has the energy decreased?

Answer

At t = 1/γ: U/U₀ = e^(-2γ(1/γ)) = e⁻² ≈ 0.135 So the energy drops to about 13.5% of its initial value.

8. Optional/Enrichment: Full Solutions (Not Required)

Full derivations use the characteristic equation of the second-order ODE and produce different functional forms for under/critical/over damping. H3 typically focuses on using the standard forms and verifying them when needed.

Next step

Return to the RLC Circuits hub for mixed revision, then continue to Special Relativity.

Continue with the next resource in this course.

Course and syllabus information
Course
GCE A-Level H3 Physics
Edition
GCE A-Level H3 Physics 2027