Quantum Harmonic Oscillator

Key idea: H3 Quantum Mechanics: the quantum harmonic oscillator — energy levels En=(n+1/2)ħω, equal spacing, and why the ground state energy cannot be zero.

  • Advanced Physics
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Learning objectives

  • Use state functions, boundary conditions, stationary states, and measurement to analyse introductory quantum systems.

The quantum harmonic oscillator is one of the most important models in quantum physics because many systems behave “approximately harmonic” near a stable equilibrium position.

1. Model and energy spectrum

Near equilibrium, a restoring force of the form F = -kx corresponds to a quadratic potential:

V(x) = (1/2)kx² = (1/2)mω² x² where ω = square root of (k/m)

The allowed energies are:

Eₙ = (n + 1/2)ħω (n = 0,1,2,…)

Immediate consequences:

  • Ground state is not zero: E₀ = (1/2)ħω (zero-point energy).
  • Equal spacing: Eₙ₊₁-Eₙ = ħω (constant for all n).
Quantum harmonic-oscillator potential and energy levelsParabolic potential-energy curve containing horizontal, equally spaced levels from n equals zero to n equals three, with the ground state above zero energy.xenergyV(x) = ½mω²x²n = 0, E₀ = ½ħωn = 1n = 2n = 3spacing ħω
Scroll diagram horizontally to read all labels.
The quadratic potential contains equally spaced levels separated by ħω; n = 0 still has the zero-point energy E₀ = ħω/2.

2. Why the ground-state energy cannot be zero

The oscillator has both kinetic and potential energy. A standard H3 argument uses the uncertainty principle to estimate the minimum possible energy.

For a state centred on the equilibrium point with ⟨x⟩ = ⟨p⟩ = 0, write the energy in terms of its spreads:

E = ((Δ p)²)/2m + (1/2)mω²(Δ x)².

Using Δ x Δ p ≥ ħ/2 gives the lower bound

E(Δ x) ≥ ħ²/(8m(Δ x)²) + (1/2)mω²(Δ x)².

Minimise with respect to Δ x:

dE/(d(Δ x)) = -ħ²/(4m(Δ x)³) + mω²(Δ x) = 0; (Δ x)² = ħ/2mω

Substitute back to get the minimum energy scale:

Eₘᵢₙ ≥ (1/2)ħω.

The oscillator ground state is a minimum-uncertainty Gaussian and reaches this bound, so its exact energy is E₀ = ħω/2.

What to say in explanations

Even at T = 0, the particle cannot have both Δ x = 0 and Δ p = 0. Confinement near equilibrium forces a non-zero momentum spread, hence a non-zero minimum kinetic energy.

3. Common mistakes

  1. Using the particle-in-a-box rule n = 1 as the ground state (for the harmonic oscillator, ground state is n = 0).
  2. Mixing h and ħ (ħ = h/2π).
  3. Mixing frequency f and angular frequency ω (ω = 2π f).

4. Useful checks

  • If asked “why E₀ ≠ 0?”, use the uncertainty-principle wording: “a state cannot have both Δ x and Δ p arbitrarily small.”
  • If asked for energy differences, go straight to Δ E = ħω.

5. Quick check

A. What is the spacing between adjacent energy levels?

Answer
E_(n + 1)-Eₙ = ħω.

B. If ω doubles, what happens to the ground state energy?

Answer

E₀ = (1/2)ħω doubles.

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Course and syllabus information
Course
Advanced Physics
Edition
Advanced Physics