Blackbody Radiation

Key idea: Interpret blackbody spectra and apply Stefan–Boltzmann and Wien laws while distinguishing emitted power, spectral intensity, temperature, and emissivity.

  • Advanced Physics
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Learning objectives

  • Connect blackbody evidence, Planck quantisation, photon momentum, and Compton scattering.

A blackbody is an ideal surface that absorbs all incident electromagnetic radiation and, in thermal equilibrium, emits the maximum possible spectral radiance at each wavelength for its temperature. A cavity with a small hole provides a close experimental approximation.

1. Definitions and quantities

  • Absolute temperature, T (K), sets the shape and scale of the spectrum.

  • Spectral intensity describes how emission is distributed over wavelength or frequency. Always identify which variable is on the horizontal axis.

  • Emissivity, e, is the ratio of a real surface’s total emissive power to that of a blackbody at the same temperature; 0 ≤ e ≤ 1.

  • Stefan–Boltzmann law:

    P = eσ AT⁴

    where σ = 5.67 × 10⁻⁸ W m⁻²K⁻⁴.

  • Wien displacement law:

    λₘₐₓT = b

    where b = 2.90 × 10⁻³ m K for a wavelength spectrum.

Blackbody spectra and the Rayleigh–Jeans failure

Hotter and cooler blackbody spectra each rise to a peak and fall at short wavelength. The hotter peak is at shorter wavelength and has greater area. A dashed Rayleigh–Jeans curve diverges toward zero wavelength.

Scroll across the graph to read all labels.

Hotter and cooler blackbody spectra each rise to a peak and fall at short wavelength. The hotter peak is at shorter wavelength and has greater area. A dashed Rayleigh–Jeans curve diverges toward zero wavelength.Hotter and cooler blackbody spectra each rise to a peak and fall at short wavelength. The hotter peak is at shorter wavelength and has greater area. A dashed Rayleigh–Jeans curve diverges toward zero wavelength.
Raising temperature increases the area under the wavelength-spectrum curve and moves its peak to shorter wavelength. The dashed classical curve fails at short wavelength.
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Values and uncertainty for Blackbody spectra and the Rayleigh–Jeans failure
SeriesWavelength (relative units)Wavelength uncertaintySpectral intensity (relative units)Spectral intensity uncertainty
Hotter body0.50.01
Hotter body10.12
Hotter body1.50.45
Hotter body20.78
Hotter body2.50.96
Hotter body31
Hotter body3.50.94
Hotter body40.83
Hotter body50.62
Hotter body60.46
Hotter body70.34
Hotter body80.25
Hotter body90.18
Hotter body100.13
Cooler body0.50
Cooler body10.01
Cooler body1.50.04
Cooler body20.1
Cooler body2.50.2
Cooler body30.32
Cooler body3.50.44
Cooler body40.53
Cooler body50.6
Cooler body60.57
Cooler body70.49
Cooler body80.4
Cooler body90.32
Cooler body100.25
Rayleigh–Jeans prediction0.51.45
Rayleigh–Jeans prediction10.9
Rayleigh–Jeans prediction1.50.58
Rayleigh–Jeans prediction20.4
Rayleigh–Jeans prediction2.50.29
Rayleigh–Jeans prediction30.22
Rayleigh–Jeans prediction40.14
Rayleigh–Jeans prediction50.1
Rayleigh–Jeans prediction60.07
Rayleigh–Jeans prediction80.04
Rayleigh–Jeans prediction100.025

2. Reading a spectrum

For a wavelength spectrum:

  • the area under the curve is proportional to total emitted power per unit area;
  • the hotter curve lies higher overall and has a larger area because total power varies as T⁴;
  • the hotter curve peaks at smaller λ because λₘₐₓ ∝ 1/T;
  • the intensity tends to zero at both very long and very short wavelength.

Do not convert a wavelength peak to a frequency peak using f = c/λₘₐₓ. Spectral density is defined per unit interval, and the change of variable introduces a Jacobian; the two peak locations are not simple reciprocals.

3. Physical model and assumptions

A cavity’s walls absorb and emit radiation until the radiation field reaches thermal equilibrium. The small hole samples that field while disturbing it minimally. The ideal laws assume uniform temperature and negligible external irradiation when discussing emitted power.

For a real body exchanging radiation with surroundings at temperature Tₛ, the net radiative power is

Pₙₑₜ = eσ A(T⁴-Tₛ⁴)

not simply eσ AT⁴.

4. Common mistakes

  • Saying a blackbody emits no radiation because it appears black. Absorption and emission are different processes; a hot blackbody is a strong emitter.
  • Using degrees Celsius in fourth-power or displacement laws. Use kelvin.
  • Treating the peak height as total power. Total power corresponds to area under the spectrum.
  • Applying Wien’s wavelength constant to a frequency-spectrum peak.
  • Forgetting emissivity or surrounding radiation for a real surface when the question supplies them.

6. Worked Examples

Modelled example 1

Peak wavelength of a hot surface

Core

Problem

A blackbody is at 5800 K. Find the peak wavelength of its wavelength spectrum.
Study the worked solution
  1. Apply Wien's law

    Method

    λₘₐₓ = 5.0 × 10⁻⁷ m = 500 nm.

    Reason

    Peak wavelength is inversely proportional to absolute temperature.

    Working

    λₘₐₓ = (2.90 × 10⁻³)/5800 = 5.0 × 10⁻⁷ m

Guided practice 2

Power change with temperature

About 4 min

Problem

The same blackbody surface rises from 300 K to 600 K. Find P₂/P₁.

Try this before viewing the solution

Hints

Hint 1: cancel unchanged factors
Area and emissivity are unchanged.
View solution step by step
  1. Form the fourth-power ratio

    Method

    P₂/P₁ = 16.

    Reason

    Stefan–Boltzmann power scales as T⁴ for the same surface.

    Working

    P₂/P₁ = (600/300)⁴ = 16

Challenge 3

Net radiative loss

Minimal support

Independent transfer

A surface of area 0.50 m² and emissivity 0.80 is at 400 K in surroundings at 300 K. Calculate its net radiative power loss.

Try this before viewing the solution

Hints

Hint 1: subtract both radiation streams
Use the difference T⁴-Tₛ⁴, not merely T-Tₛ.
View solution step by step
  1. Use net emission

    Method

    Pₙₑₜ = 4.0 × 10² W.

    Reason

    The surface emits and also absorbs radiation from its surroundings.

    Working

    Pₙₑₜ = eσ A(T⁴-Tₛ⁴) = (0.80)(5.67 × 10⁻⁸)(0.50)(400⁴-300⁴) = 4.0 × 10² W

7. Model check

Mind stretcher 1: Temperature scaling checkExtension

If T doubles, λₘₐₓ halves while total power per unit area rises by a factor of 16. Those simultaneous trends are a useful check on any spectrum sketch.

Next: Failure of Classical Theory.

Continue with the next resource in this course.

Course and syllabus information
Course
Advanced Physics
Edition
Advanced Physics