Rotational Dynamics & Rolling (IPhO Mechanics)
IPhO mechanics lesson on torque, angular momentum, moments of inertia, and rolling without slipping.
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Rigid body questions become straightforward once you separate (1) translation of the centre of mass from (2) rotation about a chosen axis, and treat rolling as a constraint rather than “a friction force you guess”.
Learning objectives
By the end, you should be able to:
- IPHO-M-ROT-01: combine ∑ F = ma_cm, ∑τ_cm = I_cmα and the correct contact constraint;
- IPHO-M-ROT-02: infer static-friction direction from incipient slip and verify |fₛ| ≤ μₛN; and
- check the chosen moment of inertia, sign convention and limiting behaviour.
- Torque & Couples (A Level)
- UY1: Moment of Inertia
- Optional alternative method: Intro to Lagrangian Mechanics (IPhO)
1. Definitions
- Torque about point O: vector τ_O = vector r × vector F, and in general ∑ vector τ_O = d vector L_O/dt.
- Moment of inertia about an axis: I = ∫ r_⊥² dm (distance perpendicular to the axis).
- Parallel axis theorem: I_O = I_cm + md².
- Angular momentum about the centre (fixed axis through centre): L_cm = I_cmω.
- Rolling without slipping (radius R on a stationary surface):
v_cm = ω R, a_cm = α Ralong the direction of motion.
- Static friction fₛ: adjusts to enforce no slip, with |fₛ| ≤ μₛ N.
- Instantaneous contact inertia: for a rolling body, I_P = I_cm + mR² about the contact point P.
2. Key ideas
- Default template:
∑ Fₓ = m a_cm, ∑τ_cm = I_cmα, a_cm = α R.
- On a stationary surface with pure rolling, static friction does no work at the contact (instantaneous contact speed is zero). Energy methods are often the fastest.
- The rolling acceleration down an incline has a memorisable form:
a = (g sin α)/(1 + I_cm/(mR²)).
- Friction direction is set by the tendency to slip at the contact, not by the direction of the centre-of-mass velocity.
- Newton + torque about centre, then use a = α R.
- Energy + rolling: mgh = 1/2 mv² + 1/2 Iω² with v = ω R.
- One-coordinate energy or Lagrangian method, with x = Rθ built in from the start.
3. Detailed explanation
3.1 Translation plus rotation (why it is reliable)
For planar rolling with one translational coordinate x and one rotation angle θ, you can nearly always write:
- translation of the centre of mass,
- rotation about the centre of mass,
- the no-slip constraint relating x and θ.
This avoids guessing friction and gives you a closed system of equations.
3.2 Why torque about contact is not the default
The contact point is an instantaneous centre of zero velocity, but it is generally not a fixed inertial pivot and may have nonzero acceleration. Therefore the fixed-axis equation ∑τ_P = I_Pα cannot be invoked solely because the contact point is instantaneously at rest.
Use centre-of-mass translation plus centre-of-mass torque as the reliable dynamics route. An angular-momentum calculation about a moving point needs the full transport relation and an explicit justification; it is rarely the shortest safe competition solution.
3.3 Static friction: direction and size
A clean approach:
- Decide the likely direction of slip if the surface were frictionless.
- Set friction opposite that slip tendency.
- Solve for fₛ from dynamics.
- Verify |fₛ| ≤ μₛ N. If not, rolling without slipping is impossible and the motion must involve slipping.
4. Common mistakes
- Using v = ω R even though the body is slipping (constraint broken).
- Using the wrong axis for I or forgetting the parallel axis theorem.
- Assuming friction always opposes motion of the centre of mass.
- Writing ∑τ = Iα about a point that is accelerating without justification.
5. Problem-solving tips
- State your sign convention early (clockwise positive or anticlockwise positive).
- If you compute friction, always check it against μₛ N.
- Use the limit I_cm → 0 as a quick checksum: you should recover particle-like motion.
- If a surface is moving (belt), do not assume static friction does no work in the lab frame.
6. Worked examples
1) Solid cylinder rolling down an incline (find a and minimum mu_s)
A solid cylinder (mass m, radius R) rolls without slipping down an incline of angle α.
For a solid cylinder, I_cm = 1/2 mR².
Translation along the slope (down-slope positive):
Rotation about the centre:
so
Substitute into translation:
Then
No-slip requires |f| ≤ μₛ N = μₛ mg cos α, hence
2) Pulling a cylinder: friction direction can flip (centre pull vs top pull)
A cylinder (mass m, radius R, I_cm = β mR²) rolls without slipping on rough horizontal ground. Compare two cases with the same horizontal force F to the right.
(A) Force applied through the centre. Translation:
Rotation about centre:
So
(B) Force applied tangentially at the top. Translation:
Torque about centre (clockwise positive for rolling right):
Solve the pair:
Add them:
Then
Takeaway: static friction enforces no slip, and its direction depends on the torque you apply.
7. Extension
1) Rolling on a moving belt: static friction can add energy
A cylinder (mass m, radius R, moment of inertia I_cm) is gently placed on a belt moving right at constant speed u. Initially v_cm = 0 and ω = 0. It slips at first (kinetic friction), then eventually reaches rolling without slipping relative to the belt.
During slipping, friction accelerates translation and produces angular acceleration:
Starting from rest:
No slip relative to the belt means the contact point matches belt speed:
Eliminate t to get final speeds (independent of F_f):
Why this is a mind stretcher: even when slipping stops, the belt’s motor is the energy source, so mechanical energy of the cylinder can increase.
8. Practice and evidence
- Do one incline rolling problem where you must compute fₛ and check |fₛ| ≤ μₛ N.
- Do one pulled-cylinder or spool problem and justify the friction direction from slip tendency.
- Treat IPHO-M-ROT-01/02 as passed only when both solutions include a declared angular sign convention and a no-slip feasibility check.
- Then continue via the IPhO Mechanics Hub.
Syllabus and review details
No official syllabus alignment is listed for this lesson.
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