Radioactivity & Radioactive Decay

Understand radioactive decay: random and spontaneous, how alpha/beta/gamma change A and Z, and how to subtract background count-rate in exam questions (O Level).

  • SEC G3 Physics 2027
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Learning objectives

  • Explain random and spontaneous nuclear decay
  • Describe alpha, beta-minus and gamma radiation
  • Use nuclide equations for radioactive decay
  • Explain background radiation

1. Definition

Radioactivity is the spontaneous emission of ionising radiation from an unstable nucleus.

2. Key Ideas

  • Radioactive decay is:
    • random (cannot predict which nucleus decays next)
    • spontaneous (no external trigger needed)
    • not affected by temperature, pressure, or chemical state
  • Parent nucleus → daughter nucleus.
  • Emissions and how A and Z change:
    • alpha ⁴₂He: A-4, Z-2
    • beta (β−) ⁰₋₁e: A same, Z + 1
    • gamma ⁰₀γ: A and Z unchanged (energy release)
  • In measurements, subtract background count-rate to get the net count-rate due to the source.
What you need for this course

You should be able to describe radioactive decay as random and spontaneous, track how A and Z change in alpha, beta-minus and gamma emission, and account for background radiation.

How alpha, beta-minus and gamma affect A and ZThree quick-reference panels showing parent-to-daughter changes in nucleon number and proton number for alpha, beta-minus and gamma emissions.AlphaA -> A - 4Z -> Z - 2emit 4/2 HeBeta-minusA -> AZ -> Z + 1emit 0/-1 eGammaA -> AZ -> Zemit gamma ray
Quick check: alpha changes A and Z, beta-minus changes Z only, gamma changes neither.

3. Detailed Explanations

A. Alpha, beta and gamma changes

For a parent nuclide ^A_ZX:

Alpha decay ^A_ZX → ^(A-4)_(Z-2)Y + ⁴₂He

Beta (β−) decay ^A_ZX → ^A_(Z + 1)Y + ⁰₋₁e

Gamma emission ^A_ZX* → ^A_ZX + ⁰₀γ

Gamma often happens after alpha or beta when the nucleus has excess energy.

In beta-minus decay, a neutron in the nucleus changes into a proton and a beta-minus particle is emitted. This explains why A is unchanged while Z increases by one. At this level, balance the stated nuclear equation using A and Z; additional particles used in more advanced models are outside this calculation method.

Link

Properties (penetrating/ionising/deflection): Alpha/Beta/Gamma Characteristics.

B. Background radiation and net count-rate

Background radiation is present even when the test source is removed. Sources include cosmic rays and radioactive materials in rocks, air and building materials. A GM tube records source contribution + background, so use:

net count-rate = measured count-rate-background count-rate

4. Common Mistakes

  • Saying decay is “caused by heating/pressure” (it is not).
  • Forgetting gamma does not change A or Z.
  • Mixing up alpha vs beta changes (alpha: A-4, Z-2; beta: A same, Z + 1).
  • Saying random means the sample has no predictable pattern. Individual decays are unpredictable, but a large population follows a predictable statistical trend.

5. Exam Tips

  1. Use the keywords: random, spontaneous, not affected by external conditions.
  2. For decay equations: conserve both A and Z.
  3. For GM tube questions: subtract background for net count-rate.

6. Worked Examples

Modelled example 1

Net count-rate

Core

Problem

Background is 35 cpm. With a source present, the meter reads 215 cpm. Find the source’s net count-rate.
Study the worked solution
  1. Identify the measured total

    Method

    Recognise that 215 cpm includes source and background.

    Reason

    The detector records environmental background even with the source present.

    Working

    Measured = source contribution + background.
  2. Subtract background

    Method

    Subtract 35 from 215.

    Reason

    This isolates the count-rate attributable to the source.

    Working

    net rate = 215-35 = 180 cpm

Guided practice 2

Identify the decay

About 4 min

Problem

After a decay, daughter A is 4 lower and daughter Z is 2 lower than the parent. Identify the emitted radiation.

Match both nuclear-number changes

Hints

Hint 1: particle values
The emitted particle must carry A = 4 and Z = 2.
Hint 2: identity
⁴₂He is an alpha particle.
View solution step by step
  1. Infer the missing particle

    Method

    Identify alpha radiation.

    Reason

    An alpha particle carries away two protons and two neutrons.

    Working

    Δ A = -4, Δ Z = -2 ⇒ ⁴₂He

Common misconception 3

Beta (β−) change

Find and correct the mistake

Learner response

A learner says beta-minus emission lowers the nucleus’s proton number because a negatively charged electron leaves. Diagnose the claim and state both A and Z changes.

Balance the emitted electron's Z = -1

View solution step by step
  1. Track nucleon number

    Method

    Keep A unchanged.

    Reason

    A neutron changes into a proton within the nucleus; the beta particle has A = 0.

    Working

    Δ A = 0
  2. Track proton number

    Method

    Increase daughter Z by 1.

    Reason

    The daughter plus emitted electron must retain the parent’s total Z: (Z + 1) + (-1) = Z.

    Working

    Δ Z = +1

Examiner practice 4

Complete an alpha decay equation

3 marks

Examination question

Complete ²³⁸₉₂U → ²³⁴₉₀Th + ?. Show how the missing particle is identified. [3 marks]

Balance both conserved totals

View solution step by step
  1. Find missing values

    2 marks

    Method

    Subtract daughter A and Z from parent values.

    Reason

    The missing emission completes both conserved totals.

    Working

    A = 238-234 = 4, Z = 92-90 = 2
  2. Name the emission

    1 mark

    Method

    Write an alpha particle.

    Reason

    A = 4, Z = 2 identifies a helium nucleus.

    Working

    ? = ⁴₂He

Challenge 5

Complete a beta (β−) decay equation

Minimal support

Parent–daughter transfer

Complete ²⁴₁₁Na → ²⁴₁₂Mg + ?. Infer the emission from the parent–daughter changes.

Find the particle needed to conserve A and Z

Hints

Hint 1: nucleon balance
The missing particle has A = 0.
Hint 2: proton balance
11 = 12 + Z_particle.
View solution step by step
  1. Balance the missing values

    Method

    Assign A = 0 and Z = -1 to the emission.

    Reason

    24 = 24 + 0 and 11 = 12 + (-1).

    Working

    A_particle = 0, Z_particle = -1
  2. Identify beta-minus

    Method

    Write ⁰₋₁e.

    Reason

    Those nuclear-equation values represent a beta-minus electron.

    Working

    ²⁴₁₁Na → ²⁴₁₂Mg + ⁰₋₁e

7. Mind Stretchers

Mind stretcher 1: Random but predictable?Extension

If decay is random, why can we still predict half-life behaviour for a large sample?

Show Answer

While individual nuclei decay randomly, a large sample contains many nuclei, so the average behaviour becomes predictable (a steady fraction decays per half-life).

Mind stretcher 2: Why external conditions don’t matterExtension

Radioactive decay is not affected by temperature or pressure. Why?

Show Answer

Because radioactive decay is a nuclear process inside the nucleus. Temperature, pressure and chemical reactions mainly affect electrons outside the nucleus, so they do not change the stability of the nucleus.

8. Practice and next step

Compare random trial runs and background-corrected readings in the Radioactivity & Half-Life Explorer, then study the Characteristics of Alpha, Beta and Gamma.