Measuring instruments: range and precision
Key idea: A useful measurement needs a suitable range and scale, a zero check and a careful reading. Repeats reduce random variation; timing many cycles improves a period estimate.
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Guided lessons · coming soon
Guided lesson
Guided steps
- Compare the range and smallest divisions.
- Follow how the size of each object guides your choice.
- Choose a cylinder for each volume.
- Find the division sizes, then choose the meter ranges.
- Read both ends of the rod and the bottom of the meniscus.
- Follow how to subtract a zero error.
- Subtract the empty-pan reading from the loaded reading.
- Read how to count and time complete cycles.
- Divide the total time and timing error by the cycle count.
- Compare timing errors and decide whether extra digits help.
- Find the mean time before dividing by the cycle count.
- Follow how a stack helps you measure one sheet.
- Choose an instrument and describe how to measure the sheet.
- Explain how weighing many grains helps you find a mean mass.
- Count the complete cycles, then find the period.
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ContinueA measuring tape is ideal for a bench but useless for the thickness of a wire, and a stopwatch that shows hundredths of a second cannot beat your reaction time. A good measurement starts with an instrument whose range and precision suit the job. It then depends on reading the scale correctly, checking the zero, timing many oscillations, repeating readings and measuring many items to find one.
Range and precision
Two properties decide whether an instrument suits a measurement.
- The range runs from the smallest to the largest value the instrument can measure. A 30 cm rule measures lengths up to 30 cm; a 0–1 A ammeter measures currents up to 1 A.
- The resolution describes the smallest change the instrument can distinguish. For these school instruments, compare the smallest scale division or display step: a metre rule marked in millimetres has 1 mm divisions, while the stated digital calipers change in 0.01 mm steps. Fine resolution helps you distinguish small changes. Precision is how closely repeated measurements agree; accuracy is how close a measurement is to the true value. See the measurement vocabulary’s distinction.
Choose in this order:
- Range: the range must cover the value you expect.
- Scale or display step: one division must be small compared with the value, and with any difference you need to detect.
- Practicality: the instrument must fit the object and be quick to use well.
A tape with 1 mm divisions can measure a 1.20 m bench as 1200 mm. A 1 mm division is tiny compared with this length. The same 1 mm is bigger than a wire 0.5 mm thick, so a rule cannot tell a 0.4 mm wire from a 0.6 mm one.
Instruments you should know
| Instrument | Quantity | Typical range | Typical resolution | Suits |
|---|---|---|---|---|
| Measuring tape | Length | Tens of metres | 1 mm | A room or corridor |
| Metre rule | Length | 0–100 cm | 1 mm | A few centimetres to 1 m |
| Digital calipers | Length | 0–150 mm | 0.01 mm | The diameter of a rod or marble; the inside diameter of a tube |
| Digital micrometer | Length | 0–25 mm | 0.001 mm | The diameter of a wire; the thickness of a thin sheet |
| Digital stopwatch | Time | Hours | 0.01 s shown | Timing by hand |
| Measuring cylinder | Volume | 10 cm³ to 1000 cm³ | 0.2 cm³ to 10 cm³ | A liquid; a solid, by displacement |
| Electronic balance | Mass | A few hundred grams | 0.1 g or 0.01 g | Small masses |
| Spring balance (newton meter) | Weight | 0–10 N | 0.2 N | A force or weight |
| Laboratory thermometer | Temperature | −10 °C to 110 °C | 1 °C | Liquids in the laboratory |
| Ammeter | Current | 0–1 A | 0.02 A | Current through a component |
| Voltmeter | Potential difference | 0–3 V or 0–5 V | 0.1 V | p.d. across a component |
Choose a quantity to compare its instruments.
Length4 instruments
Measuring tape
- Typical range
- Tens of metres
- Typical resolution
- 1 mm
Suits: A room or corridor
Metre rule
- Typical range
- 0–100 cm
- Typical resolution
- 1 mm
Suits: A few centimetres to 1 m
Digital calipers
- Typical range
- 0–150 mm
- Typical resolution
- 0.01 mm
Suits: The diameter of a rod or marble; the inside diameter of a tube
Digital micrometer
- Typical range
- 0–25 mm
- Typical resolution
- 0.001 mm
Suits: The diameter of a wire; the thickness of a thin sheet
Time1 instrument
Digital stopwatch
- Typical range
- Hours
- Typical resolution
- 0.01 s shown
Suits: Timing by hand
Volume1 instrument
Measuring cylinder
- Typical range
- 10 cm³ to 1000 cm³
- Typical resolution
- 0.2 cm³ to 10 cm³
Suits: A liquid; a solid, by displacement
Mass1 instrument
Electronic balance
- Typical range
- A few hundred grams
- Typical resolution
- 0.1 g or 0.01 g
Suits: Small masses
Weight1 instrument
Spring balance (newton meter)
- Typical range
- 0–10 N
- Typical resolution
- 0.2 N
Suits: A force or weight
Temperature1 instrument
Laboratory thermometer
- Typical range
- −10 °C to 110 °C
- Typical resolution
- 1 °C
Suits: Liquids in the laboratory
Current1 instrument
Ammeter
- Typical range
- 0–1 A
- Typical resolution
- 0.02 A
Suits: Current through a component
Potential difference1 instrument
Voltmeter
- Typical range
- 0–3 V or 0–5 V
- Typical resolution
- 0.1 V
Suits: p.d. across a component
The ranges and resolutions are typical values. Read them from the instrument you actually use.
Worked example 1
Choose and justify an instrument
Problem
Choose an instrument for each measurement and explain why: the length of a laboratory bench, about 1.5 m; the diameter of a marble, about 16 mm; the diameter of a copper wire, about 0.3 mm; 8 cm³ of a liquid.
Show full solution
Bench, about 1.5 m
Method
Choose a measuring tape.Reason
Its range of tens of metres covers 1.5 m in one go, and 1 mm is tiny compared with 1500 mm.Working
Answer
A 30 cm rule would have to be laid down five times end to end, adding a reading error each time.
Marble, about 16 mm
Method
Choose digital calipers.Reason
16 mm is inside their range, and 0.01 mm is small compared with 16 mm.Working
Answer
A rule’s 1 mm division is one-sixteenth of the diameter, and a rule is hard to line up with a curved surface.
Copper wire, about 0.3 mm
Method
Choose a digital micrometer.Reason
Its 0.001 mm display step gives a reading such as 0.312 mm.Working
Answer
Calipers would give only 0.31 mm, and a rule could not measure it at all.
8 cm³ of a liquid
Method
Choose a 10 cm³ measuring cylinder with 0.2 cm³ divisions.Reason
It covers 8 cm³, and 0.2 cm³ is small compared with 8 cm³.Working
Answer
A 100 cm³ cylinder with 1 cm³ divisions also covers 8 cm³ but has coarser divisions.
Check each choice
Working
Answer
Each instrument’s range includes the value, and its resolution is small compared with the value.
More digits do not make a reading correct. A precise instrument that is not zeroed gives readings that are precise but wrong.
Check your understanding 1 Choose a measuring cylinder
You have three measuring cylinders: 25 cm³ with 0.5 cm³ divisions, 100 cm³ with 1 cm³ divisions and 250 cm³ with 2 cm³ divisions. Which gives the finest reading in one fill for (a) 20 cm³ of water and (b) 180 cm³ of water?
Show answer
(a) The 25 cm³ cylinder: it covers 20 cm³, and 0.5 cm³ is finer than 2 cm³. (b) The 250 cm³ cylinder: 180 cm³ does not fit in the 25 cm³ cylinder, and filling it eight times would add a reading error each time.
Choosing a meter range
Many ammeters and voltmeters have more than one range. Suppose an analogue ammeter has a 0–1 A range and a 0–5 A range, each with 50 divisions across its scale.
- On 0–1 A, one division is 1 ÷ 50 = 0.02 A.
- On 0–5 A, one division is 5 ÷ 50 = 0.1 A.
To measure a current of about 0.35 A, both ranges cover it, but the 0–1 A range reads it to 0.02 A instead of 0.1 A, so choose 0–1 A. If you do not know the current, start on the largest range and switch down once you see the reading fits. A current larger than the range sends the pointer off the scale and can damage the meter.
Choose a voltmeter range the same way. For the p.d. across a 1.5 V cell, a 0–3 V range covers it; if the 0–3 V and 0–5 V scales have the same number of divisions, the 0–3 V divisions are smaller, so choose 0–3 V.
Check your understanding 2 Select and switch meter ranges
A voltmeter has 0–3 V, 0–6 V and 0–15 V ranges, each with 30 divisions. The p.d. across a component is unknown. Find the size of one division on the 0–3 V and 0–15 V ranges. Which range do you start on? The reading is 2.4 V: what do you do next, and why?
Show answer
One division is 3 ÷ 30 = 0.1 V on 0–3 V and 15 ÷ 30 = 0.5 V on 0–15 V. Start on 0–15 V, in case the p.d. is large. 2.4 V fits the 0–3 V range, so switch to it: it reads to 0.1 V instead of 0.5 V.
Read the scale correctly
A reading is only as good as the way it is taken. The end of a rule is often worn, so the rod below is lined up with a clear mark instead of the end.
The left end is at 2.0 cm and the right end is at 7.6 cm, so the rod is 7.6 - 2.0 = 5.6 cm long. The rule’s smallest division is 1 mm = 0.1 cm, so the length is recorded to 0.1 cm: 5.6 cm, or 56 mm. Reading only the right end would give 7.6 cm, too long by the 2.0 cm before the rod starts.
Look straight at each mark. Looking from one side makes the mark appear to move against the scale; this is parallax error.
In this cylinder, the labelled marks are 10 cm³ apart with five spaces between each pair, so one small division is 10 ÷ 5 = 2 cm³. Water curves up at the walls. Read the bottom of the curved surface, the meniscus, with your eye level with it: it is three small divisions above 30, so the volume is 30 + 3 × 2 = 36 cm³.
Read a thermometer the same way: keep the bulb in the liquid, stir, and read with your eye level with the end of the liquid thread.
Check the zero
Before you measure, check what the instrument reads when it measures nothing: calipers or micrometer closed, balance empty, spring balance hanging unloaded. If it does not read zero, it has a zero error, and every reading is shifted by that amount.
Reset it to zero if you can. Otherwise, correct each reading:
Worked example 2
Correct a zero error
Problem
Digital calipers read 0.03 mm with the jaws closed. On a metal rod they read 8.27 mm. Find the diameter of the rod.
Show full solution
Identify the zero error
Method
Read the display with the jaws closed.Reason
Every reading includes this offset.Working
Answer
Zero error = +0.03 mm, so every reading is 0.03 mm too large.
Correct the reading
Method
Subtract the zero error.Reason
Corrected reading = observed reading − zero error.Working
Answer
8.27 - 0.03 = 8.24 mm
Report it
Working
Answer
In metres, since 1 mm = 10⁻³ m, the diameter is 8.24 × 10⁻³ m. Keep the unit and record digits consistent with the stated instrument’s display step.
A zero error can be negative. A spring balance whose pointer rests at −0.2 N when unloaded reads 3.4 N with a load. The corrected weight is 3.4 - (-0.2) = 3.6 N: subtracting a negative zero reading adds to the reading.
Check your understanding 3 Correct the balance reading
An empty balance reads 0.4 g. With a stone on it, it reads 25.7 g. Find the mass of the stone to the nearest 0.1 g.
Show answer
25.7 - 0.4 = 25.3 g.
Time many oscillations, not one
One complete oscillation of a pendulum is a swing from one side to the other and back. The time for one oscillation is the period.
A digital stopwatch may display 0.01 s steps, but hand-trigger variation is often much larger. Follow the recording convention in your practical task, and use repeats to assess the variation. The last displayed digit may change because of your reaction time.
A pendulum with a period of about 1.8 s shows the problem. A 0.2 s timing error is more than a tenth of a single period. So time many oscillations and divide.
Worked example 3
Period from twenty oscillations
Problem
Twenty oscillations take 36.4 s. Find the period, and the effect of a 0.2 s timing error.
Show full solution
Find the period
Method
Divide the total time by the number of oscillations.Reason
One period is the time for one oscillation.Working
Answer
36.4 ÷ 20 = 1.82 s
Spread the timing error
Working
Answer
The same 0.2 s timing error is spread over 20 periods: it becomes 0.2 ÷ 20 = 0.01 s in the period.
Start the stopwatch as the bob passes the centre in a stated direction, counting that pass as “zero”. Count one complete oscillation each time it returns through the centre in the same direction. A pass in the opposite direction occurs only halfway through the cycle. The bob moves fastest at the centre, making the crossing easier to judge.
Check your understanding 4 Compare timing methods
A student can either time one pendulum oscillation, about 1.5 s, or time ten oscillations, about 15 s. The total timing error is about 0.2 s in either method. Compare the error in the period found by each method. Would a stopwatch with more display digits remove this error?
Show answer
Timing one oscillation gives an error of about 0.2 s in the period. Timing ten and dividing by ten gives an error of about 0.2 ÷ 10 = 0.02 s in the period, ten times smaller. More display digits would not remove the error because it comes from starting and stopping the stopwatch by hand.
Repeat readings and take the mean
Readings of the same quantity differ a little each time: your timing varies, and a wire is never perfectly round. Take each reading at least three times and use the mean:
Worked example 4
Mean of repeated timings
Problem
A student times 20 oscillations three times: 36.2 s, 36.6 s and 36.5 s. Find the period.
Show full solution
Find the mean time
Method
Add the readings and divide by 3.Reason
Repeating and averaging reduces the effect of random timing errors.Working
Answer
(36.2 + 36.6 + 36.5) ÷ 3 = 36.4 s, to 0.1 s like the readings
Find the period
Working
Answer
36.4 ÷ 20 = 1.82 s
Before averaging, compare the readings. If a fourth reading were 34.6 s, it would be about one period short of the others, which suggests a miscounted oscillation. Check the count and repeat the measurement. Keep the original reading and record the investigation; do not exclude it merely because it differs. Exclude a reading only when the investigation identifies an error, such as an observed miscount.
For a wire, measure the diameter at several places along it and in two directions at right angles. Readings of 0.452 mm, 0.448 mm and 0.455 mm give a mean of 1.355 ÷ 3 = 0.452 mm.
Measure many to find one
When one item is too small compared with the instrument’s scale or display step, measure many comparable items together, then divide to estimate a typical item.
Worked example 5
The thickness of one sheet of paper
Problem
Find the thickness of one sheet of paper with a metre rule.
Show full solution
Decide whether to measure directly
Method
Compare the sheet with the rule’s smallest division.Reason
One sheet is much thinner than 1 mm, so it cannot be measured directly.Working
Answer
Measure a stack instead
Measure a stack
Method
Press 200 sheets flat and measure them.Reason
A thick stack is many divisions long, so the reading is precise.Working
Answer
2.0 cm = 20 mm
Divide
Working
Answer
One sheet = 20 ÷ 200 = 0.10 mm = 1.0 × 10⁻⁴ m, which matches the order of magnitude of a sheet of paper.
The same idea works on a balance: 50 identical paper clips with a mass of 23.5 g have a mass of 23.5 ÷ 50 = 0.47 g each.
Some quantities are worked out from other measurements. The volume of an irregular stone is found by displacement: water in a measuring cylinder reads 50 cm³, and 62 cm³ with the stone fully under water, so the stone’s volume is 62 - 50 = 12 cm³.
Check your understanding 5 Measure a thin sheet
You need the thickness of a thin aluminium sheet, about 0.2 mm, as reliably as you can. Choose the instrument, justify it by range and precision, and say how you would take the readings.
Show answer
Use a digital micrometer. Its range, 0–25 mm, covers 0.2 mm, and its resolution, 0.001 mm, is small compared with 0.2 mm. The stated calipers’ 0.01 mm step would be a twentieth of the thickness, and a metre rule’s 1 mm division is larger than the sheet.
Close the micrometer and check that it reads zero; correct any zero error. Close it gently on the sheet, then repeat at several places across the sheet. Take the mean.
Check your understanding 6 Weigh a counted sample
A grain of rice has a mass of about 0.02 g, and your balance reads to 0.1 g. Explain why weighing one grain is not good enough, and describe a better method.
Show answer
One grain, about 0.02 g, is smaller than the balance’s 0.1 g display step, so a correctly zeroed display would round it to 0.0 g. Zero the balance, weigh a counted sample of many grains, such as 100, and divide. If 100 grains have a mass of 2.1 g, the mean mass per grain is 2.1 ÷ 100 = 0.021 g; real grains need not all have that mass.
Check your understanding 7 Count complete oscillations
A pendulum crosses the centre travelling right when the timer starts. The timer stops 18.0 s later at the eleventh rightward centre crossing, including the starting crossing. Find the number of complete oscillations and the period. Another learner counts every centre crossing, including leftward ones, as a full oscillation. Choose what the next leftward crossing represents.
Show the steps Optional working
Show answer
The first rightward crossing starts the first interval; the eleventh completes ten full cycles. Period = 18.0 ÷ 10 = 1.80 s. Between two rightward crossings there is a leftward crossing, only half a cycle later. Counting every centre crossing as a full oscillation doubles the count and underestimates the period. Start and finish at the same position and direction; averaging does not correct a wrong cycle count.
Challenge yourself
A digital timer shows more decimal places than a stopwatch, but both give a different mean time for the same pendulum. Design a comparison that can separate resolution, random variation and a systematic offset.
Check your thinking
Time many oscillations in repeated trials with both instruments. Compare spread for random variation, quote each resolution, and test a known interval or shared start/stop method for systematic offset. More digits alone do not establish accuracy.
Common mistakes
- Choosing the instrument with the most digits. Check that the range covers the value first, then compare its scale or display step with the value and differences to detect.
- Expecting a more precise instrument to fix a zero error. Check the zero, then reset it or subtract the zero reading.
- Adding a positive zero error. The instrument already reads too high: corrected reading = reading − zero reading.
- Treating the stopwatch’s last digit as proof of accuracy. Time several complete oscillations and repeat; the hand-trigger variation can be larger than the display step.
- Forgetting to divide by the number of oscillations or items. That gives the total, not one.
- Reading the top of the meniscus, or looking from an angle. Read the bottom of the meniscus with your eye level with it.
- Reading only the far end of an object. Subtract the start reading from the end reading.
- Starting a meter on its smallest range. Start on the largest range, then switch down.
- Deleting an unusual reading without a justified, recorded reason. Investigate and repeat; keep the original result.
Spotted an error? Report a correction
Syllabus and review details
- SEC G2 Science Physics component 2027 · 2027
Physics section, PDF pages 8–23
Last reviewed: