How To Add Forces

Key idea: Learn how to find the resultant force by adding forces in the same or opposite direction, and by using scale drawings for forces at angles (O Level Physics).

  • SEC G3 Physics 2027
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Learning objectives

  • Distinguish contact forces from non-contact forces
  • State that mass measures the amount of matter in a body
  • Describe a gravitational field as a region where a mass experiences gravitational force
  • Define gravitational field strength as gravitational force per unit mass
  • Apply weight = mass × gravitational field strength
  • Distinguish mass from weight
  • Describe the effect of balanced and unbalanced forces on a body
  • Describe ways a force may change motion
  • Identify action–reaction pairs on interacting bodies
  • Draw free-body diagrams for force systems in at most two dimensions
  • Solve three-force static equilibrium graphically
  • Apply resultant force = mass × acceleration
  • Relate mass to resistance to change in motion
  • Explain the effects of friction on motion
  • Describe falling with and without air resistance, including terminal velocity
  • Describe a moment as a force's turning effect in everyday examples
  • Apply moment = force × perpendicular distance from the pivot
  • State the principle of moments for a body in equilibrium
  • apply the principle of moments to new situations or to solve related problems
  • show an understanding that the weight of a body may be taken as acting at a single point known as its centre of gravity
  • Explain qualitatively how centre-of-gravity position affects stability

1. Definition

A. Resultant force

The resultant force is the single force that has the same effect as two or more forces acting together on an object.

Since force is a vector, you must combine forces using magnitude and direction.

2. Key Ideas

  • Force is a vector, so you must state the direction (e.g. “20 N to the right”).
  • For forces in a straight line (1D), choose a positive direction and add using signs:
    • Fᵣₑₛᵤₗₜₐₙₜ = ∑ F
  • If forces act in the same direction, the resultant is the sum of magnitudes.
  • If forces act in opposite directions, the resultant is the difference, in the direction of the larger force.
  • For forces at an angle (2D), use a scale drawing (triangle or parallelogram method) and measure the resultant.
  • Resultant force = 0 means forces are balanced (object at rest or moving with constant velocity).
Exam workflow (resultant force)
  1. Sketch the forces and label directions clearly.
  2. 1D: choose a positive direction and add forces with signs.
  3. 2D: state a scale, draw vectors to scale (head-to-tail or parallelogram), then measure.
  4. Give the magnitude and direction of the resultant (with units).

Resultant depends on the angle between forces

Resultant force magnitude versus the angle between two equal forces (10 N each).

Scroll across the graph to read all labels.

Resultant force magnitude versus the angle between two equal forces (10 N each).Resultant force magnitude versus the angle between two equal forces (10 N each).
Same magnitudes can give very different resultants. 0° adds, 180° cancels, 90° gives a diagonal (Pythagoras).
Open full-size graph
View figure data
Values for Resultant depends on the angle between forces
Angle between two equal forces (°)F1 = F2 = 10 N
020
3019.32
6017.32
9014.14
12010
1505.18
1800

3. Detailed Explanations

A. Why we use resultant force

When several forces act on an object, we often replace them with one force: the resultant.

This matters because motion depends on the resultant force:

  • if forces are balanced (Fᵣₑₛᵤₗₜₐₙₜ = 0), there is no acceleration
  • if forces are unbalanced, the object accelerates (see Unbalanced Force)

B. Forces in the same line (1D): same direction

If forces are along the same straight line and point the same way, add the magnitudes.

Example: 10 N right and 20 N right gives 30 N right.

C. Forces in the same line (1D): opposite directions

If forces oppose each other, subtract the magnitudes. The resultant is in the direction of the larger force.

Example: 40 N right and 20 N left gives 20 N right.

Resultant forces in one and two dimensionsThree labelled cases compare forces in the same direction, forces in opposite directions, and two perpendicular forces. Each case shows the direction and magnitude of the resultant.Resultant-force casesSame direction10 N20 Nresultant 30 NOpposite directions40 N20 Nresultant 20 NPerpendicular forces4 N east3 N northresultant 5 Nnorth-east
Scroll diagram horizontally to read all labels.
Add collinear forces with signs. For forces at an angle, preserve both magnitude and direction in a scale drawing.

D. Using signs (quick method for 1D)

Choose a positive direction (e.g. right is positive). Then:

  • rightward force: + F
  • leftward force: -F

Example: + 40 + (-20) = +20 N (so 20 N to the right).

E. Forces at an angle (2D): scale drawing

When forces are at an angle, you cannot add or subtract magnitudes directly. Use a scale drawing (graphical vector addition).

Workflow:

  1. Choose a scale (e.g. 1 cm represents 5 N).
  2. Draw the first force as an arrow to scale.
  3. Draw the second force as an arrow to scale in the correct direction.
  4. Use either method:
    • triangle method (head-to-tail), or
    • parallelogram method (complete the parallelogram).
  5. Draw the resultant from the start point to the end point, and measure its length (then convert using the scale).
Head-to-tail addition of perpendicular vectorsA 4 metre arrow points east. From its head, a 3 metre arrow points north. The resultant points from the original tail to the final head and is labelled 5 metres at 37 degrees north of east.Head-to-tail method4 m east3 m northresultant: 5 m37° north of east37°startfinishscale: 1 cm : 1 m
Scroll diagram horizontally to read all labels.
Using a scale of 1 cm to 1 m, draw 4 cm east and then 3 cm north. The measured resultant should be about 5 cm at 37° north of east.
Parallelogram addition of two equal vectorsTwo 5 newton arrows share a tail. One points east and one points 60 degrees north of east. Dashed parallel lines complete a parallelogram, and its diagonal is labelled as the 8.7 newton resultant at 30 degrees north of east.Parallelogram method5 N east5 N at 60°north of eastresultant: 8.7 N30° north of east60°
Scroll diagram horizontally to read all labels.
For two equal 5 N vectors separated by 60°, the parallelogram diagonal gives a resultant of about 8.7 N at 30° north of east.

F. Special case: forces at 90°

If two forces are perpendicular, the vector diagram forms a right-angled triangle, so you can use Pythagoras’ theorem for the magnitude:

Fᵣₑₛᵤₗₜₐₙₜ = square root of (F₁² + F₂²)

4. Common Mistakes

  • Adding magnitudes even when forces are in opposite directions.
  • Giving a force value without a direction (e.g. writing “20 N” when “20 N to the right” is needed).
  • Sign mistakes in 1D (choosing right as positive but treating a leftward force as positive).
  • Drawing an inaccurate scale diagram (no scale stated, ruler not used, wrong angles).
  • Treating “resultant force” as an extra force on the diagram (it replaces the forces).

5. Exam Tips

  • Start with a quick sketch showing force directions.
  • For 1D questions, state the sign convention (e.g. “right is positive”) and show the signed sum.
  • For 2D graphical questions:
    • state your scale
    • use a ruler/protractor
    • give the magnitude and direction of the resultant (if asked)
  • If the object is at rest or moves with constant velocity, write: Fᵣₑₛᵤₗₜₐₙₜ = 0 (balanced forces).

6. Worked Examples

Modelled example 1

Same direction (1D)

Core

Problem

A tug-of-war rope is pulled by 12 N to the right and 8.0 N to the right. Find the resultant force.
Study the worked solution
  1. Choose a sign convention

    Method

    Take right as positive.

    Reason

    A declared convention makes every collinear force’s direction explicit.

    Working

    right = +
  2. Add signed forces

    Method

    The signed resultant is + 20 N.

    Reason

    Both forces point in the chosen positive direction.

    Working

    Fᵣₑₛᵤₗₜₐₙₜ = +12 + (+8.0) = +20 N
  3. Interpret the sign

    Method

    The resultant is 20 N to the right.

    Reason

    The positive result points in the declared positive direction.

    Working

    + 20 N ⇒ 20 N right

Guided practice 2

Opposite directions (1D)

About 4 min

Problem

Two forces act on a trolley: 40 N to the right and 25 N to the left. Find the resultant force.

Try this before viewing the solution

Unit: N
Resultant direction

Hints

Hint 1: declare positive right
Represent the leftward force as a negative component.
View solution step by step
  1. Write signed components

    Method

    The forces are + 40 N and -25 N.

    Reason

    Right is chosen positive and left negative.

    Working

    F₁ = +40 N; F₂ = -25 N
  2. Add the components

    Method

    Fᵣₑₛᵤₗₜₐₙₜ = +15 N.

    Reason

    A resultant is the vector sum, not the sum of both magnitudes.

    Working

    Fᵣₑₛᵤₗₜₐₙₜ = +40 + (-25) = +15 N
  3. State direction

    Method

    The resultant is 15 N to the right.

    Reason

    The signed result is positive.

    Working

    + 15 N ⇒ 15 N right

Common misconception 3

Perpendicular forces (use Pythagoras for magnitude)

Find and correct the mistake

Learner claim

Two perpendicular forces act on a point: 3.0 N east and 4.0 N north. A learner adds their magnitudes to obtain 7.0 N. Diagnose the method and find the correct resultant magnitude.

Try this before viewing the solution

Correct method
Unit: N

View solution step by step
  1. Diagnose the addition

    Method

    Directly adding 3.0 + 4.0 treats the forces as parallel in the same direction.

    Reason

    The stated forces are perpendicular, so their vector triangle is two-dimensional.

    Working

    3.0 N⊥4.0 N
  2. Use the right triangle

    Method

    Apply Pythagoras to the perpendicular components.

    Reason

    The resultant is the hypotenuse of the vector triangle.

    Working

    Fᵣₑₛᵤₗₜₐₙₜ = square root of (3.0² + 4.0²)
  3. Calculate

    Method

    The resultant magnitude is 5.0 N.

    Reason

    9 + 16 = 25 and square root of 25 = 5.

    Working

    Fᵣₑₛᵤₗₜₐₙₜ = 5.0 N

Examiner practice 4

Three forces in a straight line (signs)

3 marks

Examination question

Three collinear forces act on a point: 3.0 N right, 1.5 N left and 2.0 N left. Find the resultant force. [3 marks]

Try this before viewing the solution

Unit: N
Resultant direction

View solution step by step
  1. State the convention

    1 mark

    Method

    Take right as positive.

    Reason

    The two leftward forces then carry negative signs.

    Working

    right = +; left = -
  2. Sum the forces

    1 mark

    Method

    The signed resultant is -0.5 N.

    Reason

    All three signed components must be included.

    Working

    Fᵣₑₛᵤₗₜₐₙₜ = +3.0 + (-1.5) + (-2.0) = -0.5 N
  3. Report the vector

    1 mark

    Method

    The resultant is 0.5 N left.

    Reason

    The negative sign points opposite the chosen positive direction.

    Working

    -0.5 N ⇒ 0.5 N left

Challenge 5

Perpendicular forces (magnitude and direction)

Minimal support

Independent transfer

Two perpendicular forces act on a point: 5.0 N east and 12 N north. Find the magnitude and direction of the resultant force.

Try this before viewing the solution

Unit: N
Unit: °

Hints

Hint 1: draw the component triangle
Put 5.0 N on the eastward leg and 12 N on the northward leg.
View solution step by step
  1. Find the magnitude

    Method

    Fᵣₑₛᵤₗₜₐₙₜ = 13 N.

    Reason

    The two perpendicular forces are the legs of a right triangle.

    Working

    Fᵣₑₛᵤₗₜₐₙₜ = square root of (5.0² + 12²) = 13 N
  2. Choose the reference direction

    Method

    Measure θ north of east.

    Reason

    The eastward component is adjacent and the northward component is opposite for that angle.

    Working

    tan θ = Fₙₒᵣₜₕ/Fₑₐₛₜ
  3. Calculate and state the vector

    Method

    The resultant is about 13 N at 67° north of east.

    Reason

    tan⁻¹ (12/5.0) = 67.4°.

    Working

    θ = tan⁻¹ (12/5.0) ≈ 67°

7. Mind Stretchers

Mind stretcher 1: Find the force needed to balance (resultant = 0)Extension

Two forces act on a box: 10 N to the right and 6.0 N to the right.

What single force must you add to make the resultant force zero?

Show Answer

Current resultant is 16 N to the right, so you need 16 N to the left to balance it.

A 2.0 kg trolley is pulled with 9.0 N to the right. Friction is 3.0 N to the left.

Find the acceleration.

Show Answer

Resultant force:

Fᵣₑₛᵤₗₜₐₙₜ = 9.0-3.0 = 6.0 N to the right

Using F = ma:

a = F/m = 6.0/2.0 = 3.0 m s⁻²

Continue with the next resource in this course.

Course and syllabus information
Course
SEC G3 Physics
Edition
SEC G3 Physics 2027