Balanced Forces and Newton's First Law

Key idea: Use one-body force diagrams and resultants to explain rest and constant velocity with Newton's first law.

  • SEC G3 Physics 2027
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Learning objectives

  • Distinguish contact forces from non-contact forces
  • State that mass measures the amount of matter in a body
  • Describe a gravitational field as a region where a mass experiences gravitational force
  • Define gravitational field strength as gravitational force per unit mass
  • Apply weight = mass × gravitational field strength
  • Distinguish mass from weight
  • Describe the effect of balanced and unbalanced forces on a body
  • Describe ways a force may change motion
  • Identify action–reaction pairs on interacting bodies
  • Draw free-body diagrams for force systems in at most two dimensions
  • Solve three-force static equilibrium graphically
  • Apply resultant force = mass × acceleration
  • Relate mass to resistance to change in motion
  • Explain the effects of friction on motion
  • Describe falling with and without air resistance, including terminal velocity
  • Describe a moment as a force's turning effect in everyday examples
  • Apply moment = force × perpendicular distance from the pivot
  • State the principle of moments for a body in equilibrium
  • apply the principle of moments to new situations or to solve related problems
  • show an understanding that the weight of a body may be taken as acting at a single point known as its centre of gravity
  • Explain qualitatively how centre-of-gravity position affects stability

Retrieve: isolate one body

Before using Newton’s first law, sketch the free-body diagram of a book resting on a table. Include only external forces on the book. Check your force selection in Free Body Diagrams if needed.

The forces are Earth’s gravitational force on the book (weight) downward and the table’s normal force on the book upward. Do not add motion or resultant as extra forces.

One body, one resultant

Forces on a body are balanced when their vector resultant is zero:

Fᵣₑₛᵤₗₜₐₙₜ = 0 ⇒ a = 0.

Newton’s first law says that the selected body therefore remains at rest or continues with constant velocity. Constant velocity means constant speed in a straight line. A body moving around a curve changes direction, so it is accelerating even if its speed is constant.

Equal and opposite forces on a blockA block has an equal-sized horizontal force to the right and to the left. The two forces give zero resultant force.FFresultant force = 0
The two horizontal forces act on the same selected body and have zero resultant.

Balanced forces: velocity does not change

Velocity–time graph examples for balanced forces: at rest (v = 0) and constant non-zero velocity.

Scroll across the graph to read all labels.

Velocity–time graph examples for balanced forces: at rest (v = 0) and constant non-zero velocity.Velocity–time graph examples for balanced forces: at rest (v = 0) and constant non-zero velocity.
If the resultant force is zero, acceleration is zero, so velocity is constant (it can be zero or non-zero).
Open full-size graph
View figure data
Values for Balanced forces: velocity does not change
Time (s)At restConstant velocity
005
805

Modelled example: box at rest

Forces on a box at rest on a tableA box rests on a horizontal table. The upward normal contact force and downward weight are equal and opposite.normal contact force, Nweight, Wtable
Weight and normal force both act on the box. They can balance without being a Newton's third-law pair.

Modelled example 1

A box at rest on a table

Core

Problem

A box of weight 24 N rests on a horizontal table. Find the table’s normal force on the box.
Study the worked solution
  1. Select the body

    Method

    Analyse the box only.

    Reason

    Its vertical forces are weight down and normal force up.

    Working

    Take upward as positive: Fᵣₑₛᵤₗₜₐₙₜ = N-24.
  2. Use zero acceleration

    Method

    Set the resultant to zero.

    Reason

    The box remains at rest.

    Working

    N-24 = 0, so N = 24 N upward.

Guided practice: constant velocity

Guided practice 2

A cart moves without changing velocity

About 5 min

Problem

A cart moves east at constant 3.0 m s⁻¹. Resistance is 5.0 N west. Find the driving force and resultant.

Use velocity before force

Unit: N
Unit: N

Hints

Hint 1: translate motion
Constant velocity means acceleration is zero.
Hint 2: balance components
The eastward component must balance 5.0 N west.
View solution step by step
  1. Apply Newton's first law

    Method

    Use a = 0, so Fᵣₑₛᵤₗₜₐₙₜ = 0.

    Reason

    A moving body does not need a forward resultant to keep moving.

    Working

    The driving force is 5.0 N east and the resultant is 0 N.

Misconception repair

  • “It moves forward, so the resultant is forward.” No. The direction of velocity does not determine the resultant. Only changing velocity requires a resultant.
  • “Balanced means no forces act.” No. Several real forces may act and add vectorially to zero.
  • “Constant speed means balanced.” Only if direction is also constant. Uniform circular motion has changing velocity.

Changed-context transfer

Challenge 3

A parachutist at terminal velocity

Minimal support

Problem

A parachutist descends vertically at constant velocity. Weight is 720 N. State the air resistance and explain the motion.

Analyse the parachutist only

Hints

Hint 1: translate motion
Constant velocity means zero acceleration, even during a descent.
Hint 2: balance the body
Apply the zero-resultant condition to the forces on the parachutist.
View solution step by step
  1. Balance the vertical forces

    Method

    Air resistance is 720 N upward.

    Reason

    The two forces on the parachutist give zero resultant.

    Working

    Acceleration is zero, so the downward velocity remains constant.

Independent evidence

Without hints, analyse a train moving east around a curve at constant speed. Decide whether the resultant is zero and justify your answer using velocity rather than speed alone. Then compare it with the straight-track constant-velocity cart above.

Check your reasoning

The train’s velocity changes direction, so it accelerates and its resultant is not zero. The straight-track cart has constant velocity, zero acceleration and zero resultant.

Next, practise separating one-body resultants from cross-body interaction pairs in Newton’s Third-Law Interaction Pairs.

Continue with the next resource in this course.

Course and syllabus information
Course
SEC G3 Physics
Edition
SEC G3 Physics 2027