Hydrostatic pressure

Key idea: Learn hydrostatic pressure for O Level Physics: use p = ρgh, distinguish column and total pressure, avoid depth errors, and practise worked examples.

  • SEC G3 Physics 2027
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Learning objectives

  • Define pressure as force per unit area
  • Apply pressure = force ÷ area
  • Explain pressure transmission in a hydraulic press
  • Apply density = mass ÷ volume
  • Apply liquid-column pressure = height × density × gravitational field strength
  • Explain how liquid-column height measures atmospheric pressure
  • Explain how a manometer measures pressure difference

1. Definition

A. Hydrostatic pressure

Hydrostatic pressure is the pressure in a fluid at rest, caused by the weight of the fluid above a point. It increases with depth.

B. Pressure due to a liquid column

The pressure difference between two points in the same fluid separated vertically by Δ h is:

Δ p = ρ g Δ h

If the fluid surface is at pressure p₀, then at depth h:

p = p₀ + ρ gh

In many O Level questions, p = ρ gh refers to the pressure due to the liquid column: the extra pressure compared with the surface. This is also called gauge pressure when the surface is open to the atmosphere.

2. Key Ideas

  • Hydrostatic pressure depends on:
    • depth h,
    • fluid density ρ,
    • gravitational field strength g.
  • For the same liquid and same g:
    • deeper point → larger pressure (because p ∝ h),
    • same depth → same pressure (even if the container shape is different).
  • Hydrostatic pressure does not depend on the shape or cross-sectional area of the container.
  • Use the vertical depth from the surface:
    • p = ρ gh
    • Δ p = ρ g Δ h
  • If asked for total pressure at depth in an open tank:
    • pₜₒₜₐₗ = pₐₜₘ + ρ gh

3. Detailed Explanations

A. Why pressure increases with depth

Liquid pressure increases with vertical depthAn open tank contains liquid. Points A, B, and C lie at increasing vertical depths. Pressure arrows grow longer with depth, and arrows around point B show that pressure acts in every direction.Open liquid surfacehvertical depthABClarger pressurepressure actsin all directionspcolumn = ρgh
Scroll diagram horizontally to read all labels.
Depth is measured vertically from the liquid surface. At greater depth, the pressure is larger; at one point, liquid pressure acts in every direction.

The deeper you go in a liquid, the more liquid there is above you.

  • more water above → larger weight pressing down
  • larger weight over the same area → larger pressure

B. Using p = ρ gh (what is h?)

For a point at depth h below the surface in a uniform liquid:

p_column = ρ gh

If the surface is open to the air, the total pressure is:

pₜₒₜₐₗ = pₐₜₘ + ρ gh

Column pressure vs total pressure (open tank)

Two straight lines versus depth: one shows pressure due to the water column only; the other includes atmospheric pressure as a constant offset.

Scroll across the graph to read all labels.

Two straight lines versus depth: one shows pressure due to the water column only; the other includes atmospheric pressure as a constant offset.Two straight lines versus depth: one shows pressure due to the water column only; the other includes atmospheric pressure as a constant offset.
Illustrative values for water using ρ = 1000 kg m⁻³, g = 10 N kg⁻¹ and atmospheric pressure = 100 kPa. Both lines have the same gradient; atmospheric pressure adds a constant 100 kPa.
Open full-size graph
View figure data
Values for Column pressure vs total pressure (open tank)
Depth below surface (m)Column pressure (ρgh) in waterTotal pressure (patm + ρgh)
00100
660160

C. Same depth means same pressure (shape does not matter)

Same depth gives the same liquid pressureThree differently shaped open containers hold the same liquid to the same surface level. Points A, B, and C are aligned at the same vertical depth and have equal pressure.Same liquid and same surface pressureABChpA = pB = pC
Scroll diagram horizontally to read all labels.
For the same liquid, gravitational field strength, surface pressure and vertical depth, container shape does not change the pressure at A, B or C.

In a liquid at rest:

  • all points at the same depth have the same pressure
  • the pressure at the bottom depends on depth h, not on the container’s shape or width

D. Pressure acts in all directions

Pressure at a point in a fluid acts in all directions (not just downward). This is why water pushes:

  • downward on the bottom of a tank,
  • sideways on the walls of a tank.

4. Common Mistakes

  • Using the wrong h (it must be the vertical depth below the surface, not the slanted distance).
  • Forgetting to convert cm to m (e.g. 35 cm = 0.35 m).
  • Mixing density units (use kg m⁻³ when using SI units in the formula).
  • Forgetting to add atmospheric pressure when the question asks for total pressure.

5. Exam Tips

  • Write the formula first (p = ρ gh or Δ p = ρ gΔ h), then substitute with units.
  • Quote the correct unit at the end: Pa (or kPa).
  • For water, a common value is ρ = 1000 kg m⁻³.
  • If two points are at the same depth in the same connected liquid, state: “same h → same pressure”.

6. Worked Examples

Modelled example 1

Diver underwater (column pressure and total pressure)

Core

Problem

A diver is 6.0 m below the surface of fresh water. Calculate:

  1. the pressure due to the water column;
  2. the total pressure if atmospheric pressure is 1.0 × 10⁵ Pa.

Take ρ_water = 1000 kg m⁻³ and g = 10 N kg⁻¹.

Study the worked solution
  1. Identify the pressure requested first

    Method

    Calculate the extra pressure produced by the water column.

    Reason

    The first part excludes atmospheric pressure, so use p_column = ρ gh.

    Working

    p_column = (1000)(10)(6.0) = 6.0 × 10⁴ Pa
  2. Add the surface pressure

    Reason

    Total pressure at the diver includes both atmospheric pressure at the surface and the water-column increase.

    Working

    pₜₒₜₐₗ = 1.0 × 10⁵ + 6.0 × 10⁴ = 1.6 × 10⁵ Pa

Guided practice 2

Pressure difference between two depths

About 4 min

Problem

Two points in the same liquid are separated vertically by 0.25 m. Find the pressure difference between them.

Take ρ = 1000 kg m⁻³ and g = 10 N kg⁻¹.

Use the vertical separation

Unit: Pa

Hints

Hint 1: choose the difference relationship
The question compares two points, so use Δ p = ρ gΔ h.
Hint 2: substitute the vertical separation
Use Δ h = 0.25 m directly because it is already a vertical SI distance.
View solution step by step
  1. Select the vertical depth difference

    Method

    Use the 0.25 m vertical separation as Δ h.

    Reason

    Hydrostatic pressure differences depend on vertical height, not on the path or container shape between the points.

    Working

    Δ h = 0.25 m
  2. Calculate the pressure difference

    Reason

    Both points are in the same liquid and share the stated g.

    Working

    Δ p = (1000)(10)(0.25) = 2.5 × 10³ Pa

Common misconception 3

Different liquids, same depth

Find and correct the mistake

Learner response

A point is 0.40 m below the surface of water (ρ = 1000 kg m⁻³) and another point is 0.40 m below the surface of oil (ρ = 800 kg m⁻³). Take g = 10 N kg⁻¹.

A student writes: The points are at the same depth, so the two liquid-column pressures must be equal.

Locate the first error and calculate both pressures.

Diagnose the same-depth claim

What has the student ignored?
Unit: Pa
Unit: Pa

View solution step by step
  1. Locate the missing variable

    Method

    Compare density as well as depth.

    Reason

    The relationship p = ρ gh contains both h and ρ; equal depth alone is insufficient for different liquids.

    Working

    Water is denser than oil: 1000 > 800 kg m⁻³.
  2. Calculate the water pressure

    Reason

    Use the water density at the common depth.

    Working

    p_water = (1000)(10)(0.40) = 4.0 × 10³ Pa
  3. Calculate and compare the oil pressure

    Reason

    The lower oil density produces a smaller pressure for the same g and h.

    Working

    pₒᵢₗ = (800)(10)(0.40) = 3.2 × 10³ Pa

Examiner practice 4

Find depth from pressure

3 marks

Examination question

In water, the pressure due to the liquid column is 3.0 × 10⁴ Pa. Calculate the depth. Take ρ_water = 1000 kg m⁻³ and g = 10 N kg⁻¹. [3 marks]

Write your rearrangement and answer

View solution step by step
  1. Choose the liquid-column relationship

    1 mark

    Method

    Use p = ρ gh without adding atmospheric pressure.

    Reason

    The given pressure is explicitly due to the liquid column.

    Working

    p = ρ gh
  2. Rearrange for depth

    1 mark

    Reason

    Depth is the unknown, so divide the pressure by ρ g.

    Working

    h = p/(ρ g)
  3. Calculate the depth

    1 mark

    Reason

    The supplied quantities are in compatible SI units.

    Working

    h = (3.0 × 10⁴)/(1000)(10) = 3.0 m

Challenge 5

Find density using Δ p = ρ gΔ h

Minimal support

Reverse inference

In an unknown liquid, pressure increases by 5.0 × 10³ Pa when the depth increases by 0.50 m. Find the density of the liquid. Take g = 10 N kg⁻¹.

Infer the liquid property from pressure data

Unit: kg m⁻³

Hints

Hint 1: use differences rather than total pressure
The data give a pressure increase across a depth increase, so use Δ p = ρ gΔ h.
Hint 2: make density the subject
Divide Δ p by gΔ h.
View solution step by step
  1. Rearrange the difference relationship

    Method

    Make density the subject.

    Reason

    The pressure change, vertical separation and gravitational field strength are measured, while the liquid is unknown.

    Working

    ρ = (Δ p)/(gΔ h)
  2. Infer the density

    Reason

    The pressure increase is caused by the additional 0.50 m liquid column.

    Working

    ρ = (5.0 × 10³)/(10)(0.50) = 1000 kg m⁻³

7. Mind Stretchers

Mind stretcher 1: Same depth, different shapesExtension

Two tanks have different shapes but both contain water to the same depth. One tank is very wide and the other is narrow. Which tank has the larger pressure at the bottom? Explain.

Show Answer

They have the same pressure at the bottom.

Hydrostatic pressure depends on depth only: p = ρ gh

Same liquid (same ρ) and same depth h gives the same pressure, regardless of tank shape.

Mind stretcher 2: Pressure on a different planetExtension

A lake of the same depth exists on a planet where g is half of Earth’s value. How does the hydrostatic pressure due to the water column at a given depth compare with Earth? Explain.

Show Answer

It is half of Earth’s value.

Hydrostatic pressure due to the liquid column is: p = ρ gh

If g is halved while ρ and h are the same, then p is halved.

8. Practice and next step

Use the Pressure and hydraulics explorer to test depth, density, and vessel shape. Then continue to Hydraulic systems.

Continue with the next resource in this course.

Course and syllabus information
Course
SEC G3 Physics
Edition
SEC G3 Physics 2027