Kinematics

Key idea: Speed, velocity, acceleration and unsigned motion graphs for one-direction motion.

  • SEC G3 Combined Science Physics component 2027
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Learning objectives

  • State what speed means
  • State what velocity means, including its direction
  • Calculate average speed from total distance and total time
  • Calculate acceleration as change in velocity divided by time taken
  • State what uniform acceleration means
  • Interpret examples of non-uniform acceleration
  • Plot and interpret a distance–time graph
  • Plot and interpret a speed–time graph for one-direction motion
  • Deduce rest, uniform speed and non-uniform speed from a distance–time graph
  • Deduce rest, uniform speed and uniform or non-uniform acceleration from a speed–time graph
  • Use area under a speed–time graph to determine distance travelled
  • Recall constant free-fall acceleration near Earth as approximately 10 m/s²
Syllabus and review details

This Science course uses distance–time and speed–time graphs. Signed displacement and negative velocity belong to standalone G3 Physics and are omitted.

Speed describes how quickly distance changes

Speed is the distance travelled per unit time. It is a scalar: it has a magnitude but no direction.

average speedtotal distance travelledtotal time taken

Use the totals for the whole journey. Do not take an arithmetic mean of listed speeds unless the time spent at each speed is equal.

A bus travels 12 km at 60 km/h, then another 12 km at 20 km/h. The mean of the two speeds, (60 + 20) ÷ 2 = 40 km/h, is not its average speed.

time for each part = 12 ÷ 60 = 0.20 h and 12 ÷ 20 = 0.60 h

average speed = 24 km ÷ 0.80 h = 30 km/h

The bus spends three times as long on the slow part, so the slow speed accounts for most of the journey time and pulls the average towards 20 km/h.

Note
In SI units, distance is measured in metres (m), time in seconds (s), and speed in metres per second (m/s). Convert kilometres per hour before combining it with SI data.

Velocity adds direction to speed

Velocity is speed in a stated direction. A car travelling at 12 m/s east has a velocity of 12 m/s east; “12 m/s” alone states only its speed. An object can keep the same speed while its velocity changes if its direction changes.

Speedscalaruses distance
Velocityvectorincludes direction

Acceleration is a change per unit time

Acceleration is the change in velocity per unit time. In this course every motion is along one straight line in one direction, so the change in velocity is the final speed minus the initial speed.

accelerationfinal speed − initial speedtime taken
  1. Write the initial and final speeds in the same units.
  2. Calculate final speed minus initial speed. A negative answer means the object is slowing down.
  3. Divide by the time interval and state the unit m/s2.

Acceleration is not the same as high speed. An aircraft cruising at a steady 250 m/s has zero acceleration because its speed is not changing. A cyclist pulling away from traffic lights at only 3 m/s is accelerating. Ask how much the speed changes each second, not how fast the object is already moving.

Uniform acceleration gives equal speed changes

Uniform acceleration means the velocity changes by the same amount in each equal time interval. For motion in one direction, the speed rises (or falls) by the same amount every second. A uniform acceleration of 2 m/s2 means the speed changes by 2 m/s every second.

A trolley timed each second
time / s01234
speed / m/s357911

The speed rises by 2 m/s in every second, so the acceleration is uniform: (11 − 3) ÷ 4 = 2.0 m/s2.

Non-uniform acceleration

Acceleration is non-uniform when the speed changes by different amounts in equal time intervals. A cyclist who gains 2 m/s in one second but only 1 m/s in the next is still speeding up, but the acceleration is decreasing.

Everyday motion is often like this. A car pulling away in traffic speeds up quickly at first and then more gradually. A falling skydiver gains speed more and more slowly as air resistance grows, until the speed stops rising.

On a speed–time graph, a straight sloping line has constant gradient and therefore uniform acceleration. A curved line has a changing gradient and therefore non-uniform acceleration.

Plot a motion graph from measured data

Relationships for distance–time and speed–time graphsTwo graphs share a time axis. The distance–time graph becomes steeper as speed increases. The speed–time graph rises linearly; its gradient gives acceleration and its area gives distance travelled.One journey, two Science graph viewsThe axes decide what gradient and area mean.
Read the horizontal axis first. A distance–time gradient gives speed; a speed–time gradient gives acceleration, while the area under a speed–time graph gives distance travelled.
  1. Put time on the horizontal axis and the measured motion quantity on the vertical axis.
  2. Label both axes with quantity and unit, then choose a simple linear scale using most of the grid.
  3. Plot every point accurately. Use a line through exact motion records or an appropriate best-fit trend for experimental data.
  4. Read coordinates before calculating a gradient; use a large triangle on a straight section.
Warning
A motion graph is not a drawing of the route. Its height, gradient and area each have specific meanings determined by the axis labels.

Distance–time graphs

These Science-course graphs describe motion in one direction. Distance travelled can increase or stay the same; it cannot decrease. The vertical axis records distance, while the horizontal axis records time.

Gradient = speed. The gradient compares the change in distance with the time taken.

  • horizontal: at rest
  • straight rising line: uniform speed
  • changing gradient: non-uniform speed

Reading a distance–time graph

Distance–time graph of a walk in one directionDistance in metres against time in seconds. The line rises straight from 0 m at 0 s to 12 m at 4 s, stays level at 12 m from 4 s to 7 s, then rises straight to 30 m at 10 s.
Scroll diagram horizontally to read all labels.
A walker's distance from the start, recorded while walking in one direction along a path.
  1. 0–4 s: a straight rising line, so the speed is uniform. Gradient = 12 ÷ 4 = 3.0 m/s.
  2. 4–7 s: the line is horizontal. The distance stays at 12 m, so the walker is at rest.
  3. 7–10 s: a steeper straight line. Gradient = (30 − 12) ÷ (10 − 7) = 6.0 m/s.

Read speed from the gradient, not from the height. At 6 s the walker is 12 m from the start but not moving at all. The graph also never slopes downwards: when motion is in one direction the distance travelled can only stay the same or increase.

Find the first graph-reading error

Using the walker's graph, a learner writes: “At 6 s the line is at 12, so the speed is 12 m/s. From 7 s to 10 s the speed is 30 ÷ 10 = 3 m/s.” Identify the first incorrect step, then correct both speeds using the axes and the relevant interval.

Check the correction

The first error is treating graph height as speed: the vertical axis is distance in metres. At 6 s the line is horizontal, so distance is not changing and the speed is 0 m/s. From 7 s to 10 s, use the changes between the two endpoints: (30 − 12) ÷ (10 − 7) = 6 m/s. The value 30 ÷ 10 = 3 m/s is the average for the whole walk, including the rest, rather than the speed during that final interval.

Speed–time graphs and distance

Here the vertical axis gives speed directly. Its height tells you how fast the object is moving; its gradient tells you how quickly that speed changes. Gradient = acceleration.

  • on the time axis: at rest
  • horizontal above zero: uniform speed
  • straight slope: uniform acceleration
  • curve: non-uniform acceleration

Area under the graph gives distance

Split the region between the graph and time axis into rectangles and triangles. For a speed rising uniformly from 4 m/s to 10 m/s over 3 s, the area is a trapezium:

distance = ½ × (4 + 10) × 3

distance = 21 m

This method is required here only for uniform speed or uniform acceleration. Because speed is non-negative, every included area contributes positively to distance travelled. Check the units: speed in m/s multiplied by time in s gives distance in m.

Worked example: describe and calculate from a speed–time graph

A trolley accelerates uniformly from rest to 8 m/s in 4 s, travels at 8 m/s for 3 s, then slows uniformly to rest in 2 s.

Speed–time graph of the trolleySpeed in metres per second against time in seconds. The line rises straight from 0 m/s at 0 s to 8 m/s at 4 s, stays level at 8 m/s until 7 s, then falls straight to 0 m/s at 9 s. The region under the line is shaded.
Scroll diagram horizontally to read all labels.
The shaded region under the line is split into a triangle, a rectangle and a triangle.
  1. First acceleration = (8 − 0) ÷ 4 = 2.0 m/s2.
  2. First triangle area = ½ × 4 × 8 = 16 m.
  3. Rectangle area = 3 × 8 = 24 m.
  4. Final triangle area = ½ × 2 × 8 = 8 m.
  5. Total distance = 16 + 24 + 8 = 48 m.

Free fall near Earth

A body is in free fall when gravity is the only significant force on it. Near the Earth's surface, its acceleration is then constant and approximately 10 m/s2 downward. The measured value is about 9.8 m/s2; this course uses 10 m/s2. “Free fall” does not mean the body must be moving downward.

A ball dropped from rest, with air resistance negligible
time / s0123
speed / m/s0102030

The speed rises by 10 m/s every second, whatever the mass. A 5 kg steel ball and a 0.1 kg marble dropped together gain speed at the same rate and land together. A heavier body is pulled harder by gravity, but it is also harder to speed up, so its acceleration is the same.

This model assumes air resistance is negligible, which suits a small, dense object falling a short distance. It does not suit a feather, a sheet of paper or a skydiver. For them, air resistance grows as they speed up, so their acceleration falls below 10 m/s2 and becomes non-uniform.

Warning
At the highest point of a vertical throw, the instantaneous velocity is zero but the acceleration remains about 10 m/s2 downward.

Common graph mistakes

“A steeper graph always means greater acceleration.”
Only the gradient of a speed–time graph is acceleration. A distance–time gradient is speed.
“A horizontal speed–time line means the object is stationary.”
It means constant speed. The object is stationary only when the line is on the time axis.
“A higher point on a distance–time graph means a greater speed.”
Height shows how far the object has travelled. Speed is the gradient, so a high horizontal section means the object is at rest.
“A distance–time graph slopes down when the object slows.”
For motion in one direction the distance never decreases. Slowing down makes the graph less steep; stopping makes it horizontal.
“Zero speed means zero acceleration.”
Speed describes the current motion; acceleration describes how velocity is changing.

Worked example: a journey with two stages

A delivery robot travels at a constant 2.5 m/s for 12 s. It then accelerates uniformly from 2.5 m/s to 7.5 m/s for 8 s.

  1. First-stage distance = 2.5 × 12 = 30 m.
  2. Second-stage distance = average speed × time = ½(2.5 + 7.5) × 8 = 40 m.
  3. Total distance = 30 + 40 = 70 m.
  4. Total time = 12 + 8 = 20 s.
  5. Average speed = 70 ÷ 20 = 3.5 m/s.
  6. Acceleration during the second stage = (7.5 − 2.5) ÷ 8 = 0.625 m/s2.

Check: the average speed lies between the stage speeds, and m/s divided by s gives m/s2.

Connect the complete Kinematics method

A cyclist moves at 4.0 m/s for 3.0 s, then accelerates uniformly to 10.0 m/s over 2.0 s. The acceleration on the sloping speed–time section is (10.0 − 4.0) ÷ 2.0 = 3.0 m/s2.

The distance travelled is the area under the speed–time graph: (4.0 × 3.0) + ½(4.0 + 10.0)(2.0) = 26 m. This calculation is separate from free fall: for any object moving under gravity alone near Earth, the acceleration is approximately 10 m/s2 downward, even if the object is momentarily moving upward.

Guided practice

A body moves at 6.0 m/s for 4.0 s, then accelerates uniformly to 12.0 m/s in 3.0 s. Find the acceleration and distance, describe both graph sections, and state what remains true about free-fall acceleration at the top of a later vertical flight.

Check the guided reasoning

Acceleration = (12.0 − 6.0) ÷ 3.0 = 2.0 m/s2. Distance = (6.0 × 4.0) + ½(6.0 + 12.0)(3.0) = 51 m. The first speed–time section is horizontal and the second is a straight rise. At the highest point, velocity is zero but acceleration remains about 10 m/s2 downward.

Check your understanding

1. Why is 12 m/s east a velocity but 12 m/s only a speed?

Velocity includes a direction; speed does not.

2. A car travels 30 km at 90 km/h, then 30 km at 30 km/h. Is its average speed 60 km/h?

No. The two parts take 30 ÷ 90 = 1/3 h and 30 ÷ 30 = 1 h, so the average speed is 60 km ÷ 4/3 h = 45 km/h. The car spends longer at the lower speed.

3. A speed–time line rises from 2 m/s to 11 m/s in 3 s. Find the acceleration.

(11 − 2) ÷ 3 = 3.0 m/s2.

4. A distance–time graph is horizontal at 40 m from 5 s to 9 s. What is the speed?

Zero. The object has travelled 40 m but is at rest; the height gives distance, and the zero gradient gives the speed.

5. How does a curved speed–time line show non-uniform acceleration?

Its gradient changes with time, so the acceleration is not constant.

6. A speed–time rectangle is 6 m/s high and 5 s wide. Find the distance.

Area = 6 × 5 = 30 m.

7. A 2 kg stone and a 0.2 kg pebble are dropped together. Air resistance is negligible. Compare their accelerations.

They are the same, about 10 m/s2. Free-fall acceleration does not depend on mass.

8. What is the acceleration at the highest point of a vertical throw?

Approximately 10 m/s2 downward, even though velocity is momentarily zero.

Try this next: what do gradient and area mean on a speed–time graph?

Gradient gives acceleration; area gives distance travelled.

Practise this topic

The topic check is written for this course. Use the feedback to revisit the right explanation, then try a fresh check later.

Practise

Practise: Kinematics

A text-first Kinematics assessment with labelled controls and explicit directions, graph axes, quantities and units.

About 10 minutes

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Practise

Practise after feedback: Kinematics

A text-first Kinematics assessment with labelled controls and explicit directions, graph axes, quantities and units.

About 10 minutes

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Questions are selected when you start. Use the feedback to decide what to practise next; this does not prove mastery.

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Check what I know

Check what I know: Kinematics

A text-first Kinematics assessment with labelled controls and explicit directions, graph axes, quantities and units.

About 8 minutes

Check what I know

Answer 6 short questions. This starting check helps choose what to work on; it does not prove mastery.

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Check my progress

Check my progress: Kinematics

A text-first Kinematics assessment with labelled controls and explicit directions, graph axes, quantities and units.

About 10 minutes

Check my progress

Answer 9 questions. If accepted, this result can contribute to your course progress.

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Check again

Check again: Kinematics

A text-first Kinematics assessment with labelled controls and explicit directions, graph axes, quantities and units.

About 10 minutes

Check again

Answer 9 questions. If accepted, this result can contribute to your course progress.

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Review

Review: Kinematics

A text-first Kinematics assessment with labelled controls and explicit directions, graph axes, quantities and units.

About 10 minutes

Review

Answer 9 questions. A scheduled review can contribute to your course progress only when it is due and the result is accepted.

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Course and syllabus information
Course
SEC G3 Combined Science Physics component
Edition
SEC G3 Combined Science Physics component 2027