How a load changes a potential divider

Key idea: A load across a divider's output is in parallel with its output resistor. Their lower combined resistance reduces the output voltage and increases the supply current.

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  • GCE A-Level H2 Physics 2027
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An unloaded potential divider gives the voltage set by its two series resistors. Connecting a load changes the circuit you must analyse. The device you connect draws current, and the output voltage drops. Even a voltmeter can do this, so the reading you see may be lower than the voltage that was there before you measured it.

Loading a potential divider

Connecting a load of resistance RL across the output adds a parallel branch to the lower resistor R₂. The two now act as one resistor,

Rₚ = R₂RL/(R₂ + RL)

in series with the upper resistor R₁, so the output becomes

Vₒᵤₜ = VₛRₚ/(R₁ + Rₚ)

Rₚ is smaller than R₂, so the lower part of the divider now takes a smaller share of the supply p.d.: the output falls. The current through R₁ splits between R₂ and the load.

Unloaded and loaded potential-divider circuitsSide-by-side circuits. The unloaded circuit has R1 and R2 in series, with output across R2. In the loaded circuit, load resistance RL is connected in parallel with R2, reducing the effective resistance of the output branch.Unloaded outputLoaded outputOnly R₁ and R₂ set the divider ratio.Rₗ is connected across the output terminals.Vᵢₙ+0 VR₁R₂VoutVout = Vin × R₂ / (R₁ + R₂)Vᵢₙ+0 VR₁R₂RₗVoutOutput branch: Rₑₚ = R₂ ∥ RₗUse Rₑₚ in place of R₂ in the divider formula.
Unloaded and loaded potential-divider circuitsSide-by-side circuits. The unloaded circuit has R1 and R2 in series, with output across R2. In the loaded circuit, load resistance RL is connected in parallel with R2, reducing the effective resistance of the output branch. Unloaded outputOnly R₁ and R₂ set the divider ratio.Vᵢₙ+0 VR₁R₂VoutVout = Vin × R₂ / (R₁ + R₂) Loaded outputRₗ is connected across the output terminals.Vᵢₙ+0 VR₁R₂RₗVoutOutput branch: Rₑₚ = R₂ ∥ RₗUse Rₑₚ in place of R₂ in the divider formula.
Connecting a load across R₂ puts the load in parallel with R₂. Replace that branch by Rₑₚ = R₂ ∥ Rₗ before applying the potential-divider relationship.

Worked example 1

Before and after loading

Problem

A potential divider across a 12.0 V supply has R₁ = 2.00 kΩ and R₂ = 4.00 kΩ. Find the output across R₂, then the output when a 4.00 kΩ load is connected across R₂.

Show full solution
  1. Unloaded output

    Reason

    With no load, the same current flows through both resistors.

    Working

    Answer

    Vₒᵤₜ = 12.0 × 4.00/(2.00 + 4.00) = 8.00 V

  2. Load and lower resistor

    Method

    Combine R₂ and the load in parallel.

    Reason

    They are connected across the same two points.

    Working

    Answer

    Rₚ = (4.00)(4.00)/(4.00 + 4.00) = 2.00 kΩ

  3. Loaded output

    Working

    Answer

    Vₒᵤₜ = 12.0 × 2.00/(2.00 + 2.00) = 6.00 V

The effect of the load resistance

The larger the load resistance, the less current it draws and the less it lowers the output. The graph shows the divider in the worked example with loads of different resistance: as RL becomes very large, the output approaches the unloaded 8.00 V. A load whose resistance is much larger than the divider’s resistors hardly changes the output; a small one pulls it towards zero.

Divider output and load resistance

Loaded output increases from zero as load resistance increases and approaches the horizontal unloaded value of 8 V from below.

Scroll across the figure to read all labels.

Loaded output increases from zero as load resistance increases and approaches the horizontal unloaded value of 8 V from below.Loaded output increases from zero as load resistance increases and approaches the horizontal unloaded value of 8 V from below.
An ideal 12.0 V source supplies a 2.00 kΩ upper resistor and 4.00 kΩ lower resistor. The load is across the lower resistor. The loaded output uses Rₚ = 4RL/(4 + RL), with resistances in kΩ, then Vₒᵤₜ = 12Rₚ/(2 + Rₚ). The unloaded 8.00 V line is approached as load resistance tends to infinity.
Open full-size graph
What to noticeA higher load resistance draws less output current, so voltage approaches the unloaded 8.00 V value from below.
View figure data
Figure data: Divider output and load resistance
Load resistance, RL (kΩ)Loaded outputUnloaded output
0.000.00008
0.050.28928
0.100.55818
0.150.80908
0.201.04358
0.251.26328
0.301.46948
0.351.66348
0.401.84628
0.452.01878
0.502.18188
0.552.33638
0.602.48288
0.652.62188
0.702.75418
0.752.88008
0.803.00008
0.853.11458
0.903.22398
0.953.32858
1.003.42868
1.053.52458
1.103.61648
1.153.70478
1.203.78958
1.253.87108
1.303.94948
1.354.02488
1.404.09768
1.454.16778
1.504.23538
1.554.30068
1.604.36368
1.654.42468
1.704.48358
1.754.54058
1.804.59578
1.854.64928
1.904.70108
1.954.75138
2.004.80008
2.054.84738
2.104.89328
2.154.93788
2.204.98118
2.255.02338
2.305.06428
2.355.10418
2.405.14298
2.455.18068
2.505.21748
2.555.25328
2.605.28818
2.655.32228
2.705.35548
2.755.38788
2.805.41948
2.855.45028
2.905.48038
2.955.50978
3.005.53858
3.055.56658
3.105.59408
3.155.62088
3.205.64718
3.255.67278
3.305.69788
3.355.72248
3.405.74658
3.455.77008
3.505.79318
3.555.81578
3.605.83788
3.655.85958
3.705.88088
3.755.90168
3.805.92218
3.855.94218
3.905.96188
3.955.98118
4.006.00008
4.056.01868
4.106.03688
4.156.05478
4.206.07238
4.256.08968
4.306.10658
4.356.12328
4.406.13958
4.456.15568
4.506.17148
4.556.18708
4.606.20228
4.656.21738
4.706.23208
4.756.24668
4.806.26098
4.856.27498
4.906.28888
4.956.30248
5.006.31588
5.056.32908
5.106.34208
5.156.35488
5.206.36738
5.256.37978
5.306.39208
5.356.40408
5.406.41588
5.456.42758
5.506.43908
5.556.45048
5.606.46158
5.656.47268
5.706.48348
5.756.49418
5.806.50478
5.856.51518
5.906.52538
5.956.53558
6.006.54558
6.056.55538
6.106.56508
6.156.57468
6.206.58418
6.256.59348
6.306.60268
6.356.61178
6.406.62078
6.456.62968
6.506.63838
6.556.64698
6.606.65558
6.656.66398
6.706.67228
6.756.68048
6.806.68858
6.856.69658
6.906.70458
6.956.71238
7.006.72008
7.056.72768
7.106.73528
7.156.74268
7.206.75008
7.256.75738
7.306.76458
7.356.77168
7.406.77868
7.456.78568
7.506.79258
7.556.79928
7.606.80608
7.656.81268
7.706.81928
7.756.82578
7.806.83218
7.856.83858
7.906.84488
7.956.85108
8.006.85718
8.056.86328
8.106.86938
8.156.87528
8.206.88118
8.256.88708
8.306.89278
8.356.89858
8.406.90418
8.456.90978
8.506.91538
8.556.92078
8.606.92628
8.656.93168
8.706.93698
8.756.94218
8.806.94748
8.856.95258
8.906.95778
8.956.96278
9.006.96778
9.056.97278
9.106.97768
9.156.98258
9.206.98738
9.256.99218
9.306.99698
9.357.00168
9.407.00628
9.457.01088
9.507.01548
9.557.01998
9.607.02448
9.657.02888
9.707.03328
9.757.03768
9.807.04198
9.857.04628
9.907.05048
9.957.05478
10.007.05888
10.057.06308
10.107.06718
10.157.07118
10.207.07518
10.257.07918
10.307.08318
10.357.08708
10.407.09098
10.457.09488
10.507.09868
10.557.10248
10.607.10618
10.657.10998
10.707.11368
10.757.11728
10.807.12098
10.857.12458
10.907.12818
10.957.13168
11.007.13518
11.057.13868
11.107.14218
11.157.14558
11.207.14898
11.257.15238
11.307.15578
11.357.15908
11.407.16238
11.457.16568
11.507.16888
11.557.17218
11.607.17538
11.657.17848
11.707.18168
11.757.18478
11.807.18788
11.857.19098
11.907.19408
11.957.19708
12.007.20008
12.057.20308
12.107.20608
12.157.20898
12.207.21188
12.257.21478
12.307.21768
12.357.22058
12.407.22338
12.457.22618
12.507.22898
12.557.23178
12.607.23448
12.657.23728
12.707.23998
12.757.24268
12.807.24538
12.857.24798
12.907.25068
12.957.25328
13.007.25588
13.057.25848
13.107.26108
13.157.26358
13.207.26618
13.257.26868
13.307.27118
13.357.27368
13.407.27608
13.457.27858
13.507.28098
13.557.28338
13.607.28578
13.657.28818
13.707.29058
13.757.29288
13.807.29528
13.857.29758
13.907.29988
13.957.30218
14.007.30438
14.057.30668
14.107.30898
14.157.31118
14.207.31338
14.257.31558
14.307.31778
14.357.31998
14.407.32208
14.457.32428
14.507.32638
14.557.32848
14.607.33058
14.657.33268
14.707.33478
14.757.33688
14.807.33888
14.857.34098
14.907.34298
14.957.34498
15.007.34698
15.057.34898
15.107.35098
15.157.35298
15.207.35488
15.257.35688
15.307.35878
15.357.36068
15.407.36258
15.457.36448
15.507.36638
15.557.36828
15.607.37018
15.657.37198
15.707.37388
15.757.37568
15.807.37748
15.857.37928
15.907.38108
15.957.38288
16.007.38468
16.057.38648
16.107.38818
16.157.38998
16.207.39168
16.257.39348
16.307.39518
16.357.39688
16.407.39858
16.457.40028
16.507.40198
16.557.40358
16.607.40528
16.657.40698
16.707.40858
16.757.41018
16.807.41188
16.857.41348
16.907.41508
16.957.41668
17.007.41828
17.057.41988
17.107.42138
17.157.42298
17.207.42458
17.257.42608
17.307.42758
17.357.42918
17.407.43068
17.457.43218
17.507.43368
17.557.43518
17.607.43668
17.657.43818
17.707.43968
17.757.44108
17.807.44258
17.857.44408
17.907.44548
17.957.44688
18.007.44838
18.057.44978
18.107.45118
18.157.45258
18.207.45398
18.257.45538
18.307.45678
18.357.45818
18.407.45958
18.457.46088
18.507.46228
18.557.46358
18.607.46498
18.657.46628
18.707.46768
18.757.46898
18.807.47028
18.857.47158
18.907.47288
18.957.47418
19.007.47548
19.057.47678
19.107.47808
19.157.47938
19.207.48058
19.257.48188
19.307.48308
19.357.48438
19.407.48558
19.457.48688
19.507.48808
19.557.48928
19.607.49048
19.657.49178
19.707.49298
19.757.49418
19.807.49538
19.857.49658
19.907.49768
19.957.49888
20.007.50008

A voltmeter is a load too. An ideal voltmeter has infinite resistance and draws no current, but a real one with a resistance similar to the divider’s resistors reads less than the unloaded output.

Check your understanding 1 Lower output, lower currents?

When a load is connected, the output voltage falls. Does the current from the supply fall too?

Show answer

No, it rises. The extra parallel branch lowers the total resistance of the circuit, so more current flows from the supply. The output falls because the lower part of the divider now has a smaller resistance and takes a smaller share of the supply p.d.

Guided practice 2

A voltmeter loading a divider

About 3 min

Problem

A potential divider across 9.0 V is made of two 10 kΩ resistors. A voltmeter of resistance 10 kΩ is connected across the lower resistor. Find the output before the meter is connected, the equivalent resistance of the lower arm and meter, and the reading after connection.

Find both values

Unit: V
Show the steps Optional working
Unit: kΩ
Unit: V

Hints

Hint 1

the meter is a resistor

Which components share the same two connection points?

Show full solution
  1. Both values

    Working

    Answer

    Without the voltmeter: 4.5 V. With it: 9.0 × 5.0/(10 + 5.0) = 3.0 V. The meter reads a third less than the p.d. it was meant to measure.

Try it yourself 3

Choosing a voltmeter

Minimal support

Problem

You need to measure the output of a potential divider made of two 10 kΩ resistors as accurately as possible. Which voltmeter should you use?

Choose a voltmeter

Voltmeter resistance

Hints

Hint 1

parallel combination

Find the parallel combination of each meter with the 10 kΩ lower resistor. Which leaves it almost unchanged?

Show solution step by step
  1. Compare the meters

    Reason

    The meter is in parallel with the lower resistor.

    Working

    Answer

    10 MΩ in parallel with 10 kΩ is still almost exactly 10 kΩ; the others lower it to 0.91 kΩ and 5 kΩ.

  2. Choice

    Working

    Answer

    The 10 MΩ voltmeter: its resistance is far larger than the divider’s resistors, so it barely loads the divider.

Check your understanding 2 Design for a minimum output

A 12.0 V supply feeds R₁ = 2.00 kΩ and R₂ = 4.00 kΩ. A load is connected across R₂. Find the minimum load resistance that keeps the output at or above 6.00 V. Decide whether larger or smaller loads satisfy the requirement.

Show the steps Optional working
Unit: kΩ
Unit: kΩ
Allowed load resistances

Show answer

At Vₒᵤₜ = 6.00 V, the lower equivalent is Rₚ = 2.00 kΩ. In kΩ units, 1/2.00 = 1/4.00 + 1/RL, so RL = 4.00 kΩ. Increasing RL increases Rₚ and the output, so all larger values satisfy the requirement.

Exam-style question 1

A device across the lower resistor

5 marks

Examination question

A potential divider across a 10.0 V supply has a 3.00 kΩ upper resistor and a 6.00 kΩ lower resistor. A device of resistance 3.00 kΩ is connected across the lower resistor.

(a) Calculate the p.d. across the device. [3 marks]

(b) Calculate the current from the supply and the current in the device. [2 marks]

Write your answer before viewing the mark scheme

Show solution step by step
  1. (a) P.d.

    3 marks

    Method

    Combine the lower resistor and the device, then use the divider rule.

    Reason

    They are in parallel, and the combination is in series with the upper resistor.

    Working

    Answer

    Rₚ = (6.00)(3.00)/9.00 = 2.00 kΩ, so V = 10.0 × 2.00/(3.00 + 2.00) = 4.00 V

  2. (b) Currents

    2 marks

    Working

    Answer

    Supply: 10.0/(5.00 kΩ) = 2.00 mA. Device: 4.00/(3.00 kΩ) = 1.33 mA

Common mistakes

  • Using the unloaded divider equation after a load has been connected.
  • Giving the upper resistor, the lower resistor and the load all the same current.
  • Thinking a load lowers every current in the circuit; the supply current rises.
  • Treating a real voltmeter as if it drew no current.

Spotted an error? Report a correction

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