Phase Difference
Key idea: Define phase and phase difference, and calculate phase difference from path difference or time delay (A Level Physics).
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The core idea
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Learning objectives
- Describe wave models, use wave quantities and interpret wave graphs in space and time.
- Relate phase difference to separations in time and position.
- Explain single-aperture diffraction and apply first-minimum and Rayleigh criteria.
- Explain coherent two-source interference using phase and path difference.
1. Definitions (Must Know)
A. Phase, φ (rad)
Phase, φ, tells you where you are within a cycle of oscillation.
It is measured in radians.
B. Phase difference, Δ φ (rad)
Phase difference, Δ φ, is the difference in phase between two oscillations (two points on the same wave, or two waves).
It tells you how much one oscillation leads or lags another.
C. In phase and antiphase
| Relationship | Phase difference |
|---|---|
| In phase | Δφ = 2π n |
| Antiphase (half a cycle apart) | Δφ = (2n + 1)π |
where n is an integer.
D. Linking phase difference to time delay or path difference
For the same wave (or two coherent waves of the same frequency):
- time delay Δ t at the same position: Δφ = 2π(Δ t)/T
- path difference Δ x at the same time: Δφ = 2π(Δ x)/λ
Phase is periodic. Adding or subtracting 2π does not change the physical state.
2. Key Ideas (What Earns Marks)
- Always state what you are comparing (same position? same time?).
- Use the fraction-of-a-cycle idea:
- Δ t/T is the fraction of a period.
- Δ x/λ is the fraction of a wavelength.
- Multiply the fraction by 2π to get phase difference.
- Reduce answers to a standard range if needed (e.g. 0 to 2π), but remember that 2π multiples are equivalent.
3. Detailed Explanations
A. Time delay → phase difference
If one oscillation reaches the same state Δ t later:
Δφ = 2π(Δ t)/T
Example: if Δ t = (1/4)T, then Δφ = π/2.
B. Path difference → phase difference
If two points on the same progressive wave are separated by distance Δ x (same time snapshot):
Δφ = 2π(Δ x)/λ
Example: if Δ x = (1/2)λ, then Δφ = π (antiphase).
C. Visualising phase difference (example)
This plot shows two sine waves with a fixed phase difference of Δφ = π/2.
Two waves with a phase difference of π/2
Example of two sine waves with the same frequency but a constant phase difference.
Scroll across the graph to read all labels.
View figure data
| Phase angle (rad) | Wave 1 | Wave 2 |
|---|---|---|
| 0 | 0 | 1 |
| 0.05235987755982988 | 0.05233595624294383 | 0.9986295347545738 |
| 0.10471975511965977 | 0.10452846326765346 | 0.9945218953682734 |
| 0.15707963267948966 | 0.15643446504023087 | 0.9876883405951378 |
| 0.20943951023931953 | 0.20791169081775931 | 0.9781476007338057 |
| 0.2617993877991494 | 0.25881904510252074 | 0.9659258262890683 |
| 0.3141592653589793 | 0.3090169943749474 | 0.9510565162951536 |
| 0.3665191429188092 | 0.35836794954530027 | 0.9335804264972017 |
| 0.41887902047863906 | 0.40673664307580015 | 0.913545457642601 |
| 0.47123889803846897 | 0.45399049973954675 | 0.8910065241883679 |
| 0.5235987755982988 | 0.49999999999999994 | 0.8660254037844387 |
| 0.5759586531581287 | 0.544639035015027 | 0.8386705679454243 |
| 0.6283185307179586 | 0.5877852522924731 | 0.8090169943749475 |
| 0.6806784082777886 | 0.6293203910498375 | 0.7771459614569708 |
| 0.7330382858376184 | 0.6691306063588582 | 0.7431448254773942 |
| 0.7853981633974482 | 0.7071067811865475 | 0.7071067811865476 |
| 0.8377580409572781 | 0.7431448254773942 | 0.6691306063588583 |
| 0.8901179185171081 | 0.7771459614569709 | 0.6293203910498374 |
| 0.9424777960769379 | 0.8090169943749475 | 0.5877852522924732 |
| 0.9948376736367678 | 0.8386705679454239 | 0.5446390350150273 |
| 1.0471975511965976 | 0.8660254037844386 | 0.5000000000000003 |
| 1.0995574287564276 | 0.8910065241883678 | 0.45399049973954686 |
| 1.1519173063162573 | 0.9135454576426009 | 0.40673664307580043 |
| 1.2042771838760873 | 0.9335804264972017 | 0.35836794954530066 |
| 1.2566370614359172 | 0.9510565162951535 | 0.3090169943749475 |
| 1.3089969389957472 | 0.9659258262890683 | 0.2588190451025206 |
| 1.3613568165555772 | 0.9781476007338057 | 0.20791169081775931 |
| 1.413716694115407 | 0.9876883405951378 | 0.15643446504023098 |
| 1.4660765716752369 | 0.9945218953682733 | 0.10452846326765329 |
| 1.5184364492350668 | 0.9986295347545738 | 0.05233595624294381 |
| 1.5707963267948963 | 1 | 1.2246467991473532e-16 |
| 1.6231562043547263 | 0.9986295347545738 | -0.052335956242943564 |
| 1.6755160819145563 | 0.9945218953682734 | -0.10452846326765305 |
| 1.7278759594743862 | 0.9876883405951378 | -0.15643446504023073 |
| 1.7802358370342162 | 0.9781476007338057 | -0.2079116908177595 |
| 1.832595714594046 | 0.9659258262890683 | -0.25881904510252035 |
| 1.8849555921538759 | 0.9510565162951536 | -0.3090169943749473 |
| 1.9373154697137058 | 0.9335804264972017 | -0.35836794954530043 |
| 1.9896753472735356 | 0.913545457642601 | -0.4067366430757998 |
| 2.0420352248333655 | 0.8910065241883679 | -0.4539904997395467 |
| 2.0943951023931953 | 0.8660254037844387 | -0.4999999999999997 |
| 2.146754979953025 | 0.8386705679454243 | -0.5446390350150268 |
| 2.199114857512855 | 0.8090169943749475 | -0.587785252292473 |
| 2.251474735072685 | 0.777145961456971 | -0.6293203910498373 |
| 2.3038346126325147 | 0.7431448254773945 | -0.6691306063588579 |
| 2.356194490192345 | 0.7071067811865476 | -0.7071067811865475 |
| 2.4085543677521746 | 0.6691306063588583 | -0.743144825477394 |
| 2.4609142453120048 | 0.6293203910498374 | -0.7771459614569706 |
| 2.5132741228718345 | 0.5877852522924732 | -0.8090169943749473 |
| 2.5656340004316642 | 0.5446390350150273 | -0.838670567945424 |
| 2.6179938779914944 | 0.49999999999999994 | -0.8660254037844388 |
| 2.670353755551324 | 0.45399049973954686 | -0.8910065241883678 |
| 2.7227136331111543 | 0.40673664307580004 | -0.913545457642601 |
| 2.775073510670984 | 0.3583679495453002 | -0.9335804264972016 |
| 2.827433388230814 | 0.3090169943749475 | -0.9510565162951535 |
| 2.879793265790644 | 0.2588190451025206 | -0.9659258262890683 |
| 2.9321531433504737 | 0.20791169081775931 | -0.9781476007338057 |
| 2.9845130209103035 | 0.15643446504023098 | -0.9876883405951377 |
| 3.0368728984701336 | 0.10452846326765329 | -0.9945218953682734 |
| 3.0892327760299634 | 0.05233595624294381 | -0.9986295347545738 |
| 3.1415926535897927 | 5.66553889764798e-16 | -1 |
| 3.193952531149623 | -0.052335956242943564 | -0.9986295347545738 |
| 3.2463124087094526 | -0.10452846326765305 | -0.9945218953682734 |
| 3.2986722862692828 | -0.15643446504023073 | -0.9876883405951378 |
| 3.3510321638291125 | -0.20791169081775907 | -0.9781476007338058 |
| 3.4033920413889422 | -0.25881904510252035 | -0.9659258262890684 |
| 3.4557519189487724 | -0.3090169943749473 | -0.9510565162951536 |
| 3.508111796508602 | -0.3583679495453 | -0.9335804264972017 |
| 3.5604716740684323 | -0.4067366430758002 | -0.9135454576426008 |
| 3.612831551628262 | -0.4539904997395467 | -0.891006524188368 |
| 3.665191429188092 | -0.4999999999999997 | -0.866025403784439 |
| 3.717551306747922 | -0.5446390350150271 | -0.8386705679454243 |
| 3.7699111843077517 | -0.587785252292473 | -0.8090169943749476 |
| 3.8222710618675815 | -0.6293203910498373 | -0.7771459614569708 |
| 3.8746309394274117 | -0.6691306063588582 | -0.743144825477394 |
| 3.9269908169872414 | -0.7071067811865475 | -0.7071067811865477 |
| 3.979350694547071 | -0.743144825477394 | -0.6691306063588588 |
| 4.031710572106901 | -0.7771459614569706 | -0.6293203910498378 |
| 4.084070449666731 | -0.8090169943749473 | -0.5877852522924734 |
| 4.136430327226561 | -0.838670567945424 | -0.544639035015027 |
| 4.1887902047863905 | -0.8660254037844385 | -0.5000000000000004 |
| 4.241150082346221 | -0.8910065241883678 | -0.45399049973954697 |
| 4.29350995990605 | -0.9135454576426005 | -0.40673664307580093 |
| 4.345869837465881 | -0.9335804264972019 | -0.35836794954529994 |
| 4.39822971502571 | -0.9510565162951535 | -0.3090169943749476 |
| 4.4505895925855405 | -0.9659258262890683 | -0.2588190451025207 |
| 4.50294947014537 | -0.9781476007338056 | -0.20791169081775987 |
| 4.5553093477052 | -0.9876883405951377 | -0.15643446504023112 |
| 4.607669225265029 | -0.9945218953682733 | -0.1045284632676543 |
| 4.66002910282486 | -0.9986295347545739 | -0.05233595624294348 |
| 4.71238898038469 | -1 | -2.4492935982947064e-16 |
| 4.76474885794452 | -0.9986295347545738 | 0.05233595624294388 |
| 4.817108735504349 | -0.9945218953682734 | 0.10452846326765293 |
| 4.869468613064179 | -0.9876883405951378 | 0.15643446504023062 |
| 4.9218284906240095 | -0.9781476007338056 | 0.20791169081775937 |
| 4.97418836818384 | -0.9659258262890682 | 0.2588190451025211 |
| 5.026548245743669 | -0.9510565162951536 | 0.3090169943749472 |
| 5.078908123303498 | -0.9335804264972021 | 0.3583679495452995 |
| 5.1312680008633285 | -0.9135454576426011 | 0.4067366430757997 |
| 5.183627878423159 | -0.891006524188368 | 0.4539904997395466 |
| 5.235987755982989 | -0.8660254037844386 | 0.5 |
| 5.288347633542818 | -0.8386705679454243 | 0.5446390350150266 |
| 5.340707511102648 | -0.8090169943749476 | 0.5877852522924729 |
| 5.393067388662478 | -0.7771459614569713 | 0.6293203910498368 |
| 5.445427266222309 | -0.743144825477394 | 0.6691306063588585 |
| 5.497787143782138 | -0.7071067811865477 | 0.7071067811865474 |
| 5.550147021341968 | -0.6691306063588581 | 0.7431448254773942 |
| 5.602506898901797 | -0.6293203910498378 | 0.7771459614569706 |
| 5.654866776461628 | -0.5877852522924734 | 0.8090169943749472 |
| 5.707226654021457 | -0.5446390350150278 | 0.8386705679454236 |
| 5.759586531581288 | -0.49999999999999967 | 0.8660254037844388 |
| 5.811946409141117 | -0.45399049973954697 | 0.8910065241883678 |
| 5.8643062867009474 | -0.40673664307580015 | 0.9135454576426009 |
| 5.916666164260777 | -0.35836794954530077 | 0.9335804264972015 |
| 5.969026041820607 | -0.3090169943749476 | 0.9510565162951535 |
| 6.021385919380437 | -0.2588190451025207 | 0.9659258262890683 |
| 6.073745796940267 | -0.20791169081775898 | 0.9781476007338057 |
| 6.126105674500097 | -0.15643446504023112 | 0.9876883405951377 |
| 6.178465552059927 | -0.10452846326765342 | 0.9945218953682733 |
| 6.230825429619756 | -0.05233595624294437 | 0.9986295347545738 |
| 6.283185307179585 | -1.133107779529596e-15 | 1 |
The graph shows Wave 2 leading Wave 1 by π/2: at the same horizontal coordinate, Wave 2 is one quarter-cycle further through its oscillation. Always name which wave leads or lags when the question asks for direction, because the magnitude π/2 alone does not specify it.
4. Common Mistakes
- Using degrees in a formula that expects radians (phase differences are in rad).
- Mixing up Δ x (path difference) and x (position).
- Forgetting that 2π multiples represent the same phase.
- Giving only a positive phase magnitude when the question asks which oscillation leads or lags.
5. Exam Tips
- Write the fraction first, then multiply by 2π:
- Δφ = 2π(Δ x/λ) or 2π(Δ t/T).
- If the question is about “in phase” / “antiphase”, convert your answer to a multiple of π.
6. Worked Examples
Modelled example 1
Phase difference from path difference
Problem
Study the worked solution
Find the cycle fraction
Method
The separation is one quarter of a wavelength.Reason
A full wavelength represents one complete 2π phase cycle.Working
Δ x/λ = 0.30/1.2 = 0.25Convert fraction to phase
Method
The phase difference is π/2 rad.Reason
Multiply the fraction of a spatial cycle by 2π.Working
Δφ = 2π(0.25) = π/2 rad
Guided practice 2
Time delay from phase difference
Problem
Try this before viewing the solution
Hints
Hint 1: convert phase to cycle fraction
View solution step by step
Extract the cycle fraction
Method
2π/3 is one third of a complete phase cycle.Reason
One full cycle is 2π radians.Working
Δφ/2π = 1/3Apply the fraction to time
Method
The delay is 0.20 s.Reason
A one-third-cycle delay is one third of the period.Working
Δ t = (1/3)(0.60) = 0.20 s
Common misconception 3
In phase or antiphase?
Learner claim
Try this before viewing the solution
View solution step by step
Include the full separation
Method
The phase difference is 3π.Reason
The remaining half-wavelength after one full wavelength contributes another π.Working
Δφ = 2π(1.5) = 3πReduce the physical relation
Method
3π is equivalent to π modulo 2π.Reason
Adding a full cycle does not change the relative state.Working
3π-2π = πClassify
Method
The points are antiphase, not in phase.Reason
An odd multiple of π represents half a cycle of separation.Working
Δφ = (2n + 1)π
Examiner practice 4
Path difference from phase difference
Examination question
Try this before viewing the solution
View solution step by step
State the relation
1 markMethod
Use Δφ = 2πΔ x/λ.Reason
Phase is being related to a spatial path difference.Working
Δφ = 2π(Δ x)/λFind the path fraction
1 markMethod
Δ x/λ = 3/4.Reason
Divide the stated phase by one full 2π cycle.Working
(Δ x)/λ = (3π/2)/2π = 3/4State the path difference
1 markMethod
Δ x = 3λ/4.Reason
The result is requested relative to wavelength.Working
Δ x = (3/4)λ
Self-mark with the mark scheme
Compare your response with each mark point. Select a point only when your response contains that evidence.
Self-mark the relation, phase fraction and final path difference.
Challenge 5
Phase difference from frequency and time delay
Independent transfer
Try this before viewing the solution
Hints
Hint 1: create the missing period
View solution step by step
Find the period
Method
T = 4.0 × 10⁻³ s.Reason
Frequency gives cycles per second, so its reciprocal gives seconds per cycle.Working
T = 1/250 = 4.0 × 10⁻³ sForm the delay fraction
Method
The 1.0 ms delay is one quarter of a period.Reason
1.0 ms = 1.0 × 10⁻³ s.Working
Δ t/T = 0.25Convert to phase
Method
The phase-difference magnitude is π/2 rad.Reason
A quarter cycle corresponds to a quarter of 2π.Working
Δφ = 2π(0.25) = π/2 rad
7. Mind Stretchers
Mind stretcher 1: Same phase, different answersExtension
A student finds Δφ = 5π for a phase difference question. Another student writes Δφ = π.
Are they both correct? Explain.
Show Answer
Yes.
5π and π differ by 4π = 2(2π), which is two full cycles. Adding/subtracting 2π does not change the physical state, so the phase relationship is the same.
Mind stretcher 2: Lag vs lead (equivalent phase differences)Extension
Wave 2 lags wave 1 by 3π/2 rad.
Write an equivalent phase difference in the range 0 to 2π, and state whether you could also describe wave 2 as leading wave 1.
Show Answer
Lagging by 3π/2 is equivalent to a phase difference of: 2π-3π/2 = π/2
So wave 2 lags by 3π/2 rad is the same as wave 2 leading by π/2 rad (a quarter cycle).
Mind stretcher 3: Optional (Enrichment)Extension
A. Link to interference language
Phase difference is used heavily in interference:
- constructive interference: Δφ = 2π n
- destructive interference: Δφ = (2n + 1)π
Continue with the next resource in this course.
Course and syllabus information
- Course
- GCE A-Level H2 Physics
- Edition
- GCE A-Level H2 Physics 2027