Inertial Frames and Non-inertial Frames

Key idea: Learn what makes a frame inertial, how Newton’s laws change in accelerating/rotating frames, and how to use (and interpret) fictitious forces.

  • GCE A-Level H3 Physics 2027
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Learning objectives

  • state that a frame of reference is a set of coordinates that can be used to determine positions and times of events in that frame
  • show an understanding that Newton’s laws of motion are obeyed in all inertial frames of reference

An inertial frame is a frame of reference where Newton’s laws hold in their standard form (no extra “made-up” forces needed). This lesson sets the language you’ll need for Galilean transformations and the centre of mass frame later in the H3 syllabus.

1. Definitions (Must Know)

  • Frame of reference: A set of coordinates + a clock used to assign positions and times to events.
  • Event: Something that happens at a particular place and time (e.g. “the ball hits the floor”), described by (x, y, z, t) in a chosen frame.
  • Inertial frame: A frame in which a free particle (net force = 0) moves with constant velocity (Newton’s first law holds), hence Newton’s laws apply without modification.
  • Non-inertial frame (enrichment): A frame that is accelerating and/or rotating relative to an inertial frame; Newton’s laws can still be used, but only if fictitious forces are introduced.
  • Symbols used in this lesson: u relative speed (m s⁻¹), h height (m), g ≈ 9.81 m s⁻² near Earth, m mass (kg), vector a₀ frame acceleration (m s⁻²), v speed (m s⁻¹), r radius (m), a_c centripetal acceleration (m s⁻²).

2. Key Ideas (What Earns Marks)

  • Newton’s laws are obeyed in all inertial frames. There is no “preferred” inertial frame for mechanics.
  • Different inertial observers can disagree on position, velocity, and the shape of a path, but they should still be able to explain the motion using the same physical laws.
  • A practical “test” of inertial-ness: in your frame, if an object with no net force does not move in a straight line at constant speed, your frame is not inertial (or it is only an approximation).

Quick comparison (use a table when asked to compare):

FeatureInertial frameNon-inertial frame
Free particle (net force = 0)Straight line, constant speedAppears to accelerate/curve
Newton’s lawsStandard formNeed fictitious forces to keep F = ma usable
Typical examplesTrain at constant velocity (approx.)Accelerating bus, rotating carousel

3. Detailed Explanations

A. What a frame of reference really is

A frame of reference is not just “where you stand”. You must specify:

  • an origin and axes (coordinates), and
  • how time is measured (a clock in that frame).

Only after that can you talk meaningfully about “the position at time t”.

B. Why constant-velocity frames are inertial (Galilean idea)

Suppose frame S' moves at constant velocity u relative to inertial frame S along the x-axis. The Galilean relations are:

x' = x - ut; t' = t

Differentiate with respect to time:

v' = v - u; a' = a

So acceleration is the same in both frames. If Newton’s second law holds in S: ∑ F = ma then it also holds in S' because the same real forces act on the object and a' = a.

C. The “ball tossed in a plane/train” example (what changes, what doesn’t)

  • In the plane (inertial, approximately): The passenger throws the ball straight up. They see a vertical path because the ball has no horizontal velocity relative to them.
  • On the ground (also inertial, approximately): The ball has the plane’s horizontal velocity as well as vertical motion under gravity, so the path is a parabola.

Both observers still explain the motion using the same forces (mainly weight, ignoring air resistance), and both use the same constant vertical acceleration g.

4. Common Mistakes

  • Writing “inertia frame” instead of inertial frame.
  • Thinking an inertial frame must be at rest; any frame moving at constant velocity relative to an inertial frame is also inertial.
  • Concluding “parabolic path” means “different laws”; the path shape depends on the observer’s velocity, not on whether Newton’s laws hold.
  • Treating the Earth’s surface as perfectly inertial in every situation (it’s often a good approximation, but not exact).

5. Exam Tips

  • Use mark-scheme-safe phrasing: “An inertial frame is one in which Newton’s laws of motion are obeyed.”
  • If asked to justify “no preferred inertial frame”, describe a closed experiment done entirely inside a constant-velocity vehicle (train/plane) that cannot detect its uniform motion.
  • State your assumption when needed: “Air resistance negligible, so the only force is weight, giving constant acceleration g.”

6. Worked Examples

Modelled example 1

Dropping a ball inside a moving train

Core

Problem

A train moves at constant velocity u. A passenger drops a ball from rest relative to the train from height h. Describe the path seen in the train and ground frames.
Study the worked solution
  1. Classify the frames

    Method

    The constant-velocity train and ground are treated as inertial frames.

    Reason

    Their relative velocity is constant, so no fictitious force is needed.

    Working

    a_frame = 0
  2. Describe the train view

    Method

    The ball falls straight down with acceleration g.

    Reason

    It has no horizontal velocity relative to the train when released.

    Working

    x' = constant, y = h-(1/2)gt²
  3. Describe the ground view

    Method

    The ball follows a parabola.

    Reason

    It retains horizontal speed u while accelerating vertically.

    Working

    x = ut, y = h-(1/2)gt²

Guided practice 2

Acceleration seen in two inertial frames

About 4 min

Problem

Frame S' moves at constant velocity u relative to inertial frame S. A particle has acceleration a in S. Determine a'.

Try this before viewing the solution

Hints

Hint 1: start from velocity
Write v' = v-u.
Hint 2: differentiate
The frame velocity u is constant.
View solution step by step
  1. Transform velocity

    Method

    v' = v-u.

    Reason

    The frames differ by a constant Galilean boost.

    Working

    v' = v-u
  2. Differentiate

    Method

    a' = a.

    Reason

    du/dt = 0 for constant relative velocity.

    Working

    a' = dv'/dt = dv/dt-du/dt = a

Common misconception 3

A frictionless puck in an accelerating bus (fictitious force)

Find and correct the mistake

Learner claim

A bus accelerates forward at a₀ = +2.0 m s⁻². A 0.50 kg puck on its frictionless floor appears to accelerate backward. A learner says a real backward force must act. Find the bus-frame acceleration and explain what is wrong with the claim.

Try this before viewing the solution

Cause in the bus-frame description

View solution step by step
  1. Start in the ground frame

    Method

    aₓ = 0.

    Reason

    No horizontal real force acts on the frictionless puck.

    Working

    ∑ Fₓ = 0 ⇒ aₓ = 0
  2. Transform acceleration

    Method

    a'ₓ = -2.0 m s⁻².

    Reason

    The bus frame accelerates at + a₀ relative to the inertial frame.

    Working

    a'ₓ = aₓ-a₀ = 0-2.0 = -2.0 m s⁻²
  3. Introduce the frame force

    Method

    F_(fict,x) = -1.0 N.

    Reason

    A fictitious force -ma₀ restores the usual F = ma' form within the bus frame.

    Working

    F_(fict,x) = -(0.50)(2.0) = -1.0 N

Examiner practice 4

“Effective gravity” in an accelerating elevator

3 marks

Examination question

An elevator accelerates upward at a₀ = 1.5 m s⁻². A mass is at rest relative to it. State whether the elevator frame is inertial and calculate the effective gravitational-field magnitude in that frame. [3 marks]

Try this before viewing the solution

View solution step by step
  1. Classify the frame

    1 mark

    Method

    The elevator frame is non-inertial.

    Reason

    It accelerates relative to an inertial frame.

    Working

    a₀ ≠ 0
  2. Set the effective direction

    1 mark

    Method

    The fictitious acceleration is downward, adding to gravity.

    Reason

    It acts opposite the elevator’s upward acceleration.

    Working

    g_eff = g + a₀
  3. Calculate

    1 mark

    Method

    g_eff = 11.31 m s⁻².

    Reason

    Add the two downward acceleration magnitudes.

    Working

    g_eff = 9.81 + 1.5 = 11.31 m s⁻²

Challenge 5

A turning car (rotating frame intuition)

Minimal support

Independent transfer

A car turns in a circle of radius 50 m at speed 15 m s⁻¹. A 60 kg passenger is at rest relative to the car. Find the centripetal acceleration and the fictitious-force magnitude and direction used in the rotating car frame.

Try this before viewing the solution

Hints

Hint 1: separate inertial and rotating views
First find the inward acceleration seen from the ground; the rotating-frame fictitious force points oppositely.
View solution step by step
  1. Calculate centripetal acceleration

    Method

    a_c = 4.5 m s⁻² inward.

    Reason

    Circular motion requires a_c = v²/r toward the centre.

    Working

    a_c = 15²/50 = 4.5 m s⁻²
  2. Find the frame-force magnitude

    Method

    F_fict = 270 N.

    Reason

    The rotating-frame term has magnitude ma_c.

    Working

    F_fict = (60)(4.5) = 270 N
  3. Give its direction

    Method

    The fictitious force points outward.

    Reason

    It is opposite the inward acceleration of the rotating car frame.

    Working

    vector F_fict points away from the centre

7. Mind Stretchers

Mind stretcher 1: Is a lab on Earth an inertial frame?Extension

Earth rotates, so a lab frame is (strictly) non-inertial. When is it still a good approximation to treat it as inertial?

One way to think about it

Compare the rotation-related accelerations to g. If the “extra” accelerations (e.g. centripetal due to Earth’s rotation) are tiny compared to g or other accelerations in the problem, treating the lab frame as inertial is a good approximation.

Mind stretcher 2: A quick “inertial test” you can do inside a sealed vehicleExtension

You are inside a sealed train carriage with no windows. Propose a simple experiment you could do inside the carriage that can detect whether the carriage is accelerating, but cannot detect whether it is moving at constant velocity.

One good answer

Release a small object (or roll a ball) and observe its motion relative to the carriage. If the carriage is accelerating, a free object will appear to accelerate opposite the carriage’s acceleration (straight-line constant-velocity motion fails), revealing a non-inertial frame. If the carriage moves at constant velocity, Newton’s first law still holds and the same internal experiment cannot distinguish it from rest.

8. Optional/Enrichment: Non-inertial Frames and Fictitious Forces

If your frame has acceleration vector a₀ relative to an inertial frame, objects can appear to “accelerate for no reason” in your frame. One way to keep Newton’s second law usable is to introduce a fictitious force: vector F_fict = -m vector a₀

This is useful intuition, but the detailed treatment of fictitious forces is better placed at university mechanics level:

Next step

Return to the Frames of Reference hub, or continue in sequence to Galilean Transformations.

Continue with the next resource in this course.

Course and syllabus information
Course
GCE A-Level H3 Physics
Edition
GCE A-Level H3 Physics 2027