Check what I know: Electric Fields · H2 Physics 9478

Check what you know about H2 Physics Electric Fields, practise what needs work, then check your progress and return for a later review.

GCE A-Level H2 Physics 2027

Learning goals

Work through the questions and use the feedback to plan revision.

This check is a formative starting point for the topic. Complete the questions, then use the feedback to choose the practice and repair work that follows.

Selected responses on this page do not establish H2 Physics mastery. Use your written problem solving and practical work as the stronger evidence of what you can do independently.

Check what I know

Check what I know: Electric Fields · H2 Physics 9478

A text-complete selected-response activity with quantities, units, directions, conditions, choices and feedback stated explicitly.

About 8 minutes

Check what I know

Answer 8 short questions. This starting check helps choose what to work on; it does not prove mastery.

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This check needs JavaScript to record answers. The reviewed questions are listed below for study.

Charges +3.0 μC and −2.0 μC are 0.40 m apart in air. Find the force magnitude and direction using 1/(4πε₀) = 8.99 × 10⁹ N m² C⁻².

0.337 N, attractive along the joining line
0.337 N, repulsive
3.37 × 10⁻⁶ N, attractive
0.135 N, repulsive

What are the electric-field magnitude and direction 0.20 m from a +4.0 nC point charge in air. Use k = 8.99 × 10⁹ N m² C⁻².

899 N C⁻¹ radially inward
180 N C⁻¹ outward
3.60 × 10⁻⁸ N C⁻¹ inward
899 N C⁻¹ radially outward

For an isolated charge distribution, choose zero electric potential at infinity. Which definition of potential at a point is correct?

Work done per unit mass in moving from the point to infinity
Charge stored per unit potential difference
Work done per unit positive charge by an external agent in bringing a small test charge from infinity to the point
Force per unit positive charge at the point

A +2.0 μC charge moves from 120 V to 450 V. What is the change in its electric potential energy?

+1.14 × 10⁻³ J
+6.6 × 10⁻⁴ J
−6.6 × 10⁻⁴ J
+2.3 × 10⁻⁴ J

Electric potential falls uniformly by 180 V over 0.030 m in the positive x-direction. What is the electric-field component Ex?

+6.0 × 10³ V m⁻¹
−6.0 × 10³ V m⁻¹
+5.4 V m⁻¹
−5.4 V m⁻¹

A nonrelativistic positive particle enters a uniform downward electric field with horizontal velocity. Ignore gravity and all other forces. What path begins?

A straight horizontal line because the initial velocity is horizontal.
A parabola bending upward because positive charges move opposite the field.
A parabola bending downward, with constant horizontal velocity and constant downward acceleration.
A circle at constant speed because the force is perpendicular to velocity.

Parallel plates have potential difference 600 V and separation 0.020 m. Ignoring edge effects, what is the uniform field strength?

12 V m⁻¹
1.2 × 10³ V m⁻¹
3.0 × 10⁷ V m⁻¹
3.0 × 10⁴ V m⁻¹

A 47 μF capacitor is charged to 12 V. Find its charge and stored energy, and identify the relevant graph area.

Q=0.255 C; U=1.53 J
Q=5.64 × 10⁻⁴ C; U=3.38 × 10⁻³ J; triangular area under V–Q graph
Q=3.92 C; U=6.77 × 10⁻³ J; rectangular area
Q=5.64 × 10⁻⁶ C; U=2.82 × 10⁻⁴ J

Practise

Practise: Electric Fields · H2 Physics 9478

A text-complete selected-response activity with quantities, units, directions, conditions, choices and feedback stated explicitly.

About 10 minutes

Practise

Questions are selected when you start. Use the feedback to decide what to practise next; this does not prove mastery.

Recent attempts

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Practise

Practise after feedback: Electric Fields · H2 Physics 9478

A text-complete selected-response activity with quantities, units, directions, conditions, choices and feedback stated explicitly.

About 10 minutes

Practise

Questions are selected when you start. Use the feedback to decide what to practise next; this does not prove mastery.

Recent attempts

History is stored only in this browser.

No completed attempts are saved yet.

This check needs JavaScript to record answers. The reviewed questions are listed below for study.

If one charge doubles and separation halves, state the Coulomb-force factor.

Force is unchanged.
Force increases by factor 8.
Force increases by factor 4.
Force doubles.

What are the field magnitude and direction 0.30 m from a +2.0 nC point charge in air. Use k = 9.0 × 10⁹ N m² C⁻².

66.7 N C⁻¹ outward
2.00 × 10⁻⁷ N C⁻¹ outward
200 N C⁻¹ radially outward
200 N C⁻¹ radially inward

Which option correctly describes how to derive the field expression for a point charge from Coulomb force and the field definition?

Field direction changes when the sign of the test charge changes.
E=F/q gives E=Q/(4πε₀r²), away from +Q and toward −Q.
E=Fq gives E=Qr²/(4πε₀), toward +Q.
E is potential energy per charge and has no direction.

A +4.0 μC point charge is at x = 0 and a +1.0 μC point charge is at x = 0.30 m, in vacuum. At what position between them is the electric field strength zero?

x = 0.15 m
x = 0.24 m
x = 0.20 m
x = 0.10 m

Two points lie on the same equipotential. What work does the electrostatic field do when a charge moves between them?

Negative work because field lines cross equipotentials.
Zero, because ΔV = 0 and Wfield = −qΔV.
qV, because every motion in a field requires work.
Positive work proportional to the path length.

The electric field does +0.80 mJ of work on a charge. What is the charge's potential-energy change?

−0.80 mJ
+0.80 mJ
0 J
−1.60 mJ

With zero potential at infinity, the distance from an isolated negative point charge doubles. How does its electric potential change?

It becomes positive and halves in magnitude.
It remains negative and falls to one quarter in magnitude.
It doubles in negative magnitude.
It remains negative and halves in magnitude.

A proton and an electron are placed separately in the same uniform electric field. Which force comparison is correct?

Their forces are equal in both magnitude and direction.
The electron has no force because its charge is negative.
Their forces have equal magnitudes and opposite directions.
The proton's force is larger because its mass is larger.

A nonrelativistic particle of charge q and mass m crosses plates of length L at horizontal speed u in a uniform transverse field E, without hitting either plate. Neglect other forces. What are its transit time and transverse acceleration?

Time u/L and acceleration mE/q
Time L/u and acceleration q/(mE)
Time √(2L/u) and acceleration E/q
Time L/u and acceleration qE/m

A −4.0 nC charge is placed in a uniform field of 2.5 × 10⁵ N C⁻¹ directed east. What force acts on it?

1.0 × 10¹⁴ N east
1.0 × 10⁻³ N west
1.0 × 10⁻³ N east
6.25 × 10⁻¹⁴ N west

Two parallel plates 4.0 mm apart are connected to a 200 V supply. What is the electric field strength between the plates, away from the edges?

50 V m⁻¹
5.0 × 10⁴ V m⁻¹
0.80 V m⁻¹
2.0 × 10⁻⁵ V m⁻¹

At fixed capacitance, voltage doubles. State the charge and energy factors.

Charge doubles and energy quadruples.
Both charge and energy double.
Charge quadruples and energy doubles.
Charge is unchanged and energy halves.

Check my progress

Check my progress: Electric Fields · H2 Physics 9478

A text-complete selected-response activity with quantities, units, directions, conditions, choices and feedback stated explicitly.

About 10 minutes

Check my progress

Answer 8 questions. If accepted, this result can contribute to your course progress.

Recent attempts

History is stored only in this browser.

No completed attempts are saved yet.

Check again

Check again: Electric Fields · H2 Physics 9478

A text-complete selected-response activity with quantities, units, directions, conditions, choices and feedback stated explicitly.

About 10 minutes

Check again

Answer 8 questions. If accepted, this result can contribute to your course progress.

Recent attempts

History is stored only in this browser.

No completed attempts are saved yet.

Review

Review: Electric Fields · H2 Physics 9478

A text-complete selected-response activity with quantities, units, directions, conditions, choices and feedback stated explicitly.

About 10 minutes

Review

Answer 8 questions. A scheduled review can contribute to your course progress only when it is due and the result is accepted.

Recent attempts

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Course and syllabus information

Course: GCE A-Level H2 Physics
Edition: GCE A-Level H2 Physics 2027

Check what I know: Electric Fields · H2 Physics 9478

Check what I know: Electric Fields · H2 Physics 9478

Starting check complete

Practise: Electric Fields · H2 Physics 9478

Practice complete

Practise after feedback: Electric Fields · H2 Physics 9478

Practice complete

Check my progress: Electric Fields · H2 Physics 9478

Progress check complete

Check again: Electric Fields · H2 Physics 9478

Progress check complete

Review: Electric Fields · H2 Physics 9478

Review complete