Compton Shift
Key idea: Apply the Compton wavelength-shift equation, interpret scattering spectra, and connect photon energy–momentum transfer with recoil electrons.
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The core idea
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Learning objectives
- Connect blackbody evidence, Planck quantisation, photon momentum, and Compton scattering.
In Compton scattering, a photon transfers energy and momentum to an electron. The scattered photon has lower energy, lower frequency, and greater wavelength. The angle-dependent wavelength shift provides direct evidence for particle-like photon momentum.
1. Model and equation
Assume an electron is initially free and at rest. If the photon is scattered through angle θ relative to its initial direction,
Δλ = λ'-λ = (h/mₑc)(1- cos θ)
The constant
λ_C = h/mₑc = 2.43 × 10⁻¹² m
is the electron Compton wavelength, so Δλ = λ_C(1- cos θ).
2. Angle dependence and limits
Compton shift factor versus scattering angle
The wavelength shift divided by the electron Compton wavelength follows one minus cosine theta.
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View figure data
| Scattering angle (°) | 1 − cos θ |
|---|---|
| 0 | 0 |
| 30 | 0.134 |
| 60 | 0.5 |
| 90 | 1 |
| 120 | 1.5 |
| 150 | 1.866 |
| 180 | 2 |
- At θ = 0°, Δλ = 0.
- At θ = 90°, Δλ = λ_C.
- At θ = 180°, Δλ = 2λ_C = 4.86 pm.
The shift for a free electron depends on angle and electron rest mass, not on incident intensity. The fractional energy loss does depend on the incident wavelength because E = hc/λ.
3. Interpreting observed spectra
A scattering target may produce both shifted and nearly unshifted components. Scattering by weakly bound or effectively free electrons gives the electron Compton shift. Interaction with a tightly bound electron can transfer momentum to the much heavier atom, making h/(Mc) and the resulting shift too small to resolve.
Do not say the unshifted component means “no interaction” in every case; it can reflect coherent or whole-atom scattering with negligible recoil energy.
4. Common mistakes
- Using the recoil-electron angle φ in the Compton shift equation instead of photon angle θ.
- Reporting Δλ as the outgoing wavelength. Use λ' = λ + Δλ.
- Saying a larger wavelength means the scattered photon gained energy. Photon energy is inversely proportional to wavelength.
- Treating intensity as photon energy. Greater intensity mainly means more photons per unit time.
- Using a non-relativistic electron energy relation in the derivation without checking recoil energy.
6. Worked Examples
Modelled example 1
Scattering through 90 degrees
Problem
Study the worked solution
Find the shift
Method
Δλ = 2.43 pm.Reason
1- cos 90° = 1.Working
Δλ = (2.43 pm)(1- cos 90°) = 2.43 pmAdd to the incident wavelength
Method
λ' = 73.4 pm = 0.0734 nm.Reason
Compton shift is defined as λ'-λ.Working
λ' = 71.0 + 2.43 = 73.4 pm
Guided practice 2
Maximum wavelength shift
Problem
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Hints
Hint 1: maximise the angular factor
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Choose back-scattering
Method
θ = 180°.Reason
This makes 1- cos θ = 2, its maximum.Working
Δλₘₐₓ = 2λ_CEvaluate
Method
Δλₘₐₓ = 4.86 pm.Reason
The electron Compton wavelength is 2.43 pm.Working
2(2.43 pm) = 4.86 pm
Challenge 3
Energy transferred to the electron
Independent transfer
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Hints
Hint 1: use photon energy loss
View solution step by step
Form the energy difference
Method
K = hc(1/λ-1/λ').Reason
Energy conservation gives the electron the photon’s lost energy.Working
K = E-E'Evaluate
Method
K ≈ 0.57 keV.Reason
The wavelength increase lowers the photon energy.Working
K = (1.240)(1/0.0710-1/0.0734) = 0.57 keV
7. Evidence statement
Mind stretcher 1: Connect the shift to the evidenceExtension
The wavelength change follows from treating light as particles with E = hf and p = h/λ colliding with electrons while conserving energy and momentum. A wave-only classical model does not produce this angle-dependent transfer relation.
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Course and syllabus information
- Course
- Advanced Physics
- Edition
- Advanced Physics