Planck’s Hypothesis
Key idea: Use quantised oscillator energies to explain the Planck blackbody distribution, its classical limit, and high-frequency suppression.
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The core idea
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Learning objectives
- Connect blackbody evidence, Planck quantisation, photon momentum, and Compton scattering.
Planck resolved the ultraviolet catastrophe by changing how matter exchanges energy with the electromagnetic field. Oscillators of frequency f can occupy only discrete energies separated by hf, so high-frequency excitation becomes unlikely when hf greatly exceeds the thermal energy scale kT.
1. Hypothesis and assumptions
For an oscillator of frequency f,
Eₙ = nhf, n = 0,1,2,…
The allowed energies are discrete, with adjacent levels separated by
Δ E = hf
Planck originally quantised the energy exchange of material oscillators in the cavity walls. The later photon model interprets a quantum of electromagnetic radiation as carrying energy hf. Keep those historical steps distinct even though modern calculations use the photon language naturally.
2. Mean energy and spectrum
Applying Boltzmann weighting to the allowed oscillator energies gives the mean thermal energy per mode
⟨E⟩ = hf/(e^(hf/(kT))-1)
Multiplying by the electromagnetic mode density gives the spectral energy density per unit frequency:
u_f(f,T) = ((8π hf³)/c³)1/(e^(hf/(kT))-1)
Here u_f df is the energy per unit volume in the frequency interval [f,f + df].
The wavelength form is not obtained by merely substituting f = c/λ; the interval also transforms. The result is
u_λ(λ,T) = ((8π hc)/λ⁵)1/(e^(hc/(λ kT))-1)
3. Why quantisation fixes the spectrum
Define the dimensionless ratio
x = hf/kT
- If x≪1, then e^x-1 ≈ x. Hence ⟨E⟩ ≈ kT, recovering classical equipartition and the Rayleigh–Jeans limit.
- If x≫1, then ⟨E⟩ ≈ hf e^(-x). The exponential factor overwhelms the increasing number of modes and suppresses the high-frequency spectrum.
Thus Planck’s law agrees with classical physics where classical physics works, but remains finite where the classical model diverges.
4. Photon relations
For a photon in vacuum,
E = hf = hc/λ
and the relativistic massless-particle relation E = pc gives
p = E/c = h/λ
This photon momentum is the key input to Compton scattering.
5. Common mistakes
- Starting n at one and excluding the zero-energy state in Planck’s original oscillator model.
- Saying all energies in nature must be integer multiples of one universal amount. The spacing is hf and depends on oscillator frequency.
- Treating hf as the energy of the oscillator at every temperature. It is the spacing between adjacent levels; the mean energy depends on T.
- Substituting f = c/λ into a spectral density without transforming the interval.
- Describing quantisation as an arbitrary high-frequency cutoff. The suppression follows continuously from the Boltzmann factor.
6. Worked Examples
Modelled example 1
Spacing of oscillator energies
Problem
Study the worked solution
Apply Planck's quantum
Method
Δ E = 4.0 × 10⁻¹⁹ J = 2.5 eV.Reason
Adjacent oscillator energies are separated by hf.Working
Δ E = hf = (6.63 × 10⁻³⁴)(6.0 × 10¹⁴) = 4.0 × 10⁻¹⁹ J
Guided practice 2
Testing the classical limit
Problem
Try this before viewing the solution
Hints
Hint 1: compare with unity
View solution step by step
Calculate the ratio
Method
x = 0.016.Reason
Use absolute temperature and consistent SI constants.Working
x = ((6.63 × 10⁻³⁴)(1.0 × 10¹¹))/((1.38 × 10⁻²³)(300)) = 0.016Select the limit
Method
Equipartition is a good approximation.Reason
x≪1 makes e^x-1 ≈ x and hence ⟨E⟩ ≈ kT.Working
x≪1
Challenge 3
High-frequency suppression
Independent transfer
Try this before viewing the solution
Hints
Hint 1: use the mean-energy factor
View solution step by step
Evaluate the factor
Method
⟨E⟩/(hf) = 4.54 × 10⁻⁵.Reason
The ratio is 1/(e¹⁰-1).Working
(⟨E⟩)/hf = 1/(e¹⁰-1) = 4.54 × 10⁻⁵Interpret
Method
The mode is thermally populated only very weakly.Reason
The quantum spacing is ten times the thermal scale.Working
hf≫ kT
7. Model check
Mind stretcher 1: Planck distribution limit checkExtension
The Planck distribution must approach Rayleigh–Jeans at low frequency and fall exponentially at high frequency. Checking both limits is more reliable than memorising the full expression without its assumptions.
Next: Compton Shift.
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Course and syllabus information
- Course
- Advanced Physics
- Edition
- Advanced Physics