Quantum Wells & Tunneling Toolkit (IPhO Quantum)
IPhO quantum toolbox for 1D wells and barriers: region solutions, boundary matching, parity tricks, and fast tunneling estimates.
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Wells and barriers are the standard “solve once, reuse forever” quantum problems. In olympiad settings, you are rarely asked to solve a new differential equation from scratch. You are asked to (1) write the correct region solutions, (2) apply boundary conditions correctly, and (3) estimate tunneling or bound-state scales quickly.
- Sketch V(x) and mark regions where E > V (oscillatory) and E < V (exponential).
- Write the region solutions using k or κ.
- Enforce boundary conditions: ψ and dψ/dx continuous (for finite steps).
- Use symmetry: even/odd parity in symmetric wells halves the work.
- For tunneling, the exponent is the main result: T ∼ exp(-2κ a).
1. Definitions (Must Know)
A. Time-independent Schrodinger equation (1D)
-(ħ²/2m)d²ψ/dx² + V(x)ψ = Eψ
In a region of constant potential V, define: k = square root of ((2m(E-V))/ħ²) (E > V) κ = square root of ((2m(V-E))/ħ²) (E < V)
B. Standard region solutions
- If E > V (classically allowed): oscillatory ψ(x) = Ae^ikx + Be^(-ikx)
- If E < V (classically forbidden): exponential ψ(x) = Ce^(κ x) + De^(-κ x)
C. Boundary conditions (finite potential steps)
For a finite jump in V(x) at some boundary:
- ψ is continuous,
- dψ/dx is continuous.
D. Reflection and transmission
For a 1D scattering setup, define:
- transmission coefficient T (probability of passing through),
- reflection coefficient R (probability of reflecting).
For a single barrier with no loss: T + R = 1.
E. Tunneling estimate (rectangular or WKB)
For a rectangular barrier of width a with E < V₀: T ∼ exp(-2κ a), κ = square root of ((2m(V₀-E))/ħ²)
More generally (WKB form), between turning points x₁ and x₂: T ∼ exp(-2∫_x₁^x₂ square root of ((2m(V(x)-E))/ħ²) dx)
2. Key Ideas (What Earns Marks)
- Classify regions by E-V. The sign decides the functional form.
- Use parity in symmetric wells. Even/odd solutions reduce unknown constants.
- Quantization comes from “no blow-up”. Bound states require ψ to decay outside the well.
- Tunneling is exponential. Most problems only need the exponent correctly.
- Check limits. As barrier width grows, T must decrease rapidly; as barrier height drops, T must increase.
3. Detailed Explanations
A. Infinite square well (the reference model)
For an infinite well of width L (wavefunction zero at both walls), the allowed energies are: Eₙ = n²π²ħ²/2mL², n = 1,2,3,…
Key scaling: Eₙ ∝ n² and Eₙ ∝ 1/L².
B. Finite square well (what changes)
For a finite well, the wavefunction leaks into the classically forbidden region, so:
- energy levels shift downward relative to an infinite well of the same width,
- there are only finitely many bound states (set by depth and width),
- matching at boundaries gives transcendental equations (often solved graphically or approximated).
Fast estimate for the number of bound states (order-of-magnitude): N ∼ (L/π) square root of (2mV₀/ħ²)
C. Rectangular barrier tunneling (what to remember)
For E < V₀ and a “thick” barrier, the main result is: T ∼ exp(-2κ a)
This one line often earns most of the marks because it captures the dominant dependence on:
- width a,
- mass m,
- barrier excess V₀-E.
D. Quantum reflection even when E > V
Even if E > V everywhere, there can be reflection at a sharp step because the wavelength changes (mismatch of k). This shows up in the boundary-condition algebra and is a classic exam trap.
4. Common Mistakes
- Writing exponential solutions in the wrong region (mixing up k and κ).
- Forgetting that bound states must not diverge at infinity (set the growing exponential coefficient to zero).
- Dropping the derivative continuity condition at finite steps.
- Treating tunneling like a small linear correction (it is exponential in a).
- Mixing amplitudes with probabilities: T is a probability, not a wave amplitude.
5. Exam Tips
- Always start by sketching V(x) and labeling regions with k or κ.
- If the potential is symmetric, state “use even/odd parity” explicitly.
- For tunneling estimates, show the exponent clearly: ln T ∼ -2κ a.
- Use quick constants if allowed: ħ²/2mₑ ≈ 3.81 eV Ų, hc ≈ 1240 eV nm.
6. Worked Examples
A. Infinite well energy scale (electron in a 1 nm box)
An electron is in a 1D infinite square well of width L = 1.0 nm. Estimate E₁ and the transition energy Δ E = E₂-E₁ (in eV).
Click here to show/hide solution
For an infinite well: Eₙ = n²π²ħ²/2mL²
Use ħ²/(2mₑ) ≈ 3.81 eV Ų and L = 1.0 nm = 10 Å: E₁ ≈ (π² × 3.81)/10² eV ≈ (9.87 × 3.81)/100 eV ≈ 0.38 eV
Since Eₙ ∝ n², E₂ = 4E₁ ≈ 1.5 eV.
So: Δ E = E₂-E₁ = 3E₁ ≈ 1.1 eV
B. Tunneling probability through a rectangular barrier (exponent estimate)
An electron with energy E = 2 eV hits a barrier of height V₀ = 5 eV and width a = 0.50 nm. Estimate the transmission probability.
Click here to show/hide solution
Here V₀-E = 3 eV and E < V₀.
Use: T ∼ exp(-2κ a), κ = square root of ((2mₑ(V₀-E))/ħ²)
A useful numeric form for electrons is: κ (nm⁻¹) ≈ 5.12 square root of ((V₀-E) (eV)) So: κ ≈ 5.12 square root of 3 nm⁻¹ ≈ 8.9 nm⁻¹
Then: 2κ a ≈ 2 × 8.9 × 0.50 ≈ 8.9 Hence: T ∼ e^(-8.9) ∼ 1 × 10⁻⁴
Pre-factors can change this by a factor of a few, but the exponential is the main result.
7. Mind Stretchers
A. Reflection at a potential step even when E > V₀
A particle with E > V₀ encounters a sudden step from V = 0 to V = V₀. Show that there is still reflection, and find the reflection coefficient in terms of k₁ and k₂.
Click here to show/hide hint and solution
Region 1: k₁ = square root of (2mE/ħ²), region 2: k₂ = square root of (2m(E-V₀)/ħ²).
Write: ψ₁ = Ae^ik₁x + Be^(-ik₁x), ψ₂ = Ce^ik₂x
Match ψ and dψ/dx at the boundary. Solving the two equations gives the amplitude reflection coefficient: B/A = (k₁-k₂)/(k₁ + k₂)
So the probability reflection coefficient is: R = ((k₁-k₂)/(k₁ + k₂))² This is nonzero whenever k₁ ≠ k₂ (a wavelength mismatch).
- In a double-barrier structure, transmission can become close to 1 at special energies (resonant tunneling). What phase condition is being satisfied?
- For a finite well, why do higher bound states leak more strongly into the classically forbidden region?
8. Practice
- Do 2 short drills: one infinite well energy scaling, one rectangular barrier tunneling exponent.
- Then do 1 symmetry drill: write even and odd solutions for a symmetric well and state the boundary conditions.
Syllabus and review details
No official syllabus alignment is listed for this lesson.