Fuses & Circuit Breakers
Key idea: O Level practical electricity: how fuses and circuit breakers protect circuits, why they are connected in the live wire, and how to choose a fuse rating.
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The core idea
On this page
Learning objectives
- Explain electrical heating in common appliances
- Apply P = VI
- Apply E = VIt
- Calculate electrical energy and cost in kWh
- Identify the hazard from damaged insulation
- Identify the hazard from overheating cables
- Identify the hazard from damp conditions
- Explain how fuses and circuit breakers protect circuits
- Choose and justify an appropriate fuse rating
- Explain why metal casings are earthed
- Explain why double-insulated appliances do not need an earth wire
- State the meanings and roles of live, neutral and earth
- Describe the wiring of a mains plug
- Explain live-wire placement of switches, fuses and circuit breakers
1. Definition
A. Fuse
A fuse is a safety device that melts and breaks the circuit when the current is too large.
B. Circuit breaker
A circuit breaker is an automatic switch that trips and breaks the circuit when the current is too large (and it can be reset).
You should be able to explain how fuses and circuit breakers protect a circuit, choose a suitable fuse rating and explain why these devices are fitted to the live wire.
2. Key Ideas
- Fuses and circuit breakers protect against large current (overload / short circuit) which can cause cable overheating and fires.
- They are connected in the live wire, so when they open the circuit the appliance is disconnected from the live supply.
- Fuse: melts (“blows”) → must be replaced. Circuit breaker: trips → can be reset.
- Fuse rating selection:
- find normal current: I = P/V
- choose a rating just above the normal current (next available rating)
3. Detailed Explanations
A. What hazard are they preventing?
Large currents heat up wires and cables. If insulation melts, wires can touch and sparks can occur, causing an electric fire.
Fuses and circuit breakers are designed to break the circuit when the current becomes dangerously large.
B. Why must they be in the live wire?
If a fuse/circuit breaker is in the neutral wire, the appliance may still be connected to the live wire even after the protection device opens the circuit. Parts of the appliance can still be at live potential, which is a shock hazard.
C. Choosing a fuse rating (O Level method)
- Calculate normal current:
I = P/V
- Choose a fuse rating that is just above the normal current.
Examples of common ratings (country-dependent): 3 A, 5 A, 13 A.
Never replace a blown fuse with thicker wire or foil. A higher-than-needed rating can allow dangerous currents to flow before the fuse blows.
4. Common Mistakes
- Choosing a fuse rating that is too high (“it won’t blow”) → unsafe.
- Saying a fuse is mainly to prevent electric shock (its main role is to prevent overheating/fire from large currents).
- Putting the fuse/circuit breaker in the neutral wire in explanations/diagrams.
- Forgetting units (A, V, W).
5. Exam Tips
- Use the chain: fault → large current → heating → fuse melts / breaker trips → circuit opens (in live wire).
- For fuse ratings: compute I = P/V, then choose a rating slightly higher.
- If asked “why live wire?”, write: “so the appliance is disconnected from the live supply when the circuit opens”.
6. Worked Examples
Modelled example 1
Choosing a fuse rating
Problem
Study the worked solution
Calculate normal current
Method
Use I = P/V.Reason
The appliance rating gives power at the supply voltage.Working
I = 600/240 = 2.5 AChoose the protective rating
Method
Select the 3 A fuse.Reason
It is the smallest available rating above the 2.5 A operating current.Working
2.5 A < 3 A
Guided practice 2
Maximum power before a breaker trips
Problem
Map the current limit to a power limit
Hints
Hint 1: relationship
Hint 2: conversion
View solution step by step
Calculate at the trip current
Method
Multiply voltage by current.Reason
The stated current is the breaker’s limiting current.Working
P = (240)(20) = 4800 W = 4.8 kW
Common misconception 3
Live vs neutral placement
Learner response
Distinguish stopping current from isolating live potential
View solution step by step
Identify the incomplete idea
Method
Acknowledge that opening neutral can stop normal current.Reason
The circuit is broken, but that alone does not make the appliance isolated from live.Working
Neutral open: normal current = 0, but the live connection can remain.State the safe placement
Method
Place the fuse in live.Reason
When it melts, the appliance is disconnected from the live supply and exposed internal parts are not left live through that connection.Working
Live open → appliance isolated from live supply.
Examiner practice 4
Fuse rating for a heater
Examination question
Calculate before choosing
View solution step by step
Find normal current
2 marksMethod
Use I = P/V.Reason
The rating describes normal power at the supply p.d.Working
I = 1100/240 = 4.58 ASelect and justify
2 marksMethod
Choose the 5 A fuse.Reason
It is the smallest available rating above 4.58 A.Working
4.58 A < 5 A≪13 A
Self-mark with the mark scheme
Compare your response with each mark point. Select a point only when your response contains that evidence.
Self-mark formula, current, rating and justification.
Challenge 5
Is the fuse too low?
Rating-evaluation transfer
Compare the existing rating with normal current
Hints
Hint 1: normal current
Hint 2: comparison
View solution step by step
Calculate normal current
Method
Use I = P/V.Reason
The existing fuse must be compared with operating current.Working
I = 1000/240 ≈ 4.17 AEvaluate and replace
Method
Reject 3 A and choose 5 A.Reason
3 A is below normal current; 5 A is the next suitable standard rating above it.Working
3 A < 4.17 A < 5 A
7. Mind Stretchers
Mind stretcher 1: Too-high fuse ratingExtension
A 60 W lamp is protected by a 13 A fuse. Is this safer or less safe than using a 3 A fuse? Explain.
Show Answer
Less safe. A 13 A fuse allows much larger currents to flow before it blows, so the wire/cable could overheat in a fault before the fuse breaks the circuit. A 3 A fuse is closer to the normal current and provides better protection for the lamp circuit.
Mind stretcher 2: Short circuit vs overloadExtension
Which situation is more likely to produce the larger current: a short circuit or an overload? Explain briefly.
Show Answer
A short circuit. The resistance becomes very small, so current becomes very large (I = V/R). Overload increases current too, but usually not as dramatically as a short circuit.
8. Practice and next step
- Calculate normal current first, then justify the smallest standard fuse rating above it.
- Test fault-path and rating decisions in the Practical Electric Circuitry Lab.
- Next, connect protective devices to Live, Neutral & Earth.
Continue with the next resource in this course.
Course and syllabus information
- Course
- SEC G3 Physics
- Edition
- SEC G3 Physics 2027