Uncertainty

Key idea: Learn how to estimate measurement uncertainties, distinguish random vs systematic errors, and propagate uncertainties for +, −, ×, ÷ and powers.

  • GCE A-Level H2 Physics 2027
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Learning objectives

  • Assess random, systematic and propagated uncertainties.
Undergraduate note

These “propagation rules” are a fast, conservative way to estimate uncertainties. In university labs you’ll also meet statistical approaches (standard deviation, standard error), but the logic here is still a useful baseline.

1. Definitions (Must Know)

  • Error: the difference between a measured value and the true value (true value is usually unknown).
  • Uncertainty, Δ x: an estimate of the possible range of values around a measurement x.
  • Absolute uncertainty, Δ x: uncertainty written in the same unit as x (e.g. 2.50 ± 0.05 m).
  • Fractional uncertainty: (Δ x)/x (no unit).
  • Percentage uncertainty: (Δ x)/x × 100%.
  • Random error: unpredictable variation between repeated readings; causes scatter. Repeats reveal the spread, and averaging reduces the random contribution to the mean.
  • Systematic error: consistent bias (e.g. zero error, calibration error); affects accuracy; not reduced by averaging.
  • Precision: how close repeated readings are to each other (small scatter).
  • Accuracy: how close a measurement is to the true value.

2. Key Ideas (What Earns Marks)

  • Quote readings with sensible uncertainty:
    • analogue scale: ± half the smallest division,
    • digital reading: typically ± 1 in the last displayed digit (unless stated otherwise),
    • repeated readings: random uncertainty ≈ half the range.
  • For a derived quantity, propagate uncertainties using the standard A Level rules (worst-case approach):
    • If Y = a ± b: Δ Y = Δ a + Δ b
    • If Y = ab or Y = a/b: (Δ Y)/Y = (Δ a)/a + (Δ b)/b
    • If Y = aⁿ: (Δ Y)/Y = |n| (Δ a)/a
  • If the expression is awkward, use numerical substitution (max–min):
    • compute Yₘₐₓ and Yₘᵢₙ using the extreme values,
    • then Δ Y ≈ (Yₘₐₓ-Yₘᵢₙ)/2.
  • Quote the final answer so the value and uncertainty match:
    • uncertainty: usually 1 s.f. (2 s.f. is common if it starts with 1 or 2),
    • value: same decimal place as the uncertainty.

3. Detailed Explanations

A. Estimating uncertainty in a measurement

Use the information the question gives you.

Common defaults:

  • Analogue scale: uncertainty ≈ ± half the smallest division.
  • Digital display: uncertainty ≈ ± 1 in the last displayed digit.
  • Repeats (random uncertainty): uncertainty ≈ half range.

Example (percentage given): If a timer is specified as ± 0.1% and you measure t = 638.5 ms, then Δ t = 0.001 × 638.5 ≈ 0.6 ms So quote t = 638.5 ± 0.6 ms.

B. Random vs systematic errors (what examiners want)

  • Random error mainly affects precision. Repeating reveals its size; averaging reduces its effect on the mean but does not remove the scatter in the measurements.
  • Systematic error mainly affects accuracy. Averaging does not remove it (you must correct/calibrate).

If you see “zero error”, “calibration error”, “parallax always in the same direction”, treat it as systematic.

C. Propagating uncertainties: + and − (absolute uncertainties)

If Y = a + b or Y = a - b, add absolute uncertainties: Δ Y = Δ a + Δ b

Reason: you are estimating a worst-case uncertainty range.

D. Propagating uncertainties: × and ÷ (fractional/percentage uncertainties)

If Y = ab or Y = a/b, add fractional uncertainties: (Δ Y)/Y = (Δ a)/a + (Δ b)/b

You can do this in percentages as well: %Δ Y = %Δ a + %Δ b

E. Powers (including roots)

If Y = aⁿ: (Δ Y)/Y = |n|(Δ a)/a

Examples:

  • Y = a²: percentage uncertainty doubles.
  • Y = square root of a = a^(1/2): percentage uncertainty halves.

F. Uncertainty budget (spot the dominant term)

A quick way to decide what to improve is to break the result into percentage contributions from each measurement.

Example (simple pendulum): g = 4π²L/T² So, %Δ g ≈ %Δ L + 2%Δ T

Example uncertainty budget (pendulum g)Percentage uncertainty contributions from length and (double) time term for a simple pendulum g calculation.Example uncertainty budget (pendulum g)Percentage contribution (%)
Here %Δ L = 0.25% and 2%Δ T = 2.2%, so improving the timing method gives the biggest gain.
Data table
CategoryContribution
Length, L0
Time, T (×2)2

G. Numerical substitution (max–min method)

Use this when the expression is awkward.

Workflow:

  1. Compute the best estimate Y using best values.
  2. Compute Yₘₐₓ using values that make Y as large as possible.
  3. Compute Yₘᵢₙ using values that make Y as small as possible.
  4. Estimate: Δ Y ≈ (Yₘₐₓ-Yₘᵢₙ)/2 and %Δ Y ≈ 100% × (Δ Y)/Y.

4. Common Mistakes

  • Adding percentage uncertainties for addition/subtraction (wrong). For + and -, add absolute uncertainties.
  • Adding absolute uncertainties for multiplication/division (usually wrong). For × and ÷, add fractional/percentage uncertainties.
  • Rounding too early (causes noticeable drift in uncertainty questions). Keep guard digits until the end.
  • Quoting an answer with inconsistent precision (e.g. 2.345 ± 0.1). Match decimal places.
  • Treating a systematic error as “reduced by repeats”.

5. Exam Tips

  • Write the rule you are using before you substitute (it signals method marks).
  • If one measurement has a much larger percentage uncertainty, it usually dominates the final uncertainty.
  • If you are asked for an “uncertainty in Y”, state whether you are giving absolute or percentage.
  • A good final line format is:
    • Y = (value ± Δ Y) unit
    • or Y = value unit (± percentage)
  • Related: Dimensional Analysis (unit checks) and the A Level Practical Hub (evaluation + uncertainties in Paper 4).

Practical Lab

Use this workflow-first lab if you want the Paper 4 version of this topic rather than another static summary:

Practical Lab: Uncertainty & Error Propagation

Work through instrument readings, repeated data, propagation, and final reporting with an exam-style uncertainty workflow.

BetaA LevelPractical SkillsBest for: A Level Paper 4 uncertainty handling
  • Absolute vs Percentage Uncertainty
  • Repeated-Reading Estimate
  • Propagation Rules
  • Final Answer Reporting

Open the full interactive simulation on its own page

Use the standalone simulation page for the live controls, SVG scene, run modes, and scoring flow.

The lesson stays lightweight and links out to the dedicated simulation page.

6. Worked Examples

Modelled example 1

Addition/subtraction (absolute uncertainty)

Core

Problem

For L = x + y, x = 12.4±0.1 cm and y = 8.2±0.1 cm. Find L with uncertainty.
Study the worked solution
  1. Find the best estimate

    Method

    Add measured values.

    Reason

    The derived length is defined by addition.

    Working

    L = 12.4 + 8.2 = 20.6 cm
  2. Propagate absolute uncertainties

    Method

    Add the absolute uncertainties.

    Reason

    The conservative addition/subtraction rule operates in the quantity’s units.

    Working

    Δ L = 0.1 + 0.1 = 0.2 cm
  3. Report consistently

    Method

    State 20.6±0.2 cm.

    Reason

    Value and absolute uncertainty share units and decimal place.

    Working

    L = 20.6±0.2 cm.

Guided practice 2

Multiplication/division (percentage uncertainty)

About 6 min

Problem

V = 10.0±0.3 V and I = 1.3±0.2 A. Find R = V/I with uncertainty.

Try this before viewing the solution

Hints

Hint 1: division uses relative uncertainty
Convert each input uncertainty to a percentage, then add them.
View solution step by step
  1. Find resistance

    Method

    Calculate the best estimate.

    Reason

    R = V/I.

    Working

    R = 10.0/1.3 = 7.7 Ω
  2. Add percentage uncertainties

    Method

    Combine 3.0% and approximately 15%.

    Reason

    For division, conservative fractional uncertainties add.

    Working

    %Δ R = 3.0% + 15% = 18%
  3. Convert back to absolute

    Method

    Obtain approximately 1.4 Ω.

    Reason

    The final result is reported in ohms.

    Working

    Δ R = 0.18(7.7) = 1.4 Ω, R = 7.7±1.4 Ω

Common misconception 3

Power rule (common in Mechanics)

Find and correct the mistake

Learner claim

For h = 2.00±0.01 m and v ∝ h^(1/2), a learner assigns v the same 0.5% uncertainty as h. Diagnose the claim.

Try this before viewing the solution

Percentage uncertainty in v

View solution step by step
  1. Find height percentage uncertainty

    Method

    Divide absolute uncertainty by value.

    Reason

    Power rules act on fractional or percentage uncertainty.

    Working

    %Δ h = (0.01/2.00)100% = 0.5%
  2. Apply the exponent

    Method

    Multiply by 1/2.

    Reason

    For v ∝ h^(1/2), the relative uncertainty factor is the exponent magnitude.

    Working

    %Δ v = (1/2)(0.5%) = 0.25%

Examiner practice 4

Speed from distance/time

4 marks

Examination question

An athlete covers 100.00±0.01 m in 9.63±0.01 s. Find speed and absolute uncertainty. [4 marks]

Try this before viewing the solution

View solution step by step
  1. Find speed

    1 mark

    Method

    Divide distance by time.

    Reason

    v = d/t.

    Working

    v = 100.00/9.63 = 10.38 m s⁻¹
  2. Find input percentages

    1 mark

    Method

    Obtain 0.01% and 0.10%.

    Reason

    Each is absolute uncertainty divided by its value.

    Working

    %Δ d = 0.01%; %Δ t ≈ 0.10%.
  3. Propagate

    1 mark

    Method

    Add to approximately 0.11%.

    Reason

    Speed is a quotient.

    Working

    %Δ v ≈ 0.11%.
  4. Report absolute uncertainty

    1 mark

    Method

    State 10.38±0.01 m s⁻¹.

    Reason

    0.0011(10.38) ≈ 0.01 m s⁻¹.

    Working

    v ≈ 10.38±0.01 m s⁻¹.

Challenge 5

Uncertainty in gradient (max–min method)

Minimal support

Independent graph transfer

For a V-against-I graph, best-fit points are (0.20±0.01 A,2.10±0.05 V) and (0.80±0.01 A,8.40±0.05 V). Estimate resistance and gradient uncertainty using maximum and minimum acceptable gradients.

Try this before viewing the solution

Hints

Hint 1: choose opposite uncertainty-box corners
For the maximum gradient, maximise the vertical interval and minimise the horizontal interval; reverse both choices for the minimum.
View solution step by step
  1. Construct best and extreme gradients

    Method

    Calculate the best gradient, then the steepest and shallowest acceptable lines.

    Reason

    The uncertainty boxes bound plausible endpoint positions, and half the extreme-gradient range estimates gradient uncertainty.

    Working

    Best estimate gradient: R = (Δ V)/(Δ I) = (8.40-2.10)/(0.80-0.20) = 6.30/0.60 = 10.5 Ω

    To estimate uncertainty, find extreme gradients.

    Maximum gradient: maximise numerator and minimise denominator. Δ Vₘₐₓ = (8.40 + 0.05)-(2.10-0.05) = 6.40 V Δ Iₘᵢₙ = (0.80-0.01)-(0.20 + 0.01) = 0.58 A Rₘₐₓ ≈ 6.40/0.58 ≈ 11.0 Ω

    Minimum gradient: minimise numerator and maximise denominator. Δ Vₘᵢₙ = (8.40-0.05)-(2.10 + 0.05) = 6.20 V Δ Iₘₐₓ = (0.80 + 0.01)-(0.20-0.01) = 0.62 A Rₘᵢₙ ≈ 6.20/0.62 = 10.0 Ω

    So, Δ R ≈ (Rₘₐₓ-Rₘᵢₙ)/2 = (11.0-10.0)/2 = 0.5 Ω

    Final: R ≈ 10.5 ± 0.5 Ω

    Max–min gradients from the same two points

    Best-fit line and the steepest/shallowest plausible gradients based on the stated uncertainties.

    Best-fit line and the steepest/shallowest plausible gradients based on the stated uncertainties.Best-fit line and the steepest/shallowest plausible gradients based on the stated uncertainties.
    The error bars show each stated uncertainty box. The steepest acceptable line joins (0.21 A, 2.05 V) to (0.79 A, 8.45 V); the shallowest joins (0.19 A, 2.15 V) to (0.81 A, 8.35 V).
    Open full-size graph
    View figure data
    Values and uncertainty for Max–min gradients from the same two points
    SeriesCurrent (A)Current uncertaintyPotential difference (V)Potential difference uncertainty
    Measured points0.20.012.10.05
    Measured points0.80.018.40.05
    Best-fit gradient0.22.1
    Best-fit gradient0.88.4
    Max gradient0.212.05
    Max gradient0.798.45
    Min gradient0.192.15
    Min gradient0.818.35

7. Mind Stretchers

Mind stretcher 1: Numerical substitution (max–min)Extension

A student finds density from ρ = m/V where m = 52.3 ± 0.1 g and V = 19.5 ± 0.5 cm³. Use max–min to estimate ρ and Δ ρ.

Show Answer

Best estimate: ρ = 52.3/19.5 = 2.68 g cm⁻³

Extremes:

  • ρₘₐₓ = 52.4/19.0 = 2.76
  • ρₘᵢₙ = 52.2/20.0 = 2.61

So, Δ ρ ≈ (2.76-2.61)/2 = 0.075 g cm⁻³ ≈ 0.08 g cm⁻³

Final: ρ ≈ 2.68 ± 0.08 g cm⁻³

If you need SI units: 1 g cm⁻³ = (10⁻³ kg)/(10⁻⁶ m³) = 10³ kg m⁻³ So, ρ ≈ (2.68 ± 0.08) × 10³ kg m⁻³ ≈ (2680 ± 80) kg m⁻³

Mind stretcher 2: Uncertainty in g from a pendulum (power rule + multiplication)Extension

For a simple pendulum, g = 4π²L/T².

If L = 0.800 ± 0.002 m and T = 1.80 ± 0.02 s, estimate the percentage uncertainty in g.

Show Answer

%Δ g = %Δ L + 2%Δ T

%Δ L = 0.002/0.800 × 100% = 0.25% %Δ T = 0.02/1.80 × 100% ≈ 1.1%

So, %Δ g ≈ 0.25% + 2(1.1%) ≈ 2.5%

Mind stretcher 3: Optional (Enrichment)Extension

A. Standard deviation (beyond syllabus)

In the A Level syllabus, you do not need a rigorous statistical treatment.

If you meet standard deviation in other contexts: it is a measure of the spread of repeated readings around the mean. It is useful when you have many repeats and want a more formal uncertainty estimate than “half range”.

Continue with the next resource in this course.

Course and syllabus information
Course
GCE A-Level H2 Physics
Edition
GCE A-Level H2 Physics 2027