Motion and forces

Displacement, velocity and acceleration, motion graphs, the constant-acceleration equations, momentum and Newton's laws of motion, for H2 Physics.

  • GCE A-Level H2 Physics 2027
  • 5 lessons

Before you begin

Describe motion with signed quantities and graphs, then explain changes in motion with momentum and Newton’s laws.

Be comfortable with: scalars and vectors, because displacement, velocity, acceleration, momentum and force are all vectors with signs.

Learning goals
  • Interpret position, displacement, velocity and acceleration using equations and graphs.
  • Derive the uniformly accelerated motion equations from the definitions of velocity and acceleration.
  • Derive and apply uniformly accelerated motion equations with a stated sign convention.
  • Explain inertia and momentum, then apply Newton's laws using free-body diagrams.
Syllabus statements covered
  • show an understanding of and use the terms position, distance, displacement, speed, velocity and acceleration
  • use graphical methods to represent distance, displacement, speed, velocity and acceleration
  • identify and use the physical quantities from the gradients of position–time or displacement–time graphs and areas under and gradients of velocity–time graphs, including cases of non-uniform acceleration
  • derive, from the definitions of velocity and acceleration, equations which represent uniformly accelerated motion in a straight line
  • solve problems using equations which represent uniformly accelerated motion in a straight line, e.g. for bodies falling vertically without air resistance in a uniform gravitational field
  • show an understanding that mass is the property of a body which resists change in motion (inertia)
  • define and use linear momentum as the product of mass and velocity
  • state and apply each of Newton’s laws of motion: 1st law: a body at rest will stay at rest, and a body in motion will continue to move at constant velocity, unless acted on by a resultant external force; 2nd law: the rate of change of momentum of a body is (directly) proportional to the resultant force acting on the body and is in the same direction as the resultant force; 3rd law: the force exerted by one body on a second body is equal in magnitude and opposite in direction to the force simultaneously exerted by the second body on the first body
  • recall the relationship resultant force F = ma, for a body of constant mass, and use this to solve problems

How the ideas connect

Resultant force determines accelerationTwo horizontal free-body diagrams. Equal forces of 8 newtons left and right give zero resultant force and constant velocity, which can be zero. Forces of 4 newtons left and 8 newtons right give a 4 newton resultant to the right and acceleration to the right. Vertical forces balance and are omitted.Balanced forces8 N8 NResultant: 0 NConstant velocity (or rest)Unequal forces4 N8 NResultant: 4 N rightAcceleration to the right
A zero resultant means constant velocity, including rest. A non-zero resultant changes velocity. These illustrative diagrams show horizontal forces only; vertical forces balance.
  1. Describe the motion

    Use displacement, velocity and acceleration, with a chosen positive direction.

    Step 1
  2. Read the graphs

    Connect gradients and signed areas to changes in motion. Use constant-acceleration equations only when acceleration is constant.

    Step 2
  3. Explain the change

    Add the forces on one body. The resultant force determines how its momentum changes.

    Step 3
Explore the lessons

Lessons

Work through them in order.

Practise and check

Or choose

Topic reference

Quick reference

Read the graph

Gradient of displacement–time = velocity. Area under velocity–time = displacement.

Use a tangent for an instantaneous gradient. Displacement is in m; velocity in m s⁻¹.

Common pitfall

Area below the time axis is negative for displacement. Distance uses the magnitudes of the areas.

Check the condition

v = u + at and s = ut + (1/2)at²

Use signed values and constant acceleration. Time is in s; acceleration in m s⁻².

Common pitfall

An object can have zero velocity at an instant and still have non-zero acceleration.

Choose one body

∑ F = ma for constant mass.

Add all external forces on the chosen body. Force is in N; mass in kg.

Common pitfall

A third-law pair acts on two different bodies. It does not cancel in one body’s force diagram.

Complete quick-reference table
IdeaRelationNotes
displacement–time graphgradient = velocityuse a tangent for an instantaneous value
velocity–time graphgradient = acceleration; area = displacementarea below the axis is negative
acceleration–time grapharea = change in velocity
constant accelerationv = u + at
s = (1/2)(u + v)t
s = ut + (1/2)at²
v² = u² + 2asonly while a is constant
free falla = g = 9.81 m s⁻² downwardno air resistance
momentump = mva vector, in kg m s⁻¹
Newton’s second lawF = (Δ p)/(Δ t); F = ma for constant massF is the resultant force

Velocity–time graphs: compare shapes

Two velocity–time series from zero to five seconds. One rises from one to eleven metres per second with constant gradient two metres per second squared. The other remains at six metres per second.

Scroll across the figure to read all labels.

Two velocity–time series from zero to five seconds. One rises from one to eleven metres per second with constant gradient two metres per second squared. The other remains at six metres per second.Two velocity–time series from zero to five seconds. One rises from one to eleven metres per second with constant gradient two metres per second squared. The other remains at six metres per second.
Gradient gives acceleration; signed area between a velocity–time graph and the time axis gives displacement.
Open full-size graph
What to noticeThe rising solid line has constant positive gradient. The dashed horizontal line has zero gradient, while both enclose area representing displacement.
View figure data
Figure data: Velocity–time graphs: compare shapes
Time (s)Constant acceleration, a = 2 m s⁻²Constant velocity, a = 0 m s⁻²
016
136
256
376
496
5116

Core knowledge to remember

Definitions and core knowledge
  • Displacement is the change in position, with a direction. Distance is the total path length.
  • Velocity is the rate of change of displacement; acceleration is the rate of change of velocity.
  • Mass is the property of a body that resists change in its motion: its inertia.
  • Linear momentum is the product of mass and velocity.
  • Newton’s first law: a body at rest will stay at rest, and a body in motion will continue to move at constant velocity, unless acted on by a resultant external force.
  • Newton’s second law: the rate of change of momentum of a body is proportional to the resultant force acting on the body and is in the same direction as the resultant force.
  • Newton’s third law: the force exerted by one body on a second body is equal in magnitude and opposite in direction to the force simultaneously exerted by the second body on the first body.

Common mistakes

More mistakes to check
  1. Reading the height of a graph when the question needs its gradient or area.
  2. Cancelling areas above and below the time axis when finding a distance.
  3. Using the constant-acceleration equations over an interval in which the acceleration changes.
  4. Saying the acceleration is zero at the top of a vertical throw.
  5. Using one force instead of the resultant force in F = ma.
  6. Treating two forces on the same body as a third-law pair.
  7. Thinking a moving body needs a resultant force to keep moving at constant velocity.
  8. Assuming the normal force always equals the weight.