Periodic Motion

Key idea: Describe free oscillations, define period, frequency, angular frequency and phase, and plan reliable timing measurements (A Level Physics).

  • GCE A-Level H2 Physics 2027
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Learning objectives

  • Use oscillation quantities and describe free oscillations and their investigation.
  • Relate displacement, velocity, acceleration and phase in simple harmonic motion.

1. Definitions (Must Know)

A. Periodic motion

Periodic motion is motion that repeats itself after a fixed time interval.

B. Period, T (s)

The period, T, is the time taken for one complete cycle.

C. Frequency, f (Hz)

The frequency, f, is the number of cycles per second.

Relationship: T = 1/f and f = 1/T

D. Angular frequency, ω (rad s⁻¹)

Angular frequency, ω, is the rate of change of phase: ω = 2π f = 2π/T

E. Displacement and amplitude

  • displacement, x (m): distance from equilibrium (can be positive or negative)
  • amplitude, x₀ (m): maximum magnitude of displacement

F. Phase and phase difference

  • phase, φ (rad): where you are within a cycle
  • phase difference, Δφ (rad): how far one oscillation leads/lags another

G. Free oscillation

An ideal free oscillation repeats about equilibrium with no periodic driving and no energy gained from or lost to the environment. A restoring force still acts; “free” does not mean force-free.

Link: phase difference

Phase difference (two oscillations)

Two sine waves with the same frequency. Oscillation B lags oscillation A by a constant phase difference.

Scroll across the graph to read all labels.

Two sine waves with the same frequency. Oscillation B lags oscillation A by a constant phase difference.Two sine waves with the same frequency. Oscillation B lags oscillation A by a constant phase difference.
A phase difference is a horizontal shift. Here B lags A by Δφ = π/3 (one-sixth of a cycle), so the time delay is Δ t = (Δφ/2π)T.
Open full-size graph
View figure data
Values for Phase difference (two oscillations)
Phase angle, ωt (rad)A: sin(ωt)B: sin(ωt − π/3) (lags by π/3)
00-0.866
0.5240.5-0.5
1.0470.8660
1.57110.5
2.0940.8660.866
2.6180.51
3.14200.866
3.665-0.50.5
4.189-0.8660
4.712-1-0.5
5.236-0.866-0.866
5.76-0.5-1
6.2830-0.866

2. Key Ideas (What Earns Marks)

  • Always include units:
    • T in seconds, f in hertz, ω in rad s⁻¹.
  • Convert “revolutions per second” or “cycles per second” directly to frequency.
  • Use ω = 2π f when you see sine/cosine SHM forms like sin(ω t).
  • Measure several cycles and divide by the number of cycles to reduce the percentage timing uncertainty in T.

3. Detailed Explanations

A. Why ω = 2π f

One complete cycle corresponds to a phase change of 2π radians.

If there are f cycles per second, the phase changes by 2π f radians per second: ω = 2π f

B. Where these terms show up in SHM

In simple harmonic motion, displacement is often written in the form: x = x₀ sin(ω t + φ₀)

You do not need to memorise every variant. You mainly need:

  • x₀ is the amplitude
  • ω sets the period (T = 2π/ω)
  • φ₀ sets the starting point
Link: SHM equations and graphs

C. Investigating an oscillator

Use a motion sensor or video tracking to record displacement against time. Read T between equivalent points such as successive maxima, or time N complete cycles and calculate T = t/N. Repeat the measurement and compare the periods; amplitude should be kept within any approximation stated for the oscillator.

The displacement–time graph establishes periodicity. To establish SHM, you must additionally show that acceleration is proportional to -x, for example with a straight-line a–x graph through the origin.

4. Common Mistakes

  • Using T = 2π f (wrong; it is ω = 2π f and T = 1/f).
  • Mixing up f (Hz) and ω (rad s⁻¹).
  • Forgetting that phase must be in radians in expressions like sin(ω t).
  • Calling a motion SHM merely because it repeats.

5. Exam Tips

  • If you are given x = x₀ sin(ω t), read off ω directly and find T using T = 2π/ω.
  • If you are given “rpm”, convert to Hz first: f = rpm/60.
  • In an investigation, time several complete cycles rather than one whenever practical.

6. Worked Examples

Modelled example 1

Convert between T and f

Core

Problem

An oscillator has period T = 0.40 s. Find its frequency and interpret the result.
Study the worked solution
  1. Use reciprocal quantities

    Method

    Use f = 1/T.

    Reason

    Frequency counts cycles per second while period is seconds per cycle.

    Working

    f = 1/T
  2. Evaluate and interpret

    Method

    Obtain 2.5 Hz.

    Reason

    The oscillator completes 2.5 cycles per second.

    Working

    f = 1/0.40 = 2.5 Hz

Guided practice 2

Find ω from T

About 4 min

Problem

An oscillator has period 0.20 s. Find its angular frequency.

Try this before viewing the solution

Unit: rad s⁻¹

Hints

Hint 1: convert cycles to phase
Use ω = 2π/T.
View solution step by step
  1. Choose the relation

    Method

    Use ω = 2π/T.

    Reason

    Angular frequency is phase change per second.

    Working

    ω = 2π/T
  2. Evaluate

    Method

    Obtain 10π rad s⁻¹, or 31.4 rad s⁻¹.

    Reason

    A complete cycle advances phase by 2π radians.

    Working

    ω = 2π/0.20 = 10π rad s⁻¹

Common misconception 3

Convert rpm to ω

Find and correct the mistake

Learner claim

A motor rotates at 1800 rpm. A learner writes ω = 2π(1800) rad s⁻¹. Diagnose the error and find ω.

Try this before viewing the solution

Unit: rad s⁻¹

View solution step by step
  1. Repair the time unit

    Method

    Convert 1800 rpm to 30 Hz.

    Reason

    Angular frequency is required per second, not per minute.

    Working

    f = 1800/60 = 30 Hz
  2. Convert cycles to radians

    Method

    Obtain 60π rad s⁻¹ ≈ 188 rad s⁻¹.

    Reason

    Each revolution corresponds to 2π radians.

    Working

    ω = 2π f = 2π(30) = 60π rad s⁻¹

Examiner practice 4

Read T, f, and ω from an SHM equation

4 marks

Examination question

An oscillator has displacement x = 0.050 sin(8t + π/6) in SI units. State its amplitude and angular frequency, then calculate its period and frequency. [4 marks]

Try this before viewing the solution

View solution step by step
  1. Read the amplitude

    1 mark

    Method

    x₀ = 0.050 m.

    Reason

    The coefficient outside the sine is the maximum displacement.

    Working

    x₀ = 0.050 m.
  2. Read angular frequency

    1 mark

    Method

    ω = 8 rad s⁻¹.

    Reason

    The coefficient of t is angular frequency.

    Working

    ω = 8 rad s⁻¹.
  3. Find the period

    1 mark

    Method

    T = 0.785 s.

    Reason

    Use T = 2π/ω.

    Working

    T = 2π/8 = 0.785 s
  4. Find the frequency

    1 mark

    Method

    f = 1.27 Hz.

    Reason

    Use f = 1/T = ω/(2π).

    Working

    f = 8/2π = 1.27 Hz

Challenge 5

Phase difference to time delay

Minimal support

Independent transfer

Two oscillations have frequency 5.0 Hz. Oscillation B lags A by π/3. Find the time delay and state which oscillation reaches the same phase point later.

Try this before viewing the solution

Hints

Hint 1: convert phase to a cycle fraction
π/3 is the fraction (π/3)/(2π) of one period.
View solution step by step
  1. Find the period

    Method

    T = 0.20 s.

    Reason

    The oscillations complete 5.0 cycles per second.

    Working

    T = 1/f = 0.20 s
  2. Convert phase fraction to time

    Method

    Obtain Δ t = 0.033 s.

    Reason

    A phase difference of π/3 is one sixth of a full 2π cycle.

    Working

    Δ t = ((π/3)/2π)(0.20) = 0.033 s
  3. Interpret the lag

    Method

    B reaches each matching phase point 0.033 s after A.

    Reason

    “B lags A” fixes the order, not just the delay magnitude.

    Working

    A leads; B follows.

7. Mind Stretchers

Mind stretcher 1: What does “phase constant” change?Extension

Two SHM motions have the same x₀ and ω, but different φ₀.

What is the same, and what is different?

Show Answer

Same: amplitude and period/frequency (since x₀ and ω are unchanged).

Different: where the motion starts at t = 0 (the displacement/velocity at t = 0).

Mind stretcher 2: How many cycles occur in a time interval?Extension

An oscillator has frequency f = 12 Hz. How many complete cycles occur in 3.0 s?

Show Answer

Number of cycles: N = ft = (12)(3.0) = 36

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Course and syllabus information
Course
GCE A-Level H2 Physics
Edition
GCE A-Level H2 Physics 2027