Current electricity

Electric current, e.m.f., potential difference, resistance and the I–V graphs of a metal, a filament lamp and a diode, for G3 Pure and O-Level Physics.

  • SEC G3 Physics 2027
  • 8 lessons

Before you begin

Current electricity is about charge flowing round a circuit and the energy it carries. The lessons start with current as a flow of charge, add e.m.f. and p.d. as energy per coulomb, then use resistance to link the two and compare the I–V graphs of a metal, a filament lamp and a diode.

Be comfortable with: static electricity, because current is charge in motion.

Learning goals
  • State current as rate of charge flow measured in amperes
  • Distinguish conventional current from electron flow
  • Apply charge equals current multiplied by time
  • Define source e.m.f. as work done per unit charge around a circuit
  • Calculate total e.m.f. for sources in series
  • Define component potential difference as work done per unit charge
  • State resistance as potential difference divided by current
  • Apply resistance equals potential difference divided by current
  • Apply wire-resistance proportionalities for length and cross-sectional area
  • Describe the effect of temperature on metallic resistance
  • Sketch and interpret required current–voltage characteristics
Syllabus statements covered
  • state that current is the rate of flow of charge and that it is measured in amperes
  • distinguish between conventional current and electron flow
  • recall and apply the relationship charge = current × time to new situations or to solve related problems
  • state that the electromotive force (e.m.f.) of a source is the work done per unit charge by the source in driving charges around a complete circuit and that it is measured in volts
  • calculate the total e.m.f. where several sources are arranged in series
  • state that the potential difference (p.d.) across a component in a circuit is the work done per unit charge in driving charges through the component and that it is measured in volts
  • state that resistance = p.d. / current
  • apply the relationship R = V / I to new situations or to solve related problems
  • recall and apply the relationship of the proportionality between resistance and the length and cross-sectional area of a wire to new situations or to solve related problems
  • describe the effect of temperature increase on the resistance of a metallic conductor
  • sketch and interpret the I-V characteristic graphs for a metallic conductor at constant temperature (ohmic conductor), for a filament lamp and for a semiconductor diode.

Lessons

Work through them in order.

Practise and check

Or choose

Topic reference

Quick reference

QuantitySymbolEquationUnit
currentII = Q/tampere (A), 1 A = 1 C s⁻¹
chargeQQ = Itcoulomb (C)
e.m.f.EE = W/Qvolt (V), 1 V = 1 J C⁻¹
p.d.VV = W/Qvolt (V)
resistanceRR = V/Iohm (Ω), 1 Ω = 1 V A⁻¹
cells in seriesEₜₒₜₐₗadd aiding e.m.f.s, subtract opposing onesvolt (V)
wire resistanceRR ∝ L, R ∝ 1/Aohm (Ω)
Required O-Level current–voltage characteristicsThree qualitative current-against-potential-difference graphs. The ohmic metallic conductor is a straight line through the origin in quadrants one and three. The filament lamp is a symmetric curve through the origin that becomes less steep as magnitude of voltage rises. The semiconductor diode has almost zero reverse current and a steep forward-current rise.Metallic conductorconstant temperatureVI0Filament lamptemperature changesVI0Semiconductor diodeone-way conductionVI0straight line through originsymmetric curve through originreverse current ≈ 0Qualitative shapes only; axis scales are not shared.
Required O-Level current–voltage characteristicsThree qualitative current-against-potential-difference graphs. The ohmic metallic conductor is a straight line through the origin in quadrants one and three. The filament lamp is a symmetric curve through the origin that becomes less steep as magnitude of voltage rises. The semiconductor diode has almost zero reverse current and a steep forward-current rise.Metallic conductorconstant temperatureVI0straight line through originFilament lamptemperature changesVI0symmetric curve through originSemiconductor diodeone-way conductionVI0reverse current ≈ 0Qualitative shapes only; axis scales are not shared.
Use the complete graph: the metallic conductor and filament lamp pass through the origin in opposite quadrants, while the diode conducts strongly in only one direction.

Core knowledge to remember

  • Current is the rate of flow of charge. Conventional current flows from the positive terminal round the circuit to the negative terminal; in a metal, electrons drift the other way.
  • E.m.f. is the work done per unit charge by a source in driving charges around a complete circuit.
  • P.d. is the work done per unit charge in driving charges through a component.
  • Resistance is p.d. divided by current. A metal at constant temperature obeys Ohm’s law: I ∝ V.
  • A hotter metal has a larger resistance, because its ions vibrate more and the electrons collide with them more often.
  • An ammeter goes in series and has a very small resistance; a voltmeter goes in parallel and has a very large resistance.

Common mistakes

  1. Using minutes instead of seconds in Q = It.
  2. Mixing up e.m.f. (energy given by a source) and p.d. (energy transferred in a component).
  3. Calling every use of R = V/I Ohm’s law; it defines resistance at one point.
  4. Treating the gradient of an I-against-V graph as the resistance. For a straight line through the origin it is 1/R; for a curve, use V/I at the point.
  5. Halving the resistance for a doubled diameter: the area, and so the factor, is four.
  6. Sketching only the positive half of an I–V graph, or drawing a diode’s graph the same on both sides.