In many situations, several electrical devices are connected to the same power supply. There are two basic methods of connecting resistors or other devices together. They are called series and parallel connections.

The derivation of the formula for effective resistance for series and parallel resistors can be found at the end of this post.

## Effective Resistance Of Resistors

### Resistors In Series

If individual resistors are connected from end to end, the resistors are said to be connected in series. The effective resistance, R, of three resistors of resistances R_{1}, R_{2}; and R_{3} connected in series (shown in the figure) is given by:

$ R = R_{1} + R_{2} + R_{3}$

In general, if there are n resistors in series, the effective resistance R is given by:

$ R = R_{1} + R_{2} + …. + R_{n}$

**Note:** In a series connection, the effective resistance, R, is always larger than the largest of the individual resistances.

### Resistors In Parallel

If each end of individual resistors are connected together to one another as one, the resistors are said to be connected in parallel.

The effective resistance, R, of three resistors of resistances R_{1}, R_{2} and R_{3} connected in parallel is given by:

$ \frac{1}{R} = \frac{1}{R_{1}} + \frac{1}{R_{2}} + \frac{1}{R_{3}}$

In general, if there are n resistors in parallel, the effective resistance R is given by:

$ \frac{1}{R} = \frac{1}{R_{1}} + \frac{1}{R_{2}} + …. + \frac{1}{R_{n}}$

**Note:** In a parallel connection, the effective resistance, R, is always smaller than the smallest of the individual resistances.

## Derivation of effective resistance for series and parallel resistors

### Series Resistors

When the resistors are in series, the current through each resistor is the **same**. We shall denote the current as I. Each resistor will have its own voltage. If the resistance of the resistors are different ($R_{1} \neq R_{2} \neq R_{3} \neq \dots$), the voltage drop across each resistor will be different ($V_{1} \neq V_{2} \neq V_{3} \neq \dots$).

We know that resistance is given by $R = \frac{V}{I}$.

Hence the effective resistance of the whole stretch of resistor is given by:

$$R_{eff} = \frac{V_{total}}{I}$$

However, we know that

$$V_{total} = V_{1} + V_{2} + V_{3} + \dots$$

Substitute that into the effective resistance equation, we have:

$$\begin{eqnarray} R_{eff} &=& \frac{V_{total}}{I} \\ &=& \frac{V_{1} + V_{2} + V_{3} + \dots}{I} \\ &=& \frac{V_{1}}{I} + \frac{V_{2}}{I} + \frac{V_{3}}{I} + \dots \\ &=& R_{1} + R_{2} + R_{3} + \dots \end{eqnarray}$$

### Parallel Resistors

When the resistors are in parallel, the voltage drop across each resistor is the same. We shall denote the voltage as V. Each resistor will have its own voltage. If the resistance of the resistors are different ($R_{1} \neq R_{2} \neq R_{3} \neq \dots$), the current through each resistor will be different ($I_{1} \neq I_{2} \neq I_{3} \neq \dots$).

We know that resistance is given by $R = \frac{V}{I}$.

Hence the effective resistance of the whole stretch of resistor is given by:

$$R_{eff} = \frac{V}{I_{total}}$$

However, we know that

$$I_{total} = I_{1} + I_{2} + I_{3} + \dots$$

Substitute that into the effective resistance equation, we have:

$$\begin{eqnarray} R_{eff} &=& \frac{V}{I_{total}} \\ R_{eff} &=& \frac{V}{I_{1} + I_{2} + I_{3} + \dots} \\ \frac{1}{R_{eff}} &=& \frac{I_{1} + I_{2} + I_{3} +\dots}{V} \\ \frac{1}{R_{eff}} &=& \frac{I_{1}}{V} + \frac{I_{2}}{V} + \frac{I_{3}}{V} + \dots \\ \frac{1}{R_{eff}} &=& \frac{1}{R_{1}} + \frac{1}{R_{2}} + \frac{1}{R_{3}} + \dots \end{eqnarray}$$

If 3 resistor is connected in parallel how to calculate the effective resistance…?? Plzz reply me as soon as possible…

Since 1/R effect. =1/R1 +1/R2+1/R3……..1/Rn for parallel series

Here there are 3 resistor

Therefore to find effective resistance apply the above equation up to 1/R3

thanks for the efforts