**Assuming that the jaws of the vernier calipers are tightly closed, find the zero error of the vernier calipers below.**

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**Show Answer**

$$-0.06 \text{cm}$$

**Show Answer**

$$+0.06 \text{cm}$$

**Show Answer**

$$-0.04 \text{cm}$$

**Show Answer**

$$+0.03 \text{cm}$$

**Show Answer**

$$-0.03 \text{cm}$$

**Show Answer**

$$+0.10 \text{cm}$$

### Vernier Caliper Practice:

Wow so simple

Dad?

Got it, so easy

I taught the last one was supposed to be 0.20cm

Good

Hmm

Pliz I don’t understand how u re coming up with zero errors. More explanation pliz coz am lost

Can someone tell how to find zero error in a vernier Caliper . I don’t understand. Pls help thank you

nani?!

ur not alone

Why is the zero error in the last one 0.1 cm, can someone please explain?

Beacause it is counted from backwards and the line which correspobds is the 10th line which is also know as 0.10 cm (from right to left

It’s right as follows;

Main scale reading (top) = 0.1cm

Vernier scale reading (bottom) = 0.00mm

Thus 0.1 + 0.00 = 0.10cm or 0.1cm

Note; since the vernier scale is located at the right handside of the 0 MAIN SCALE= +

Hence, the answer is +0.10cm

It’s right as follows;

Main scale reading (top) = 0.1cm

Vernier scale reading (bottom) = 0.00mm

Thus 0.1 + 0.00 = 0.10cm or 0.1cm

Note; since the vernier scale is located at the right hand side of the 0 MAIN SCALE= + and it is counted from the back.

Hence, the answer is +0.10cm

I’m confused…how do u find out the value of zero error???

Thank you so much for this . It’s very good

good? how do u find this easy

i cant understand can u plz explain

I understood positive zero error’s measurements but I don’t know how you find out all of the above negative zero errors. Suppose in the top most figure, zero error should have been -0.04cm as 4th line of vernier scale is in line with main scale, not the 6th one, so how did you calculate it to be 0.06cm. Could you explain it please?

In the case of negative zero errors, the coinciding line which is suppose 0.04 in the first case is subtracted from the highest possible reading and hence the error is reported as 0.04 – (0.10) = -0.06com

Asher,when its negative you start counting from the back of the callipers, thats just how l cae to understand that

The zero correction should be added from the reading which is measured

such a fruitful website for me

Me too