A quick guide on how to read a vernier caliper. A vernier caliper outputs measurement readings in **centimetres (cm)** and it is precise up to 2 decimal places (E.g. 1.23 cm).

**Note:** The measurement-reading technique described in this post will be similar for vernier calipers which output measurement readings in **inches**.

## Measurement Reading Technique For Vernier Caliper

In order to read the measurement readings from vernier caliper properly, you need to remember two things before we start. For example, if a vernier caliper output a measurement reading of **2.13 cm**, this means that:

- The
**main scale**contributes the main number(s) and one decimal place to the reading (E.g. 2.1 cm, whereby 2 is the main number and 0.1 is the one decimal place number) - The
**vernier scale**contributes the second decimal place to the reading (E.g. 0.03 cm)

Let’s examine the image of the vernier caliper readings above. We will just use a two steps method to get the measurement reading from this:

- To obtain the
**main scale**reading: Look at the image above, 2.1 cm is to the**immediate left of the zero**on the vernier scale. Hence, the main scale reading is 2.1 cm - To obtain the
**vernier scale**reading: Look at the image above and look closely for an**alignment of the scale lines**of the main scale and vernier scale. In the image above, the aligned line correspond to 3. Hence, the vernier scale reading is 0.03 cm.

In order to obtain the **final measurement reading**, we will add the main scale reading and vernier scale reading together. This will give 2.1 cm + 0.03 cm = 2.13 cm.

### In a nutshell

Use the following formula:

$$ \text{Obtained reading} = \text{Main scale reading} \, + \, \text{Vernier scale reading} $$

Let’s go through another example to ensure that you understand the above steps:

**Main scale** reading: 10.0 cm (Immediate left of zero)

**Vernier scale** reading: 0.02 cm (Alignment of scale lines)

**Measurement reading**: 10.02 cm

## Compensating For Zero Error

### In a nutshell

Use the following formula:

$ \text{Correct reading} = \text{Obtained reading} \, – \, \text{Zero error} $

where $\text{zero error}$ can be either **negative** (the “0” of vernier scale is **left** of the “0” of the main scale) or **positive** (the “0” of vernier scale is **right** of the “0” of the main scale)

### Explanation

Now, we shall try with zero error. If you are not familiar on how to handle zero error for vernier calipers, I suggest that you read up on Measurement of Length.

The reading on the top is the measurement obtained and the reading at the bottom is the zero error. Find the actual measurement. (Meaning: get rid of the zero error in the measurement or take into account the zero error)

Measurement with zero error: 3.34 cm

Zero error: – 0.04 cm (negative because the vernier scale is to the left)

Measurement without zero error: $3.34 \, – ( \, – 0.04) = 3.38$ cm

If you do not understand the subtraction of the negative zero error from the measurement, please read on. Since the zero error is -0.04 cm, this means that all measurements taken by the vernier calipers will be *SMALLER* by 0.04cm. Hence, you will have to *ADD* 0.04 cm to *ALL* measurements in order to get the *TRUE* measurement. The subtraction is done in the above case is to have an elegant way of obtaining a resultant addition: $3.34 + 0.04 = 3.38$ and to make it *COMPATIBLE* with positive zero error. This means that once you have determined the nature of the zero error (positive or negative), you can just subtract the zero error and be sure that your final answer is correct.

Consider a zero error of +0.04 cm. With my method, $3.34 \, – (+ 0.04) = 3.30$ cm.

**Normal method:** Since the zero error is +0.04 cm, this means that all measurements taken by the vernier calipers will be larger by 0.04 cm. Hence, you will have to *SUBTRACT* 0.04 cm from *ALL* measurements in order to get the true measurement. The final calculation will be $3.34 \, – 0.04 = 3.30$ cm, which is the same as my method.

**Note:** I hope that I did not confuse you. Drop a comment below if you encounter any difficulties.

## More Vernier Caliper Practice:

## Self-Test Questions For Vernier Calipers

### Where on the vernier calipers would you read to obtain the main scale reading?

**Show/Hide Answer**

The main scale reading is obtained from the reading on the main scale that is at the** immediate left of the zero** on the vernier scale.

### Where on the vernier calipers would you read to obtain the vernier scale reading?

**Show/Hide Answer**

The vernier scale reading is obtained from the reading on the main scale that has an **alignment of the scale lines** of the main scale and vernier scale.

### What is the smallest possible reading (in cm) of a vernier caliper?

**Show/Hide Answer**

The smallest possible reading of a vernier caliper is 0.01 cm.

If you still do not understand the concept, there is a **very useful** simulation of the vernier calipers: Vernier Caliper Simulation (Source)

I don’t understand why the scale on my gauge starts about 4mm from the left-hand jaw? So if I measure something, it gives a reading of say 5mm, but when I measure distance between jars with a tape measure, t’s actually 9mm?

Thank you.

XD XD

Thank you.

What’s about the different various vernier resolution e.g.

0.02 mm

0.05 mm

imprinted on top of vernier moving part ?

It means that the measurement has an increment of 0.02 or 0.05. The lower the resolution, the higher the accuracy and precision.

Let’s say the actual measurement is 4.57. If you use a caliper with a least count/resolution of 0.05, most probably your measurement reading will be 4.55. If you use a caliper with a 0.02 resolution, your measurement reading will be 4.56 OR 4.58 which is closer to the actual value.

yes

bruh no one gives a damn about this crap tbh :/

Olodo

You did not know book

zeke

zeke

Main scale reading = 43cm

The vernier scale reading = 0.15cm

The sum of MRS and VRS = 43.15cm

Thanks so much

Nice

Great , -now I can solve any question concerning vernier callipers

It tells that if it’s negative ,instead of reading it to left to right which is the answer will gonna be 0.06 cm, you need to read it right to left and start to 0.01, and the answer will 0.04. I hope you understand

I didn’t understand the zero error

Well articulated

Plz I don’t understand anything

lmfao same

Same here

You just check where the original scale and the Vernier scale meet that’s the answer 😊

Main scale reading = 43cm

The vernier scale reading = 0.15cm

The sum of MRS and VRS = 43.15cm

I appreciate the clear explanations on this site.

However, I think there may be an error in the second figure under “Compensating for Zero Error.” To my reading, the error appears to be – 0.06 cm, not – 0.04 cm.

Am I missing something?

Yes. It confused me at first too, until I thought of it as “-0.1cm + 0.06cm” since you have to add the vernier reading to the scale reading immediately to the left of zero.

Thank you

Thank you

You’re wrong check well

Awesome. Thanks for the help. This article was very comprehensive.

Hello there! What is the biggest possible reading on vernier scale?? Can anybody plz kindly tell me?😊

Hello there! What is the biggest possible reading on vernier scale?

I was not clear about the topic but when I read this page, It was crystal clear to me. Thanks for being so helpful.

In the illustration of the “zero error” measurement, the zero of the vernier scale appears to be slightly less that 1/2 way between the zero and the first hash mark of the main scale, but the alignment on the vernier scale seems to clearly occur on the “6”, making the zero measurement -0.06?

The explanations were comprehensive and the tests made it more understandable.

thank you so much I come back to this every test haha

Nice

can you please shade more light on measurement reading technique. l am an o level student . please email me

The Self-Test Questions are very helpful.

See main scale is just immediately left to zero

Vernier scale division is where two lines Aline

Vernier scale reading is=vernier scale division into 0.01

Total reading=vernier scale reading+main scale

It’s very easy concept

And this site really helped me

Still confused may be a demonstration lecture will help otherwise

After getting the vernier scale reading can I simply devide by 100 to get the actual reading. And if so, why is 100 chosen for this devision?

Not understand

Even I need help, hope to catch up as i continue studying.

I still don’t get the workout here because its different from the ones in the textbook. Please can anyone help me out here?

can anybody help me how to read a vernier scale/caliper

I did not really understand

Thanks a lottt

this work is not clear to me me well. please anybody hear to explain to me clearly

It really helped

Mmmm me its confusing me a bit,

i think the value of zero error is 0.03

Thanks very much, but i stil have a litle misundestanding on reading some scale, eg. from MS u start frnm the first figu

can you fully showing out by arrows pointing directly to the readings of the scale on how you really get the measurement of the zero error ?

I really don’t understand is the anyone that can help me out

How do i measure zero error from the scale

Thanks for the excellent explanation including the part about the zero error which though very simple was never something that ever occurred to me.

Parveen Kumar village buradehar distt

Jind teh julana Haryana

I love your simple approach so much.The only part that is a bit unclear for me,is the zero error.

For the vernier.

When the zero mark on the vernier scale is to the left of the zero mark on the main scale,the error is negative.

For the mic screw gauge.

When the zero mark of the thimble scale is below the the horizontal line of the sleeve scale, the error is positive. Otherwise its negative.

i think the value of zero error is 0.03

If the vernier scale is 1-10 and the reading is 10, do we add 0.1 to the main scale reading?

Thks for this it really help

Please to be sincere I don’t understand how u people are doing the reading? How many unit does those slash line have?

I think there something wrong with that zero error….it should be -0.06 not -0.04

Yep I thought that too

Thanks for this… I would like to clarify one thing: when you read the negative zero error, it seems that you are counting backwards from the right-most mark on the Vernier scale (four ticks) instead of forwards from the left (six ticks) on a normal measurement. Can you please confirm?

I’m with Ken. How are you calculating that your zero error is -0.04?

Please like this question how can I solve it.

A venier measures a distance of 1.17cm and the main scale reads 1.1cm . Draw and discover the venier scale reading

You had helped me a lot … Tomorrow is my practical … Thanks a lot ….

I am a Physics teacher. Inexplicably, some of your answers seem wrong to me. Above, and in two of the practice examples (next page). Eg, above, the zero reading is -0.06, surely, not -0.04. What am I missing?

this comment saved me i was terribly confused on how he arrived at the zero error

Hi ivan, i just wanted to ask that when you will stack up 20 pieces of paper and measure them with either vernier calliper or micrometer screw guage and get the reading and divide it with the number of pieces of paper you have taken measure of, will you read only the main scale or both scales on either both instruments

First look at the main scale and imagine additional lines to the left of zero, i.e. -0.1, -0.2, etc. Then if you read the caliper in the usual way, the Vernier scale zero lies to the right of the -0.1, so that is our “main scale” reading. Next you need to add the measurement from the Vernier scale, which as you mention is 0.06. This results in the “zero reading” in this case of -0.1 + 0.06 = -0.04.

Thank you, I was confused about this!

Always read it on the mainscale as if it would have additional negative lines, and then add the value of the Vernier scale?

With positive zero error the same way? So first main (fe. right to 0,1) and then vernier (fe. 0,06) = +0,16 ?

thank you so much<3

i think you for this

In vernier scal which least count is 0.02mm. Can I measure 20.23mm?

Very informative and well explained in easy words. Thanks…it helped me a lot.

Thanks so much! I needed this for my Physics exam and this really helped! Things were a bit unclear, but re-reading it solved it so it wasn’t that big of a deal

still things re not clear especially that -0.04 how did you get that one?

The vernier reading (0.06) is a measure of the displacement of the vernier zero from the main scale marker to its immediate left, -0.1 . So the actual measurement at this point would be main plus vernier, -0.1 plus 0.06 equal to -0.04 if the error is less than one division to the left. Good luck.

How to know that 0.04 as the error and how you calculated

Extra…. Examples

Thank you for this article..I decided to go and buy a newer type digital caliper as I found matching up the lines of the vernier sliding scale too hard on the eyes..and never felt exactly sure

How did you know the zero error was -0.04?

Since the sliding scale 0 is left of the fixed scale 0 when the jaws are fully closed, you have to count from the right end of the sliding scale to the mark that most closely aligns with a mark on the fixed scale. In the example above, there are 4 marks from the right thus .04 is the correction. This is a negative error and must be subtracted from every reading taken. Subtracting a negative value is equivalent to adding. So, in the example, you would have to add .04 to every reading taken with this instrument.

Thank You So Much!

First time I’m reading this article

Question is why chose a mark that most closely aligns (i.e 4th mark) when there’s one that directly aligns (i.e 6th mark)

@Realone: the 6th mark was indeed used; re-read Russ’ comment above about counting from the right.

i THINK your wrong

When you deduct the vernier scale reading0.9×6=5.4mm from mains calendar reading 1×5=5mm you will get the error _0.4mm error

Best site.????????.

Helped me a lot.

May the other users find this site impressive too.????????

hello

shouldn’t the zero error be – 0.06 cm instead of – 0.04 cm?

Please confirm

I understood thank u a lot. I am a teacher I improve my concept by reading here better that I am gaining.

The zero error mentioned in this page is wrong. that is not 0.04cm it is 0.06cm. please re correct it.

I’ve a vernier scale whose reading on vernier scale is in double figures such as 25, 35… 75 etc. When I go to find out value of vernier scale, I get confused. Suppose my main scale value is 7mm, and my vernier scale shows 75mm, which after multiplying with 0.1 mm (L.C) leaves 7.5mm. Now to get final answer, I got to add 7 + 7.5 = 14.5 which is obviously the wrong answer in light of main scale’s reading. It should have been somewhere above 7 and below 8mm. How to figure this issue our? Should I take vernier’s value as .75mm instead of 75? If so, I left with 7.075 final answer whereas my other device shows 7.75.

Any help?

I learn measurement all gauging

You are not confusing but a confused mind requires no stimulation to get more confused.

But one suggestion is negative and positive symbols cld be shown and similarly the vernier scale should be highlighted and properly the reading should be marked with marker in order easily noticed.

I don’t get how to calculate the zero error and subtract it… is there any simpler way to find the zero out? Also, you didn’t talk about positive and negative zero error.

I don’t know anything about it…..

why did you see it

buy digital vernier caliper

thnq sooooooooooooooioomch realy

WOW

wrong calculation.

will not get odd reading from vernier

What do u mean by odd reading. Cld u please elaborate?

Wow it was enthusiastic

Wow I really understood that’s ???? ????????????????

Thank you…. I found it most easiest explaination among all others but I have a confusion….. How the zero error is-0.04, according to what u taught here it should be – 0.06 as here the 6th smallest division on vernier scale lines up with maine scale division.

Thank u

Wow your explanation is perfect. And thank you very much to helping me understand it.

thanks for making me understand

woww you’ve described a very simple and straight forward method of taking measurement. Thanks

Useful..im very impressed.

Very good explanation. Simple but precise. TQ.

May you describe what positive and negative zero error means

very smat thenks

amazing

my concept is totally clear

Nice

what is the meaning of scale alignment

this means that where there the reading of vernier caliper and main scale collide(join)

Thanks for this post,i finally got it

superb and nice

Thank u so much 4 this post

It really helped me very much before my physics practical exam.

nice and easy well done

nice

Nice website

Well there is no explanation to read scale in mm.

Couldn’t you just convert from cm to mm?

You can convert cm into mm….

1cm= 10 mm

therefore,

0.1/10=0.01cm the least count of vernier callipers

&

0.02/10=0.002cm the least count of micrometer screwguage

0.02 is the least count of vernier caliper.

0.01.is the least count of micro meter.

What did you look for to find the value of the zero error?

Please refer to Measurement of length for information on the procedures to identify the zero error for vernier caliper.

For more practices on finding the zero error, you can refer to this post.

Thanks it is really helpfull i got all my answers

Hey, explanation was very helpful. Except I still fail to understand how to calculate zero error.

If the zero division of M.S is on the left side of zero division of V.S then it is ve zero error and if on the right hand side then -ve error

Thank you so much , today is my exam

Good except a note of the counting backwards (ie the error is 1-0.6) on the zero error would be nice

Great job….thanks

I have an exam today and this article is a life saver!!! Thankss

It really helped.thanks a lot

I still dont understand. I need more explaination,pls

Try playing around with the vernier caliper simulation

thanks explanation was just what i wanted

Why its 0.04 and not 0.4 cm addition or subtraction plz reply as soon as possible

This method is really helpful and comparatively easier. However, i have one concern; if all the readings are in mm the same 0.0x reading will be taken for vernier caliper?

Please reply as soon as possible. 🙂

Sorry, I do not understand your question.

Thank you for the help it’s very much appreciated. You’re a star ??

It was very much confusion but mini physics has cleared my doubts. Thanks a lot

You really confuse me a lot! I was fine after reading this but not after your comment

I will be much grateful if you can forward a video on it to my email

nice explanation..thank you

it is very helpfull for us

It would have been nice if u added a video clip to it

this is really the best explanation anyone could get. thanks

wow,your explaination was cool,for me,it is just what i wanted,thanks

I partially understand

cool..

Nice and very helpful information for assignment. But it would have been great if you have embedded video to describe process of reading vernier caliper.

Regards

A It is good tutorial, but aimed at students in USA only. In some old systems , which are in vogue at some places , an inch is divided in 8 parts and fractions like 1/8, 1/16, 1/32 and so on. how does a vernier work in those system ? A passing remark, I believe, would be desirable.

The basic structure and instructions to read the vernier caliper divided in inches are the same for a vernier caliper divided in cm (as above).

For a vernier caliper whose vernier scale is divided in fractions of an inch ($\frac{1}{8}$, $\frac{1}{16}$, …), the instructions to read the vernier caliper is the same! Consider the image below:

In this image, we are interested in the scale at the top. The reading given by the main scale is 0.75 inches.

The vernier scale is divided into $\frac{1}{128}$ inches. This means that each division is 0.0078125 inches ($\frac{1}{128}$). The reading given by the vernier scale is 1 division on a $\frac{1}{128}$ inches scale, which gives approximately 0.008 inches. Hence, the reading is 0.758 inches.

I would be better, if u teach with the

help of diagram.

Very nice and well defined all the points thankss a lot

Thank you so much this really helped me a lot!!!!!!

It was quite helpful.Thanks.

wel i understand buh dat zero error of a thing is confusing

Good, its easy to understand

thanks, that was a very simple explanation

Very precise and comprehensive material is there on your resource. thanks a lot to work at this level

No any confution about ur work.Thank you very much.

nice

This very helpful. Thanks a lot.

Only one thing i did not understand how did u get the zero error to be + 0.04

i get the concept of positive and negative zero error but how did u read 0.04.

In the diagram, the marking denoting ‘6’ matches with the main scale. The reading is 0.06 cm. However, since the vernier scale is to the left of the main scale, this means that ALL readings are short by 0.1 – 0.06 = 0.04 cm.

You subtract the 0.06 cm because you only need to shift 0.04 cm to the right to get the “perfect” vernier caliper (one with no zero error). Hence, 0.04 cm is the error.

same… i still don’t really get it

veeeeeeeeeeeeeery nice I have no confusion thanks for your website

Thank you so much this really helped me a lot!!!!!!

Hi thank u for these very helpful notes. BTW do you have any alternative to practical tips.

Do you mean tips for Physics practicals?

Yes

Your website and instructions regarding the topic is very good!!!

THANKS!

That was not confusing at all. Thanks for the help, i was actually struggling with zero error and could not find any reference in text books or even other websites. This really cleared all my questions. Thanks again.

No problem. Glad that this post is useful for you. 🙂