The top image depicts the vernier caliper with its jaws tightly closed while the bottom image depicts the vernier caliper with its jaws closed on an object. Find the zero error and the correct reading of the vernier calipers below.
If you encounter any difficulties or have forgotten how to read a vernier caliper, you can visit How to read a vernier caliper.
Show Answer
$$\text{Zero Error }=-0.03 \text{cm}$$
Correct Reading:
$$0.06 \text{cm}-(-0.03 \text{cm}) = 0.09 \text{cm}$$
Show Answer
$$\text{Zero Error }=+0.03 \text{cm}$$
Correct Reading:
$$1.06 \text{cm}-(+0.03 \text{cm}) = 1.03 \text{cm}$$
Show Answer
$$\text{Zero Error }=-0.06 \text{cm}$$
Correct Reading:
$$6.43 \text{cm}-(-0.06 \text{cm}) = 6.49 \text{cm}$$
More Vernier Caliper Practice:
I think the zero error of the last question is not correct
Its actually correct
Yess sister it isn’t
What do you mean? It’s correct.
good
Please I still don’t get how the zero error is gotten when the vernier scale is left to the main scale
You can refer to this post: “How to read a vernier caliper“. The explanation provided in the post is using a situation whereby the vernier scale is left of the main scale.
Alternatively, you can refer to this post: “Parallax error and zero error“.
count from right side to left on the vernier scale in case of negative error
MY DOUBT ALSO IS THIS
When the 0 of the venier caee scale is to the left of the main scale, you count backwards from 10. So the last one would be -0.06.
I really love this platform ..
Self learning is so easy and convenient here.
Thanks a lot to the developer
I don’t really understand the reading of vanier calipers
we dont count the line coinciding with the main scale I think 🙂
how is the second error +0.03 is it not +0.04?
does anyone know how the zero error affects the depth rod of the Vernier caliper ? if it does then how ,if doesn’t then why?
The topic is explained in a simpler and understandable manner. It is really very helpful.
Is it a joke!!!!!!
how this error became 0.03
Dear Hamna…for negative zero error formula will be (10-coinciding div)*LC
So we have -(10-7)*0.01=-0.03 zero error????
we dont count the line coinciding with the main scale I think 🙂
vernier callipers its good for us future engineers but tough to read on my first day at secondary school whoosh it good to be provided online for readers
Thanks! I understand how to read off a vernier caliper already 🙂
great job! it really came in handy
Thanks so much, this really helped!
this is good for people who study GCE O/LEVEL
well this is a very informative site to go on.
its my exam tomorrow and i am having a bit o review from this site and found it greatly helpful i even have bookmarked it for further queries